4. Tìm x biết :
a) (125 + x) + 68 = 236
b) 2x - 1= 123
TTìm số nguyên x, biết: a) 262 + ( 2x - 123)= 283; b) 63 - ( - 51 + 3x) = 237 c) - ( 2x + 24) + 211 = -123 d) 125 - ( 125 - x) + 22+ 3x) = 237 c) - ( 2x + 24) + 211 = -123 d) 125 - ( 125 - x) + 22
tim x
123+x+2x=2x+345-236
1324+x+x=125-2x-3x
123+x+2x=2x+345-236
<=>x+2x-2x=345-236-123
<=>x=-14
vậy x=-14
1324+x+x=125-2x-3x
<=>x+x-2x-3x=125-1324
<=>-3x=-1199
<=>x=\(\frac{1999}{3}\)
vậy x=\(\frac{1999}{3}\)
k mk nha mấy bạn
\(123+x+2x=2x+345-236\)
\(\Leftrightarrow2x+345-236-2x-x=123\)
\(\Leftrightarrow109-x=123\)
\(\Leftrightarrow x=-14\)
Bài 1 : Tìm x thuộc Z , biết :
a) -x+9+123)=-52+(-123)
b)-(x+30)-5=-25 + 153
c)x-34+125=-(34+75)
d)(420-x)+(-123)= -(-420)+177
e)-x-530=-2x+30
g)-(x+123)-153=-2x+502
CẦN GẤP !!!NHANH TICK !!!!!!
tìm x biết: a) (2x-1)4=16 b) (2x+1)=125
a) \(\left(2x-1\right)^4=16\)
\(\)TH1: \(\left(2x-1\right)^4=2^4\)
\(=>2x-1=2\)
\(2x=2+1\)
\(2x=3\)
\(x=\dfrac{3}{2}\)
TH2: \(\left(2x-1\right)^4=\left(-2\right)^4\)
\(=>2x-1=-2\)
\(2x=-2+1\)
\(2x=-1\)
\(x=\dfrac{-1}{2}\)
Vậy x = \(\dfrac{3}{2}\) hoặc x = \(\dfrac{-1}{2}\)
________--
b) \(\left(2x+1\right)^3=125\) ( mình nghĩ đề bài đúng là vầy )
\(\left(2x+1\right)^3=5^3\)
\(=>2x+1=5\)
\(2x=5-1\)
\(2x=4\)
\(x=4:2\)
\(x=2\)
Vậy x = \(2\)
Giải các phương trình sau:
a) x + 2 x + x − 1 5 3 = 1 − 3 x − 1 − 2 x 3 5 ;
b) 2 x + 1 2 5 − x − 1 2 3 = 7 x 2 − 14 x − 5 15 .
Câu 4 : Tìm x, biết.
a) 2^x.4 = 128 b) (2x + 1)^3 = 125 c) 2x – 2^6 = 6 d) 49.7^x = 2401\(a,2^x.4=128\\2^x.2^2=2^7\\ 2^x=\dfrac{2^7}{2^2}=2^{7-2}=2^5\\ Vậy:x=5\\ ----\\ b,\left(2x+1\right)^3=125=5^3\\ \Rightarrow 2x+1=5\\ 2x=5-1=4\\ x=\dfrac{4}{2}=2\\ ----\\ c,2x-2^6=6\\ 2x=6+2^6=6+64\\ 2x=70\\ x=\dfrac{70}{2}=35\\ ----\\ d,49.7^x=2401\\ 7^x=\dfrac{2401}{49}=49=7^2\\ Vậy:x=2\)
Tìm x biết, X+1/125+x+2/124+x+3/123+x+4/122+x+146/5=0
Bài 1 : Rút gọn biểu thức :
a) 2x + (- 461) - ( 231 - 461 )
b) ( - 83 - x + 45) + 83
c) 211 - (123 - x ) + ( 123 - 211)
d) 25 - ( 125 - x +32) + 22