`100:(x+2,5)=2,5`

`=> x+2,5=100:2,5`

`=> x+2,5=40`

`=> x=40-2,5`

`=> x=37,5`

`100:(x+2,5)=2,5`

`x+2,5=100:2,5=40`

`x=40-2,5`

`x=37,5`

\(-2,5\times\left(x+\dfrac{1}{5}\right)=\dfrac{7}{5}\)

\(\Leftrightarrow x+\dfrac{1}{5}=\dfrac{7}{5}:\left(-2,5\right)\)

\(\Leftrightarrow x+\dfrac{1}{5}=\dfrac{7}{5}\times\left(-\dfrac{2}{5}\right)\)

\(\Leftrightarrow x+\dfrac{1}{5}=-\dfrac{14}{25}\)

\(\Leftrightarrow x=-\dfrac{19}{25}\)

\(-2,5\cdot\left(x+\dfrac{1}{5}\right)=\dfrac{7}{5}\)

\(x+\dfrac{1}{5}=\dfrac{7}{5}:\left(-2,5\right)\)

\(x+\dfrac{1}{5}=\dfrac{7}{5}\times\left(-\dfrac{2}{5}\right)\)

\(x+\dfrac{1}{5}=-\dfrac{14}{25}\)

\(x=-\dfrac{14}{25}-\dfrac{1}{5}\)

\(x=-\dfrac{19}{25}\)

x+1/5=7/5:(-5/2)
x= -14/25 -1/5
x= -19/25

\(x.4,7-x.2,5=6,6\)

\(x.\left(4,7-2,5\right)=6,6\)

\(x.2,2=6,6\)

\(x=6,6:2,2\)

\(x=3\)

x.4,7−x.2,5=6,6

.(4,7−2,5)=6,6x.(4,7−2,5)=6,6

.2,2=6,6x.2,2=6,6

X=6,6:2,2x=6,6:2,2

X=3x=3

$x.4,7-x.2,5=6,6$

$x.\left(4,7-2,5\right)=6,6$

$x.2,2=6,6$

$x=6,6:2,2$

$x=3$

Bài 1 : 

Khẳng định b) sai vì |-2,5| > 0

Các khẳng định a) và c) đúng

Bài 2 :

Nếu |x| = y thì x = y hoặc x = -y. theo công thức trên thì :

a) x = \(\frac{1}{5}\) hoặc x = \(-\frac{1}{5}\)

b) x = 0,37 hoặc x = -0,37

c) x = 0

d) x = \(1\frac{2}{3}\) hoặc x = \(-1\frac{2}{3}\)

\(x\times2,5+x\times4=13\)

\(\Leftrightarrow x\times\left(2,5+4\right)=13\)

\(\Leftrightarrow x\times6,5=13\)

\(\Leftrightarrow x=13:6,5\)

\(\Leftrightarrow x=2\)

🐕🐶🐶🐶🐶🐶🐶🐶🐕🐶🐶🐶🐶🐶🐶🐶🐶🐶🐶🐶🐶🐶🐕🐶🐶🐶🐶🐶🐶🐶🐶🐶🐶🐶🐶🐶🐕🐶🐶🐶🐶🐶🐶🐶🐕

\(\left(x+2,5\right):2\frac{1}{2}-1,5=-1\frac{1}{4}\\ \left(x+2,5\right):2,5=-1\frac{1}{4}+1,5\\ x:2,5+1=\frac{-1}{4}\\ x:\frac{5}{2}=\frac{-5}{4}\\ x=\frac{-1}{2}\)

\(3,12.4,1=12,792\)

\(5,03.2,5=12,575\)

\(8,3.4,36=36,188\)

\(1,6.5,05=8,08\)

=> 1,5-x = 0 và 2,5-x = 0

x = 1,5-0 và x = 2,5-0

x = 1,5 và x = 2,5

=> không có x thỏa mãn