40 nha bạn

40

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(30% + 1) x X = 52

130% x X = 52

X = 52 : 130%

X = 40

e, ta có \(2x=3y\Rightarrow\frac{x}{3}=\frac{y}{2}\Rightarrow\frac{x^2}{9}=\frac{y^2}{4}\)

AĐTCTSBN ta có \(\frac{x^2}{9}=\frac{y^2}{4}=\frac{x^2+y^2}{9+4}=\frac{52}{13}=4\)

\(\Rightarrow\hept{\begin{cases}x=2\cdot3=6\\y=2\cdot2=4\end{cases}}\)

a) Áp dụng tính chất dãy tỉ số bằng nhau, ta có:

\(\frac{x}{7}=\frac{y}{4}=\frac{x-y}{7-4}=\frac{30}{3}=10\)

\(\Rightarrow\hept{\begin{cases}\frac{x}{7}=10\Leftrightarrow x=70\\\frac{y}{4}=10\Leftrightarrow y=40\end{cases}}\)

b,\(\frac{x^2}{9}=\frac{y}{4}\)

=\(\frac{x^2+y}{9+4}\)=\(\frac{100}{13}\)

a) \(75\%\times x+\frac{3}{4}\times x+x=30\)

\(\frac{3}{4}\times x+\frac{3}{4}\times x+x=30\)

\(x\times\left(\frac{3}{4}+\frac{3}{4}+1\right)=30\)

\(x\times\frac{5}{2}=30\)

\(x=30\div\frac{5}{2}\)

\(x=30\times\frac{2}{5}\)

\(x=12\)

b) \(x-40\%=36\)

\(x-\frac{2}{5}=36\)

\(x=36+\frac{2}{5}\)

\(x=36\frac{2}{5}\)

c) \(30\%\times x+x=52\)

\(\frac{3}{10}\times x+x=52\)

\(x\times\left(\frac{3}{10}+1\right)=52\)

\(x\times\frac{13}{10}=52\)

\(x=52\div\frac{13}{10}\)

\(x=40\)

a,  10 x + 2 2 . 5 = 10 2

10x = 100–20

10x = 80

x = 8

b,  5 2 + 15 - x = 30

15–x = 5

x = 10

c,  2 2 . 5 2 - 25 + x = 40

100–(25+x) = 40

25+x = 60

x = 35

d,  7 2 x - 6 2 x = 13 . 2 3 - 26

49x–36x = 104–26

13x = 78

x = 6

(7 - x) + (10 -x) + (13 - x) + ... + (52 - x) + (55 - x) = 493 
<=>7+10+13+...+55-17x=493 
<=>(55+7).17:2 - 17x=493 
<=>527-17x=493 
<=>x=2

x = 23                                         

x + 3 + x + 5 + x + 7 - x - 9 = 52

2x + 6 = 52

2x = 46

x = 23

D

D. 52

D