\(P=\frac{0,75-0,6+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+\frac{11}{7}+\frac{11}{13}}=\frac{3\left(0,25-0,2+\frac{1}{7}+\frac{1}{13}\right)}{11\left(0,25-0,2+\frac{1}{7}+\frac{1}{13}\right)}=\frac{3}{11}\)

P = \(\frac{0,75-0,6+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+\frac{11}{7}+\frac{11}{13}}\)= \(\frac{3\left(0,25-0,2+\frac{1}{7}+\frac{1}{13}\right)}{11\left(0,25-0,2+\frac{1}{7}+\frac{1}{3}\right)}\)=\(\frac{3}{11}\)

Đề có vấn đề

\(P=\frac{0,75-0,6+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+\frac{11}{7}+\frac{11}{13}}\)\(=\frac{\frac{3}{4}-\frac{3}{5}+\frac{3}{7}+\frac{3}{13}}{\frac{11}{4}-\frac{11}{5}+\frac{11}{7}+\frac{11}{13}}\)\(=\frac{3.\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)}{11.\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)}\)\(=\frac{3}{11}\)

\(P=\frac{0,75-0,6+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+\frac{11}{7}+\frac{11}{13}}\)

\(P=\frac{\frac{3}{4}-\frac{3}{5}+\frac{3}{7}+\frac{3}{13}}{\frac{11}{4}-\frac{11}{5}+\frac{11}{7}+\frac{11}{13}}\)

\(P=\frac{3.\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)}{11.\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}-\frac{1}{13}\right)}\)

\(P=\frac{3}{11}\)

\(P=\frac{0,75-0,6+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+\frac{11}{7}+\frac{11}{13}}\)

\(P=\frac{0,15+3\times\left(\frac{1}{7}+\frac{1}{13}\right)}{0,55+11\times\left(\frac{1}{7}+\frac{1}{13}\right)}\)

\(P=\frac{0,05\times3+3\times\left(\frac{1}{7}+\frac{1}{13}\right)}{0,05\times11+11\times\left(\frac{1}{7}+\frac{1}{13}\right)}\)

\(P=\frac{3\times\left(0,05+\frac{1}{7}+\frac{1}{13}\right)}{11\times\left(0,05+\frac{1}{7}+\frac{1}{13}\right)}\)

\(P=\frac{3}{11}\)

\(=\left(\frac{3.\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)}{11.\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)}\right)\)

=\(\frac{3}{11}\)

dung roi

=\(\frac{\frac{3}{4}-\frac{3}{5}+\frac{3}{7}+\frac{3}{13}}{\frac{11}{4}-\frac{11}{5}+\frac{11}{7}+\frac{11}{13}}\)

=\(\frac{3\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)}{4\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)}\)

=\(\frac{3}{4}\)

Ta có: \(A=\frac{0,75-0,6+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+\frac{11}{7}+\frac{11}{3}}=\frac{\frac{3}{4}-\frac{3}{5}+\frac{3}{7}+\frac{3}{13}}{\frac{11}{4}-\frac{11}{5}+\frac{11}{7}+\frac{11}{3}}=\frac{3\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{3}\right)}{11\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{3}\right)}=\frac{3}{11}\)

\(P=\frac{0.75-0.6+\frac{3}{7}+\frac{3}{13}}{2.75-2.2+\frac{11}{7}+\frac{11}{3}}\)

\(P=\frac{\frac{3}{4}-\frac{3}{5}+\frac{3}{7}+\frac{3}{13}}{\frac{11}{4}-\frac{11}{5}+\frac{11}{7}+\frac{11}{13}}\)

\(P=\frac{3\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{15}\right)}{11\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{15}\right)}\)

\(P=\frac{3}{11}\)