Tính nhanh
\(\frac{3,06:7,5+3,4\text{x}0,38}{19-2,6\text{x}0,5}x\frac{\left(1,6-1-0,6\right)x\left(2,29-0,76\right)}{1,6+2,53}\)=
\(\frac{17,8\text{x}3,7-7,8\text{x}4,8+5,7\text{x}17,8-4,2\text{x}7,8}{11,2+12,3=13,4-12,6-11,5-10,4}=\)
Những câu hỏi liên quan
Tính nhanh
a) \(\frac{17,8\text{x}3,7-7,8\text{x}4,8+5,7\text{x}17,8-4,2\text{x}7,8}{11,2+12,3+13,4-12,6-11,5-10,4}\)=
b) \(\frac{3,06:7,5+3,4\text{x}0,38}{19-2,6\text{x}0,5}x\frac{\left(1,6-1-0,6\right)x\left(2,29-0,76\right)}{1,6+2,53}\)=
Tính nhanh
a) \(\frac{3,06:7,5+3,4\text{x}0,38}{19-2,6\text{x}0,5}x\frac{\left(1,6-1-0,6\right)x\left(2,29-0,76\right)}{1,6+2,53}\)=
b) \(\frac{17,8\text{x}3,7-7,8\text{x}4,8+5,7\text{x}17,8-4,2\text{x}7,8}{11,2+12,3+13,4-12,6-11,5-10,4}=\)
Tìm X
x . 4 - x : 4 - 24,7 = 190,48 : 2
Tính nhanh
\(\frac{17,8\text{x}3,7-7,8\text{x}4,8+5,7\text{x}17,8-4,2\text{x}7,8}{11,2=12,3+13,4-12,6-11,5-10,4}\)=
17,8 x 3,7-7,8 x 4,8+5,7 x 17,8 - 4,6 x 7,8 _________________________________
11,2+12,3+13,4-12,6-11,5-10,4
Giúp tui vs🙃🙃🙃
\(\frac{17,8.3,7-7,8.4,8+5,7.17,8-4,6.7,8}{11,2+12,3+13,4-12,6-11,5-10,4}\)
\(=\frac{17,8\left(3,7+5,7\right)-7,8\left(4,8+4,6\right)}{\left(13,4-12,6\right)+\left(12,3-11,5\right)+\left(11,2-10,4\right)}\)
\(=\frac{17,8.9,4-7,8.9,4}{0,8+0,8+0,8}\)
\(=119,1\)
Ai giải giúp mấy bài toán vsBài 1:Asqrt{frac{1}{text{√}2+1}-frac{text{√}8-text{√}10}{2-text{√}5}}Bfrac{5text{√}5}{text{√}5+2}+frac{text{√}5}{text{√}5-1}-frac{3text{√}5}{3+text{√}5}Bài 2 rút gọn biểu thứcAleft(frac{x+sqrt[]{xy}}{text{√}x+text{√}y}-2right):frac{1}{text{√}x+2} với x :y 0Bleft(frac{a}{a-2text{√}a}+frac{a}{text{√}a-2}right):frac{text{√}a+1}{a-4text{√}a+4}Bài 3 cho biểu thứcPleft(frac{x-2}{x+2text{√}x}+frac{1}{text{√}x+2}right)frac{text{√}x+1}{text{√}x-1}a)Rút gọn Pb)tìm x để Ptext{√}...
Đọc tiếp
Ai giải giúp mấy bài toán vs
Bài 1:
A=\(\sqrt{\frac{1}{\text{√}2+1}-\frac{\text{√}8-\text{√}10}{2-\text{√}5}}\)
B=\(\frac{5\text{√}5}{\text{√}5+2}+\frac{\text{√}5}{\text{√}5-1}-\frac{3\text{√}5}{3+\text{√}5}\)
Bài 2 rút gọn biểu thức
A=\(\left(\frac{x+\sqrt[]{xy}}{\text{√}x+\text{√}y}-2\right):\frac{1}{\text{√}x+2}\) với x :y >0
B=\(\left(\frac{a}{a-2\text{√}a}+\frac{a}{\text{√}a-2}\right):\frac{\text{√}a+1}{a-4\text{√}a+4}\)
Bài 3 cho biểu thức
P=\(\left(\frac{x-2}{x+2\text{√}x}+\frac{1}{\text{√}x+2}\right)\frac{\text{√}x+1}{\text{√}x-1}\)
a)Rút gọn P
b)tìm x để P=\(\text{√}x+\frac{5}{2}\)
bài 4 rút gọn biểu thức
A=\(\frac{1}{x+\text{√}x}+\frac{2\text{√}x}{x-1}-\frac{1}{x-\text{√}x}\)
B=\(\left(\frac{x}{x+3\text{√}x}+\frac{1}{\text{√}x+3}\right):\left(1-\frac{2}{\text{√}x}+\frac{6}{x+3\text{√}x}\right)\)
Bài 5
A=\(\left(\frac{2}{\text{√}x-3}-\frac{1}{\text{√}x+3}-\frac{x}{\text{√}x\left(x-9\right)}\right):\text{(√}x+3-\frac{x}{\text{√}x-3}\)
a)rút gọn A
b)tìm gtri x để A= -1/4
AI GIẢI GIÙM MÌNH ĐI MÌNH TẠ ƠN
Tính:1. frac{x^2}{x^2-x}-frac{x^2}{x+1}-frac{2text{x}}{x^2-1}2. frac{4x^2-3x+5}{x^3-1}-frac{1-2text{x}}{x^2+x+1}-frac{6}{x-1}3. frac{5}{2text{x}^2+6text{x}}-frac{4-3text{x}^2}{x^2-9}-34. frac{7}{8x^2-18}+frac{1}{2text{x}^2+3text{x}}-frac{1}{4text{x}-6}5. frac{1}{xleft(x+1right)}+frac{1}{left(x+1right)left(x+2right)}+...+frac{1}{left(x+9right)left(x+10right)}
Đọc tiếp
Tính:
1. \(\frac{x^2}{x^2-x}-\frac{x^2}{x+1}-\frac{2\text{x}}{x^2-1}\)
2. \(\frac{4x^2-3x+5}{x^3-1}-\frac{1-2\text{x}}{x^2+x+1}-\frac{6}{x-1}\)
3. \(\frac{5}{2\text{x}^2+6\text{x}}-\frac{4-3\text{x}^2}{x^2-9}-3\)
4. \(\frac{7}{8x^2-18}+\frac{1}{2\text{x}^2+3\text{x}}-\frac{1}{4\text{x}-6}\)
5. \(\frac{1}{x\left(x+1\right)}+\frac{1}{\left(x+1\right)\left(x+2\right)}+...+\frac{1}{\left(x+9\right)\left(x+10\right)}\)
text{Tìm }x,text{ }text{biết:}1text{)}text{ }2.left(x-frac{1}{3}right)-3left(x-frac{1}{2}right)frac{1}{2}x2text{) }-3left(x-frac{1}{4}right)-frac{1}{3}left(x+frac{1}{2}right)xtext{3) }frac{3}{2}left(x-frac{5}{3}right)-frac{4}{5}x+1text{4) }frac{1}{6}left(2.x-3right)frac{1}{2}left(-x+frac{1}{4}-frac{2}{3}right)text{5) }-frac{2}{3}left(x-frac{1}{4}right)frac{1}{3}left(2.x-1right)
Đọc tiếp
\(\text{Tìm }x,\text{ }\text{biết:}\)
\(1\text{)}\text{ }2.\left(x-\frac{1}{3}\right)-3\left(x-\frac{1}{2}\right)=\frac{1}{2}x\)
\(2\text{) }-3\left(x-\frac{1}{4}\right)-\frac{1}{3}\left(x+\frac{1}{2}\right)=x\)
\(\text{3) }\frac{3}{2}\left(x-\frac{5}{3}\right)-\frac{4}{5}=x+1\)
\(\text{4) }\frac{1}{6}\left(2.x-3\right)=\frac{1}{2}\left(-x+\frac{1}{4}-\frac{2}{3}\right)\)
\(\text{5) }-\frac{2}{3}\left(x-\frac{1}{4}\right)=\frac{1}{3}\left(2.x-1\right)\)
Số các giá trị của x thỏa mãn: \(\frac{\left|x\text{-}5\right|}{\left|x\text{-}3\right|}=\frac{\left|x\text{-}1\right|}{\left|x\text{-}3\right|}\)
1) B=\(\left(\frac{\sqrt{x}}{2}\text{+}\frac{1}{2\sqrt{x}}\right)\left(\frac{\sqrt{x}-1}{\sqrt{x}\text{+}1}-\frac{\sqrt{x}\text{+}1}{\sqrt{x}-1}\right)\)