\(\frac{42}{25}:\frac{x}{5}=\frac{6}{5}\)
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\(\frac{42}{25}:\frac{x}{5}=\frac{6}{5}\).tìm x
a.\(\frac{11}{14}-\frac{3}{x-1}=\frac{5}{14}\)
b.\(\frac{42}{25}:\frac{2x+1}{5}=\frac{6}{5}\)
a.\(\frac{11}{14}-\frac{3}{x-1}=\frac{5}{14}\)
\(\frac{3}{x-1}=\frac{11}{14}-\frac{5}{14}\)
\(\frac{3}{x-1}=\frac{3}{7}\)
\(\Rightarrow x-1=7\)
\(x=7+1\)
Vậy \(x=8\)
b.\(\frac{42}{25}:\frac{2x+1}{5}=\frac{6}{5}\)
\(\frac{2x+1}{5}=\frac{42}{25}:\frac{6}{5}\)
\(\frac{2x+1}{5}=\frac{7}{5}\)
\(\Rightarrow2x+1=7\)
\(2x=7-1\)
\(2x=6\)
\(x=6:2\)
\(x=3\)
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a.\(\frac{11}{14}-\frac{3}{x-1}=\frac{5}{14}\)
\(\frac{3}{x-1}=\frac{11}{14}-\frac{5}{14}=\frac{3}{7}\)
\(\Rightarrow x-1=7\)
\(x=7+1=8\)
VẬY, \(x=8\)
b. \(\frac{42}{25}:\frac{2x+1}{5}=\frac{6}{5}\)
\(\frac{2x+1}{5}=\frac{42}{25}:\frac{6}{5}=\frac{7}{5}\)
\(\Rightarrow2x+1=7\)
\(2x=7-1=6\)
\(x=6:2=3\)
VẬY, \(x=3\)
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a ) \(\frac{11}{14}-\frac{3}{x-1}=\frac{5}{14}\)
\(\frac{3}{x-1}=\frac{11}{14}-\frac{5}{4}\)
\(\frac{3}{x-1}=\frac{6}{14}=\frac{3}{7}\)
\(=>x-1=7=>x=7+1=8\)
b ) \(\frac{42}{25}\div\frac{2x+1}{5}=\frac{6}{5}\)
\(\frac{2x+1}{5}=\frac{42}{25}\div\frac{6}{5}\)
\(\frac{2x+1}{5}=\frac{210}{150}=\frac{7}{5}\)
\(2x=7-1=6=>x=6\div2=3\)
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\(\frac{5}{6}-\left(\frac{-1}{12}\right)+\frac{2}{3}-\left(\frac{-2}{7}\right)+\frac{1}{25}-\left(\frac{-1}{4}\right)-\frac{5}{42}\)\(\frac{5}{42}\)
i)\(\frac{25^9}{5^{16}}-5^3\div5\)
k)\(\frac{5}{7}-\left|\frac{2}{-7}\right|\)
l)\(\frac{3^6\times3^4}{9^3}\)
m)\(\frac{19}{42}+2019+1\frac{5}{27}+\frac{23}{42}-\frac{5}{27}\)
i) \(\frac{25^9}{5^{16}}-5^3:5\)
\(=\frac{\left(5^2\right)^9}{5^{16}}-5^2\)
\(=\frac{5^{18}}{5^{16}}-25\)
\(=5^2-25\)
\(=25-25\)
\(=0.\)
k) \(\frac{5}{7}-\left|\frac{2}{-7}\right|\)
\(=\frac{5}{7}-\left|\frac{-2}{7}\right|\)
\(=\frac{5}{7}-\frac{2}{7}\)
\(=\frac{3}{7}.\)
l) \(\frac{3^6.3^4}{9^3}\)
\(=\frac{3^{6+4}}{\left(3^2\right)^3}\)
\(=\frac{3^{10}}{3^6}\)
\(=3^4.\)
\(=81.\)
Chúc bạn học tốt!
\(\frac{24}{x}\)\(\div\)\(\frac{8}{3}\)=\(\frac{3}{5}\)
b\(\frac{42}{25}\)\(\div\)\(\frac{x}{5}\)=\(\frac{6}{5}\)
a) \(\frac{24}{x}\div\frac{8}{3}=\frac{3}{5}\)
\(\frac{24}{x}\cdot\frac{3}{8}=\frac{3}{5}\)
\(\frac{24}{x}=\frac{3}{5}\div\frac{3}{8}\)
\(\frac{24}{x}=\frac{24}{15}\)
Vậy x = 15
b) Tương tự
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\(\frac{24}{x}:\frac{8}{3}=\frac{3}{5}\)
\(\frac{24}{x}=\frac{3}{5}.\frac{8}{3}\)
\(\frac{24}{x}=\frac{8}{5}\)
\(\frac{24}{x}=\frac{24}{15}\)
\(=>x=15\)
vay \(x=15\)
b) \(\frac{42}{25}:\frac{x}{5}=\frac{6}{5}\)
\(\frac{x}{5}=\frac{42}{25}:\frac{6}{5}\)
\(\frac{x}{5}=\frac{42}{25}.\frac{5}{6}\)
\(\frac{x}{5}=\frac{7}{5}\)
\(=>x=7\)
vay \(x=7\)
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Xem thêm câu trả lời
Bài 1:Tìm x,biết
a) x-frac{20}{11.13}-frac{20}{13.15}-frac{20}{15.17}-...-frac{20}{53.55}frac{3}{11}
b)x+frac{15}{90.94}+frac{15}{94.98}+frac{15}{98.102}+...+frac{15}{146.150}frac{2}{3}
c)x-frac{1}{2}-frac{1}{6}-frac{1}{12}-frac{1}{20}-frac{1}{30}-frac{1}{42}-frac{1}{56}frac{5}{24}
d)8-frac{8-frac{8}{5}+frac{8}{25}-frac{8}{125}}{9-frac{9}{5}+frac{9}{25}-frac{9}{125}}:frac{161616}{151515}frac{4+frac{4}{73}-frac{4}{115}}{5+frac{5}{73}-frac{1}{23}}
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Bài 1:Tìm x,biết
a) \(x-\frac{20}{11.13}-\frac{20}{13.15}-\frac{20}{15.17}-...-\frac{20}{53.55}=\frac{3}{11}\)
b)\(x+\frac{15}{90.94}+\frac{15}{94.98}+\frac{15}{98.102}+...+\frac{15}{146.150}=\frac{2}{3}\)
c)\(x-\frac{1}{2}-\frac{1}{6}-\frac{1}{12}-\frac{1}{20}-\frac{1}{30}-\frac{1}{42}-\frac{1}{56}=\frac{5}{24}\)
d)\(8-\frac{8-\frac{8}{5}+\frac{8}{25}-\frac{8}{125}}{9-\frac{9}{5}+\frac{9}{25}-\frac{9}{125}}:\frac{161616}{151515}=\frac{4+\frac{4}{73}-\frac{4}{115}}{5+\frac{5}{73}-\frac{1}{23}}\)
a, Câu hỏi của Nguyễn Ánh Ngân - Toán lớp 6 - Học toán với OnlineMath
b, Câu hỏi của Vũ Xuân Hiếu - Toán lớp 6 | Học trực tuyến
c)
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TÌM X BIẾT
a) \(\frac{12+x}{42}=\frac{5}{6}\)
b) \(\frac{25-x}{40}=\frac{3}{8}\)
a) 42 x 5 : 6 - 12 = 23
b) 25- 40 x 3 : 8 = 10
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Xem thêm câu trả lời
A=\(1-\frac{5}{6}+\frac{7}{12}-\frac{9}{20}+\frac{11}{30}-\frac{13}{42}+\frac{15}{56}-\frac{17}{72}+\frac{19}{90}-\frac{21}{110}+\frac{23}{132}-\frac{25}{156}\)\(\frac{25}{156}\)
Giups mình nha !!!
Đè thừa một số \(\frac{25}{156}\),mk ko lại đề bài nhé
\(A=1-\frac{2+3}{2\cdot3}+.....+\frac{11+12}{11\cdot12}-\frac{12+13}{12\cdot13}\)
\(=1-\frac{1}{2}-\frac{1}{3}+\frac{1}{3}+\frac{1}{4}-...+\frac{1}{11}+\frac{1}{12}-\frac{1}{12}-\frac{1}{13}\)
\(=\frac{1}{2}-\frac{1}{13}=\frac{11}{26}\)
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tính giá trị:
A=\(\frac{5}{6}-\frac{-1}{12}+\frac{2}{3}-\frac{-2}{7}+\frac{1}{25}-\frac{-1}{4}-\frac{5}{42}\)
B=\(\frac{7.6^{10}.2^{20}.3^6-2^{19}.6^{15}}{9.6^{19}.2^9-4.3^{17}2^{26}}\)