\(\left(-27\right)^{27}=\left(-3\right)^{3^{27}}=\left(-3\right)^{81}\)

\(\left(-243\right)^{13}=\left(-3\right)^{5^{13}}=\left(-3\right)^{65}\)

\(\Rightarrow\left(-27\right)^{27}< \left(-243^{13}\right)\)

\(\left(\frac{1}{27}\right)^{10}\&\left(\frac{1}{243}\right)^7\)

\(\left(\frac{1}{27}\right)^{10}=\left(\frac{1}{3^3}\right)^{10}=\frac{1}{3^{30}}\)

\(\left(\frac{1}{243}\right)^7=\left(\frac{1}{3^5}\right)^7=\frac{1}{3^{35}}\)

Vậy \(\left(\frac{1}{27}\right)^{10}>\left(\frac{1}{243}\right)^7\)

Ta có : 

\(\left(\frac{1}{27}\right)^{10}=\left(\frac{1}{3^3}\right)^{10}=\frac{1}{3^{30}}\)

\(\left(\frac{1}{243}\right)^7=\left(\frac{1}{3^5}\right)^7=\frac{1}{3^{35}}\)

Do :     \(\frac{1}{3^{30}}>\frac{1}{3^{35}}\left(3^{30}< 3^{35}\right)\)

\(\Rightarrow\left(\frac{1}{27}\right)^{10}>\left(\frac{1}{243}\right)^7\)

2987.(-1974).(+243).0      Với 0

=-5896338.243.0

=1432810134.0

=0    (ĐPCM)

(-12).(-45):(-27)         Với |-1|

=540:(-27)

=-20 < |-1| 

=> (-12).(-45):(-27) < |-1|

\(243^5=\left(3^5\right)^5=3^{25}\)

\(3.27^8=3.\left(3^3\right)^8=3.3^{24}=3^{25}\)

Vậy\(243^5=3.27^8\)

\(243^5=\left(3^5\right)^5=3^{25}\)

\(3.27^8=3.\left(3^3\right)^8=3.3^{24}=3^{25}\)

Vậy suy ra : \(243^5=3.27^8\)

Như đặc cầu

27^5 = (3^3)^5 = 3^3.5 = 3^15

243^3 = (3^5)^3 = 3^5.3 = 3^15 

Vậy 27^5 = 243^3

Ta có: 243⁵=(3⁵)⁵=3^5.5=3²⁵

3.27⁸=3.(3³)⁸=3.3^3.8=3²⁵

=>3²⁵=3²⁵

Vậy 243⁵=3.27⁸

243⁵ = (3⁵)⁵ = 3²⁵

3 . 27⁸ = 3 . (3³)⁸ = 3²⁵

=> 243⁵ = 3 . 27⁸

ta có 243^5=(3^5)^5=3^25  (1)

        3.27^8=3.(3^3)^8=3.3^24=3^25  (2)

        Từ(1)và(2)=>243^5=3.27^8

27⁵ và 243³

27⁵=(3³)⁵=3¹⁵

243³=(3⁵)³=3¹⁵

=>27⁵=243³

27⁵=(3³)⁵=3¹⁵

243³=(3⁵)³=3¹⁵

Vậy 27⁵=243³

27^5 = (3^3)^5 = 3^3.5 = 3^15

243^3 = (3^5)^3 = 3^5.3 = 3^15 

Vậy 27^5 = 243^3

Có:243⁷=(3⁵)⁷=3³⁵

    9¹⁰x27⁵=(3²)¹⁰x(3³)¹⁰=3²⁰x3³⁰=3⁵⁰

^=>..

Ta có:9¹⁰ = (3²)¹⁰ =3²⁰

            27⁵ = (3³)⁵ =3¹⁵

          243⁷ =(3⁵)⁷=3³⁵

9¹⁰+27⁵=3²⁰+3¹⁵=3³⁵

Mà 3³⁵=3³⁵

Vậy 243⁷=9¹⁰+27⁵

     243^7                                    9^10  x  27^5

= (3^5)^7                                  =  (3^2)^10  x  (3^3)^5

=    3^35                                   =         3^20  x    3^15

                                                 =                3^35

Vi 3^35 = 3^35

=>    243^7  =  9^10 x 27^5

Vay 243^7 = 9^10 x 27^5

27⁵=(3.3.3)⁵=3¹⁵

243³=(3.3.3.3.3)³=3¹⁵

Vậy suy ra 27⁵=243³

27⁵=(3³)⁵=3^3.5=3¹⁵

243³=(3⁵)³=3^5.3=3¹⁵

  Vậy 27⁵=243³