tim x biet: 1 + 5 + 9 +13 ... + x = 501
tim x biet :1+5+9+13+16+...+x=501501
(x+1)x:2=501.1001. =>(x+1)x=1002.1001=>x=1001
Ta co :
x+1:4+1=501501
x+1:4 = 501501-1
x+1:4 =501500
x+1 = 501500:4
x+1 = 125375
x = 125375 -1
x =125374
Vay x=125735
**** nhe
a,Tim x biet:1+5+9+13+17+...+x=507528
tim x thuoc z
1)26-|x+9|=-13
2)|x+7|-13=25
tim x biet
1)123-3.(x+4)=23
2)720:[41-(2x-5)]=23.5
Tìm x thuoc z:
1) \(26-\left|x+9\right|=-13\)
\(\Leftrightarrow\left|x+9\right|=26-\left(-13\right)\)
\(\Leftrightarrow\left|x+9\right|=39\)
\(\Leftrightarrow\left[{}\begin{matrix}x+9=39\\x+9=-39\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=39-9=30\\x=-39-9=-48\end{matrix}\right.\)
Vậy: \(x\in\left\{30;-48\right\}\)
2) \(\left|x+7\right|-13=25\)
\(\Leftrightarrow\left|x+7\right|=25+13=38\)
\(\Leftrightarrow x+7\in\left\{38;-38\right\}\)
\(\Leftrightarrow x\in\left\{31;-45\right\}\)
Vậy:.................
tim x biet
\(1)123-3.\left(x+4\right)=23\)
\(\Leftrightarrow3\left(x+4\right)=123-23\)
\(\Leftrightarrow3\left(x+4\right)=100\)
\(\Leftrightarrow x+4=\frac{100}{3}\)
\(\Leftrightarrow x=\frac{100}{3}-4=\frac{100-12}{3}=\frac{88}{3}\)
Vậy:................
2) Tương tự
bai 1)tim x biet
a )24-(36+5)=x
b)14-21=(13-x)-(15+8)
bai 2) tim x biet
a)17-x=-25+(-16+9)
b)3x-21=-19-(-2x)
Bài 1: Tìm x, biết
a )24-(36+5)=x b)14-21=(13-x)-(15+8)
24-41=x (13-x)-23=-7
x=-17 13-x=(-7)+23
Vậy x=-17 13-x=16
x=13-16
x=-3 Vậy x=-3
Bài 2:Tìm x, biết
a)17-x=-25+(-16+9) b)3x-21=-19-(-2x)
17-x=-25+(-7) 3x-21=-19+2x
17-x=-32 3x-2x=-19+21
x=17-(-32) x=4
x=49 Vậy x=4
Vậy x=49
Bài 1:
a. 24 - (36+5) = x
=> 24 - 41 = x
=> -17 = x
=> x = -17
b. 14 - 21 = (13 - x) - (15 + 8)
=> -7 = 13 - x - 23
=> -7 - 13 + 23 = -x
=> 3 = -x
=> x = -3
Bài 2:
a. 17 - x = -25 + (-16 + 9)
=> 17 - x = -25 + (-7)
=> 17 - x = -32
=> 17 + 32 = x
=> x = 49
b. 3x - 21 = -19 - (-2x)
=> 3x - 21 = -19 + 2x
=> 3x - 2x = -19 + 21
=> x = 2
Bài1
a)24-(36+5)=x\(\Rightarrow\)x=24-41=-17
b)14-21=(13-x)-(15+8)\(\Rightarrow\)(13-x)-(15+8)=-7\(\Rightarrow\)13-x=-7+23=16\(\Rightarrow\)x=13-16=-3
Bài2
a)17-x=-25+(-16+9)\(\Rightarrow\)17-x=-25+-7\(\Rightarrow\)17-x=-32\(\Rightarrow\)x=17-(-32)=17+32=49
b)3x-21=-19-(-2x)\(\Rightarrow\)3x-(-2x)=-19-21\(\Rightarrow\)3x+2x=-40\(\Rightarrow\)5x=-40\(\Rightarrow\)x=-8
giup minh nha mai minh nop roi ^_^ ^_^
Ta có : 1 = 0 + 1 ; 5 = 2 + 3; 9 = 4 + 5;
13 = 6 +7 ; 17 = 8+ 9; ....
Do đó => x = a + (a+1) (a ∈∈N*)
=> 1 + 5 + 9+ 13 + 17 +....+ x = 4950
= 1 + 2+3+4+5+6+...+ a + (a+1) = 4950
Hay [(a+1)+1]×(a+1)2[(a+1)+1]×(a+1)2 = 4950
=> (a+1)(a+2) = 4950 .2 = 9900
=> (a+1)(a+2) = 99.100
=> a = 98
Do đó : x = a+ (a+1) = 98 + (98 + 1) = 197
Tim x biet a,2:(x-1)=9 b,156-(x+61)=82 c,13+(x-1)=6
a) 2 : (x - 1) = 9
x - 1 = 2 : 9
x - 1 = \(\frac{2}{9}\)
x = \(\frac{2}{9}+1\)
x = \(\frac{11}{9}\)
b) 156 - (x + 61) = 82
x + 61 = 156 - 82
x + 61 = 74
x = 74 - 61
x = 13
c) 13 + (x - 1) = 6
x - 1 = 6 - 13
x - 1 = -7
x = -7 + 1
x = -6
cho A = 1 -2 + 3 - 4 + 5 - 6 + ....... + 19 - 20
a, A co chi het ch2, cho 3, cho 5 khong?
b, tim x biet: 1 + 5 + 9 + 13 + 16 + ..... + x
A = 1 - 2 + 3 - 4 + 5 - 6 + ...... + 19 - 20
= (1 - 2) + (3 - 4) +( 5 - 6) + ...... + (19 - 20)
= -1 + (-1) + (-1) + ...... + (-1)
= -1 x 10
= -10
A=1-2+3-4+5-6+.....+19-20
A=(1-2)+(3-4)+(5-6)+....+(19-20)
A=(-1)+(-1)+(-1)+...+(-1) co 10 so -1
=>A= (-1)×10=-10
Ma -10 chia het cho 2 va 5 nhung khong chia het cho 3
Tim x biet (3x-1)2-9.(x+2)2=13
(3x-1)2-9.(x+2)2=13
<=>(9x2-6x+1)-9.(x2+4x+4)=13
<=>9x2-6x+1-9x2-36x-36=13
<=>-42x-35=13
<=>-42x=13+35
<=>-42x=48
<=>x=-8/7
Tim so nguyen x biet:
a,x-(-24)=3
b,(x+5)-(x-9)=x+3
c,c(x+2)=0
d,(x-1)^2=0
e,x^2-3x=0
f,-13-(6-|x+1|)=24
g,26-|x+9|=-13
i,(3x-6).3=3^4