\(\frac{\frac{2}{3}+\frac{2}{7}-\frac{1}{14}}{-1-\frac{3}{7}+\frac{3}{28}}\)
\(\frac{2}{\frac{3}{\frac{-1}{ }-}}+\frac{2}{\frac{7}{\frac{3}{7}+}}-\frac{1}{\frac{14}{\frac{3}{28}}}\)
-\(\frac{2}{3}\) + \(\frac{14}{21}\) - \(\frac{28}{42}\) = \(\frac{2}{3}\) + \(\frac{14}{21}\) - \(\frac{14}{21}\) = \(\frac{14}{21}\) + \(\frac{14}{21}\) - \(\frac{14}{21}\) = \(\frac{14}{21}\)
\(\frac{\frac{2}{3}+\frac{2}{7}-\frac{1}{14}}{-1-\frac{3}{7}+\frac{3}{28}}\)
\(\frac{\frac{2}{3}+\frac{2}{7}-\frac{1}{14}}{-1-\frac{3}{7}+\frac{3}{28}}\)
\(=\frac{\frac{37}{42}}{\frac{-37}{28}}\)
\(=\frac{37}{42}.\frac{-28}{37}=\frac{-2}{3}\)
Bài làm
\(\frac{\frac{2}{3}+\frac{2}{7}-\frac{1}{14}}{-1-\frac{3}{7}+\frac{3}{28}}=\frac{\frac{28}{42}+\frac{12}{42}-\frac{3}{24}}{-\frac{28}{28}-\frac{12}{28}+\frac{3}{28}}=\frac{\frac{37}{42}}{\frac{-37}{28}}=\frac{37}{42}:-\frac{37}{28}=\frac{37}{42}x\frac{-28}{37}=-\frac{28}{42}=-\frac{14}{21}\)
~ Mình chỉ làm tắt một dòng thôi, bạn thích xuống dòng thì xuống để trình bày cho đẹp nha ~
# Chúc bạn học tốt #
Bài làm
thu gọc câu của mình là -14/21 = -2/3 nha
~ Làm như Lam Ngo Tung đúng rồi đó, mình quên chưa rút gọn ~
# Học tốt #
thực hiện ptính :\(\frac{\frac{2}{3}+\frac{2}{7}-\frac{1}{14}}{-1-\frac{3}{7}+\frac{3}{28}}\)
\(\frac{\frac{2}{3}+\frac{2}{7}-\frac{1}{14}}{-1-\frac{3}{7}+\frac{3}{28}}\)
\(=\frac{\frac{20}{21}-\frac{1}{14}}{\frac{-10}{7}+\frac{3}{28}}\)
\(=\frac{\frac{37}{42}}{\frac{-37}{28}}\)
Thực hiện phép tính: \(\frac{\frac{2}{3}+\frac{2}{7}-\frac{1}{14}}{-1-\frac{3}{7}+\frac{3}{28}}\)
tinh \(\frac{\frac{2}{3}+\frac{2}{7}-\frac{1}{14}}{-1-\frac{3}{7}+\frac{3}{28}}\)
Ai nhanh mik tick
\(\frac{\frac{2}{3}+\frac{2}{7}-\frac{1}{14}}{-1-\frac{3}{7}+\frac{3}{28}}\)
\(=\frac{37}{\frac{42}{-\frac{37}{28}}}\)
\(=-\frac{2}{3}\)
=28/42+12/42-3/42/-28/28-12/28+3/28=40/42-3/42/-40/28+3/28=37/42/-37/42=-2/3
a,\(\frac{\frac{2}{3}+\frac{2}{7}-\frac{1}{14}}{-1-\frac{3}{7}+\frac{3}{28}}\)
b,\(\left(x+\frac{1}{2}\right).\left(\frac{2}{3}-2x\right)=0\)
a) \(\frac{\frac{2}{3}+\frac{2}{7}-\frac{1}{14}}{-1-\frac{3}{7}+\frac{3}{28}}=\frac{\frac{37}{42}}{\frac{-37}{28}}=\frac{37}{42}.\frac{28}{-37}=\frac{-2}{3}\)
b) \(\left(x+\frac{1}{2}\right).\left(\frac{2}{3}-2x\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x+\frac{1}{2}=0\\\frac{2}{3}-2x=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=0-\frac{1}{2}=\frac{-1}{2}\\x=\left(\frac{2}{3}-0\right):2=\frac{1}{3}\end{cases}}\)
Vậy \(x\in\left\{\frac{-1}{2};\frac{1}{3}\right\}\)
a,\(\frac{\frac{2}{3}+\frac{2}{7}-\frac{1}{14}}{-1-\frac{3}{7}+\frac{3}{28}}=\frac{2.\left(\frac{1}{3}+\frac{1}{7}-\frac{1}{28}\right)}{3.\left(-\frac{1}{3}-\frac{3}{7}+\frac{1}{28}\right)}=\frac{-2}{3}\)
cách này k cần dùng máy tính (hok tốt)
b,\(\left(x+\frac{1}{2}\right).\left(\frac{2}{3}-2x\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x+\frac{1}{2}=0\\\frac{2}{3}-2x=0\end{cases}\Rightarrow\orbr{\begin{cases}x=-\frac{1}{2}\\x=\frac{1}{3}\end{cases}}}\)
Vậy....
1) tính giá trị biểu thức:
a)-1\(\frac{5}{7}.15+\frac{2}{7}\left(-15\right)+\left(-105\right)\left(\frac{2}{3}-\frac{4}{5}+\frac{1}{7}\right)\)
b)\(\frac{3}{14}:\frac{1}{28}-\frac{13}{21}:\frac{1}{28}+\frac{49}{42}:\frac{1}{28}-6\)
c)\(4.\left(-\frac{1}{2}\right)^3-2.\left(-\frac{1}{2}\right)^2+3.\left(-\frac{1}{2}\right)+1\)
a) \(\frac{14}{21}+1-|\frac{1}{3}-1|\)
b) \(\frac{1}{3}-|\frac{-1}{4}+\frac{5}{6}|-|\frac{-7}{12}|\)
c) \(|\frac{-5}{6}+\frac{1}{2}|-\frac{1}{3}+|\frac{-5}{12}|\)
d) \(\frac{-10}{6}-\frac{4}{-8}|\frac{-3}{4}+\frac{5}{-2}|\)
e) \(|\frac{-5}{2}|-|\frac{-4}{28}+1|-\frac{-3}{14}\)
g) \(\frac{5}{7}-|\frac{-4}{28}+\frac{1}{2}|-|\frac{-3}{14}|\)
Các bạn giúp mik bài này nhé. Càm ơn nhiều
a) \(\frac{14}{21}+1-\left|\frac{1}{3}-1\right|\)
\(=\frac{2}{3}+1-\frac{2}{3}\)
\(=1+\left(\frac{2}{3}-\frac{1}{3}\right)\)
\(=1\)
b) \(\frac{1}{3}-\left|\frac{-1}{4}+\frac{5}{6}\right|-\left|\frac{-7}{12}\right|\)
\(=\frac{1}{3}-\frac{7}{12}-\frac{7}{12}\)
\(=-\frac{5}{6}\)
\(\frac{1}{3}-|\frac{-1}{4}+\frac{5}{6}|-|\frac{-7}{12}|\)
\(=\frac{2}{3}+1-\frac{2}{3}\)
\(=1+(\frac{2}{3}-\frac{2}{3})\)
\(=1\)
Tính giá trị biểu thức
\(1.A=\frac{1}{5}+\frac{3}{17}-\frac{4}{3}+\left(\frac{4}{5}-\frac{3}{17}+\frac{1}{3}\right)-\frac{1}{7}+\left[\frac{-14}{30}\right]\)
\(2.B=\left(\frac{5}{8}-\frac{4}{12}+\frac{3}{2}\right)-\left(\frac{5}{8}+\frac{9}{13}\right)-\left[\frac{-3}{2}\right]+\frac{7}{-15}\)
\(3.C=\frac{5}{18}+\frac{8}{19}-\frac{7}{21}+\left(\frac{-10}{36}+\frac{11}{19}+\frac{1}{3}\right)-\frac{5}{8}\)
\(4.D=\frac{1}{9}-\left[\frac{-5}{23}\right]-\left(\frac{-5}{23}+\frac{1}{9}+\frac{25}{7}\right)+\frac{50}{14}-\frac{7}{30}\)
\(5.E=\frac{1}{13}+\left(\frac{-5}{18}-\frac{1}{13}+\frac{12}{17}\right)+\left(\frac{12}{17}+\frac{5}{18}+\frac{7}{5}\right)\)
\(6.F=\frac{15}{14}-\left(\frac{17}{23}-\frac{80}{87}+\frac{5}{4}\right)+\left(\frac{12}{17}-\frac{15}{14}+\frac{1}{4}\right)\)
\(7.G=\frac{1}{25}-\frac{4}{27}+\left(\frac{-23}{27}+\frac{-1}{25}-\frac{5}{43}\right)+\frac{5}{43}-\frac{4}{7}\)
\(8.H=\frac{4}{15}-\frac{23}{28}-\left(\frac{-23}{28}+\frac{-11}{15}-\frac{29}{27}\right)-\frac{2}{27}\)
\(9.K=\frac{1}{16}-\frac{5}{21}+\left(\frac{-1}{16}+\frac{-3}{5}-\frac{-5}{21}\right)+\frac{-2}{5}+\frac{3}{4}\)
\(10.L=\frac{7}{12}+\frac{15}{14}-\left(\frac{14}{22}+\frac{-1}{14}+\frac{5}{21}\right)-\frac{-5}{21}+\frac{3}{5}\)
yutyugubhujyikiu