ai nhanhh mk h

\(1440:\left(41-\left(2x-5\right)\right)=48\)

<=> 41 - 2x + 5 = 1440:48 

<=> 46 - 2x = 30

<=> 16 = 2x

<=> x = 8

Vậy x cần tìm là 8

a) đặt [41-(2x-5)] là a <=> 1440 : a = 48
=> a = 30 <=> [41-(2x-5)] = 30   => 41-(2x-5) =30
<=> -(2x-5) = -11 <=> 2x-5 = 11 <=> 2x = 16 <=> x=2

b) tương tự câu a
gợi ý đáp án : x = 210

Tìm x,y thuộc N,biết:

a,1440:[41-(2x-5)]=2⁴*3

1440:[41-(2x-5)]=48

41-(2x-5)=1440:48

41-(2x-5)=30

2x-5=11

2x=16

x=8

5*[15²-(x-10)]5³=0

5*[15²-(x-10)]=0:5^3

5*[15²-(x-10)]=0

15²-(x-10)=0:5

15²-(x-10)=0

x-10=225-0

x-10=225

x=235

1440:[41-(2x-5)]=2⁴.3

1440 : [41 - (2x - 5 ) ] = 48

41 - (2x - 5 ) = 1440 : 48

41 - ( 2x - 5 ) = 30

2x - 5 = 41 - 30

2x - 5 = 11

2x = 11 + 5

2x = 16

x= 16 : 2

x = 8

a) 1440: [41-{2x-5}]=16.3

    41-(2x-5)=1440-48

   41-(2x-5)=1392

     2x-5=41-1392

     2x-5=-1351

        2x=-1351+5

        2x=-1346

         x=(-1346):2

         x=-673

b) 5.[225-(x-10)]-125=0

      5.[225-(x-10)=0+125

          225-(x-10)=125:5

          225-(x-10)=25

                x-10=225-25

               x-10=200

               x=200+10

             x=210

c) x thuộc {1,2,3,6}

\(1440:\left[41-\left(2x-5\right)\right]=2^4.3\)

\(\Rightarrow1440:\left[41-\left(2x-5\right)\right]=48\)

\(\Rightarrow41-\left(2x-5\right)=30\)

\(\Rightarrow2x-5=11\)

\(\Rightarrow2x=16\)

\(\Rightarrow x=8\)

Vậy \(x=8\)

\(1440:\left[41-\left(2x-5\right)\right]=2^4\cdot3\)

\(1440:\left[41-\left(2x-5\right)\right]=48\)

\(41-\left(2x-5\right)=\frac{1440}{48}=30\)

\(2x-5=41-30=11\)

\(2x=16\)

\(x=8\)

t) \(1440:\left[41-\left(2x-5\right)\right]=2^4.3\)

\(1440:\left[41-\left(2x-5\right)\right]=16.3\)

\(1440:\left[41-\left(2x-5\right)\right]=48\)

\(41-\left(2x-5\right)=1440:48\)

\(41-\left(2x-5\right)=30\)

\(2x-5=41-30\)

\(2x-5=11\)

\(2x\) \(=11+5\)

\(2x\) \(=16\)

\(x=16:2\)

\(x=8\)

Vậy \(x=8\)