\(\left(x+\frac{2}{3}\right)\left(\frac{5}{4}-2x\right)>0\)

th1 : 

\(\hept{\begin{cases}x+\frac{2}{3}>0\\\frac{5}{4}-2x>0\end{cases}\Rightarrow\hept{\begin{cases}x>-\frac{2}{3}\\-2x>-\frac{5}{4}\end{cases}\Rightarrow}\hept{\begin{cases}x>-\frac{2}{3}\\x>\frac{5}{8}\end{cases}\Rightarrow}x>\frac{5}{8}}\)

th2 : 

\(\hept{\begin{cases}x+\frac{2}{3}< 0\\\frac{5}{4}-2x< 0\end{cases}\Rightarrow\hept{\begin{cases}x< -\frac{2}{3}\\-2x< -\frac{5}{4}\end{cases}\Rightarrow}\hept{\begin{cases}x< -\frac{2}{3}\\x< \frac{5}{8}\end{cases}\Rightarrow}x< -\frac{2}{3}}\)

vậy_

720 : [41 - (2x - 5)] = 8 . 5

=> 720 : [41 - (2x - 5)] = 40

=> 41 - (2x - 5) = 720 : 40

=> 41 - (2x - 5) = 18

=> 2x - 5 = 41 - 18

=> 2x - 5 = 23

=> 2x = 23 + 5

=> 2x = 28

=> x = 28 : 2

=> x = 14

Vậy x = 14

1 + 2 + 3 + 4 + ... + (x - 1) + x = 78

            có x số hạng

=> (x + 1) . x : 2 = 78

=> (x + 1) . x = 78 . 2

=> (x + 1) . x = 156

=> (x + 1) . x = 13 . 12

=> x = 12

Vậy x = 12

90/17

1111111111111111111111111111111111111111111111111111111111111111111111111111111

\(\frac{4x+720}{70\times x}=\frac{1}{2}\Rightarrow2\left(4x+720\right)=70x\)

<=>8x+1440=70x

 =>8x-70x=0-1440

=>-62x=-1440

=>x=\(\frac{720}{31}\)

Giải:

a) \(70.\dfrac{4x+720}{x}=\dfrac{1}{2}\)

\(\Leftrightarrow\dfrac{280x+50400}{x}=\dfrac{1}{2}\)

\(\Leftrightarrow2\left(280x+50400\right)=x\)

\(\Leftrightarrow560x+100800=x\)

\(\Leftrightarrow560x-x=-100800\)

\(\Leftrightarrow549x=-100800\)

\(\Leftrightarrow x=-\dfrac{11200}{61}\)

Vậy ...

b) \(x^2+5x< 0\)

\(\Leftrightarrow x\left(x+5\right)< 0\)

\(\Leftrightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x< 0\\x+5>0\end{matrix}\right.\\\left\{{}\begin{matrix}x>0\\x+5< 0\end{matrix}\right.\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x< 0\\x>-5\end{matrix}\right.\\\left\{{}\begin{matrix}x>0\\x< -5\end{matrix}\right.\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}0>x>-5\\x\in\varnothing\end{matrix}\right.\)

Vậy ...

a, 128 – 3(x+4) = 23

b,  12 x - 4 3 . 8 3 = 4 . 8 4

c, [(4x+28).3+55]:5 = 35

d, 720:[41 – (2x – 5)] =  2 3 . 5

x=20

\(70:\dfrac{4x+720}{x}=\dfrac{1}{2}\)

\(\Rightarrow\dfrac{4x+720}{x}=70:\dfrac{1}{2}=140\)

\(\Rightarrow4x+720=140.x\)

\(\Rightarrow720=36.x\)

\(\Rightarrow720:36=x\)

\(\Rightarrow x=20\)

Đk : x khác 0 

=> 35/2x + 720/x = 1/2

=> 35+1440/2x = 1/2

=> 1475/2x = 1/2

=> 1475 = 1/2 . 2x = x

Vậy x = 1475

k mk nha

X=1475