Bài 1) Rút gọn biểu thức
a) \(\frac{2^7.9^3}{6^5.8^2}\)
b) \(\frac{6^3+3.6^2+3^3}{-13}\)
c) \(\frac{5^4.20^4}{25^5.4^5}\)
d)(\(\frac{5^4-5^3}{125^4}\) )
Rút gọn biểu thức
a) \(\frac{2^7.9^3}{6^5.8^2}\) b) \(\frac{6^3+3.6^2+3^3}{-13}\) c) \(\frac{5^4.20^4}{25^5.4^5}\)
3 tick nha mn
\(a,=\frac{2^7\cdot\left(3^2\right)^3}{2^5\cdot3^5\cdot2^3}=\frac{2^7\cdot3^6}{2^8\cdot3^5}=\frac{3}{2}\)
câu a)
\(=\frac{2^7\times\left(3^2\right)^3}{2^5\times3^5\times2^3}=\frac{2^7\times3^6}{2^8\times3^5}=\frac{3}{2}\)
Bài làm
a) \(\frac{2^7.9^3}{6^5.8^2}=\frac{2^7.\left(3^2\right)^3}{\left(2.3\right)^5.\left(2^3\right)^2}=\frac{2^7.3^5}{2^5.3^5.2^5}=\frac{1.1}{1.1.2^3}=\frac{1}{2^3}=\frac{1}{8}\)
b) \(\frac{6^3+3.6^2+3^3}{-13}=\frac{6^2.6+3.6^2+3^3}{-13}=\frac{6^2.\left(6+3+3^3\right)}{-13}=\frac{36.36}{-13}\approx-99,7\)
c) \(\frac{5^4.20^4}{25^5.4^5}=\frac{5^4.\left(4.5\right)^4}{\left(5^2\right)^5.4^5}=\frac{5^4.4^4.5^4}{5^7.4^7}=\frac{5.1.1}{1.4^3}=\frac{5}{64}\approx0,08\)
# Chúc bạn học tốt #
Tính:
a) \(\frac{4^2.4^3}{2^{10}}\)
b) \(\frac{\left(0,6\right)^5}{\left(0,2\right)^5}\)
c) \(\frac{2^7.9^3}{6^5.8^2}\)
d) \(\frac{6^3+3.6^2+3^3}{-13}\)
e) \(\frac{5^4.20^4}{25^5.4^5}\)
HELP ME!
a.ta có :4^2.4^3/2^10=2^4.2^6/2^10=2^10/2^10=1
b. ta co :(0,6)^5/(0,2)^5=(0,6/0,2)^5=3^5=243
a) \(\frac{4^2.4^3}{2^{10}}=\frac{4^5}{2^{10}}=\frac{2^{10}}{2^{10}}=1\)
b) \(\frac{\left(0,6\right)^5}{\left(0,2\right)^5}=\left(\frac{0,6}{0,2}\right)^5=3^5=243\)
c) \(\frac{2^7.9^3}{6^5.8^2}=\frac{2^7.3^6}{2^5.3^5.2^6}=\frac{2^7.3^6}{2^{11}.3^5}=\frac{3}{2^4}=\frac{3}{16}\)
d) \(\frac{6^3+3.6^2+3^3}{-13}=\frac{2^3.3^3+3^3.2^2+3^3}{-13}=\frac{3^3\left(2^3+2^2+1\right)}{-13}=\frac{27.13}{-13}=-27\)
e) \(\frac{5^4.20^4}{25^5.4^5}=\frac{5^4.2^8.5^4}{5^{10}.2^{10}}=\frac{2^8.5^8}{5^{10}.2^{10}}=\frac{\left(2.5\right)^8}{\left(5.2\right)^{10}}=\frac{10^8}{10^{10}}=\frac{1}{10^2}=\frac{1}{100}\)
Tính:
a) \(\frac{4^2.4^3}{2^{10}}\)
b) \(\frac{\left(0,6\right)^5}{\left(0,2\right)^5}\)
c) \(\frac{2^7.9^3}{6^5.8^2}\)
d) \(\frac{6^3+3.6^2+3^3}{-13}\)
e) \(\frac{5^4.20^4}{25^5.4^5}\)
B1:Tính
a)(-2/3+3/7):4/5+(-1/3+4/7):4/5
b)5/9:(1/11-5/22)+5/9:(1/15-2/3)
c)4^2.4^3/4^10
d)(0,6)^5/(0,2)^6
e)2^7.9^3/6^5.8^2
g)6^3+3.6^2+3^3/-13
h)(3/7+1/2)^2
i)(3/4-5/6)^2
k)5^4.20^44/25^5.4^5
l)(-10/3)^5.(-6/5)^4
f)(1+2/3-1/4).(4/5-3/4)^2
m)2:(1/2-2/3)^3
n)9.9.(-1/3)^3+1/3
y)(4.2^5):(2^3.1/16)
a) \(\left(-\dfrac{2}{3}+\dfrac{3}{7}\right):\dfrac{4}{5}+\left(-\dfrac{1}{3}+\dfrac{4}{7}\right):\dfrac{4}{5}\)
\(=\left(-\dfrac{5}{21}\right):\dfrac{4}{5}+\left(\dfrac{5}{21}\right):\dfrac{4}{5}\)
\(=\left(-\dfrac{5}{21}+\dfrac{5}{21}\right):\dfrac{4}{5}\)
\(=0:\dfrac{4}{5}\)
\(=0\)
b) \(\dfrac{5}{9}:\left(\dfrac{1}{11}-\dfrac{5}{22}\right)+\dfrac{5}{9}:\left(\dfrac{1}{15}-\dfrac{2}{3}\right)\)
\(=\dfrac{5}{9}:\left(-\dfrac{3}{22}\right)+\dfrac{5}{9}:\left(-\dfrac{3}{5}\right)\)
\(=\dfrac{5}{9}:\left[\left(-\dfrac{3}{22}\right)+\left(-\dfrac{3}{5}\right)\right]\)
\(=\dfrac{5}{9}:\left(-\dfrac{81}{110}\right)\)
\(=-\dfrac{550}{729}\)
c) \(4^2.4^3:4^{10}\)
\(=\dfrac{4^5}{4^{10}}\)
\(=\dfrac{1}{4^5}\)
\(=\dfrac{1}{256}\)
d) \(\left(0,6\right)^5:\left(0,2\right)^6\)
\(=\dfrac{\left(0,2\cdot3\right)^5}{\left(0,2\right)^6}\)
\(=\dfrac{\left(0,2\right)^5\cdot3^5}{\left(0,2\right)^6}\)
\(=\dfrac{243}{0,2}\)
\(=1215\)
Mai mốt bạn đăng một lần ít thôi nha tại giờ khuya quá nên mình chỉ làm đến đây thôi =))
Rút gọn biểu thức:
a) 2^7 . 9^3/ 6^5.8^2
b) 6^3 + 3.6^2 +3^3 / -13
c) 5^4 . 20^4/ 25^4 . 4^5
d) (5^4.5^3)^3/125^4
e) Căn ( 2,5 - 0,7)^2
f) Căn 3^2 + căn 39^2/ căn 7^2 + căn 91^2
a) \(\frac{2^7\cdot9^3}{6^5\cdot8^2}=\frac{2^7\cdot\left(3^2\right)^3}{\left(2\cdot3\right)^5\cdot\left(2^3\right)^2}=\frac{2^7\cdot3^6}{2^5\cdot3^5\cdot2^6}=\frac{3}{2^4}=\frac{3}{16}\)
c) \(\frac{5^4\cdot20^4}{25^4\cdot4^5}=\frac{5^4\cdot\left(2^2\cdot5\right)^4}{\left(5^2\right)^4\cdot\left(2^2\right)^5}=\frac{5^4\cdot2^8\cdot5^4}{5^8\cdot2^{10}}=\frac{1}{2^2}=\frac{1}{4}\)
d) \(\frac{\left(5^4\cdot20^4\right)^3}{125^4}=\frac{5^{12}\cdot20^{12}}{\left(5^3\right)^4}=\frac{5^{12}\cdot\left(2^2\cdot5\right)^{12}}{5^{12}}=2^{24}\cdot5^{12}\)
Bài 1: Rút gọn biểu thức:
a, \(\frac{2^7.9^3}{6^5.8^2}\)
Bài 2: Thực hiện phép tính:
a, \(\frac{1}{2}-\frac{1}{3}+\frac{1}{12}\)
b, \(\frac{9^9.27^4}{3^8.81^5}\)
BÀI 1
\(\frac{2^7.9^3}{6^5.8^2}=\frac{2^7.\left(3^2\right)^3}{\left(2.3\right)^5.\left(2^3\right)^2}=\frac{2^7.3^6}{2^5.3^5.2^6}=\frac{3}{2^4}=\frac{3}{16}.\)
bài 2
a) \(\frac{1}{2}-\frac{1}{3}+\frac{1}{12}=\frac{6}{12}-\frac{4}{12}+\frac{1}{12}=\frac{3}{12}=\frac{1}{4}\)
b) \(\frac{9^9.27^4}{3^8.81^5}=\frac{\left(3^2\right)^9.\left(3^3\right)^4}{3^8.\left(3^4\right)^5}=\frac{3^{18}.3^{12}}{3^8.3^{20}}=\frac{3^{30}}{3^{28}}=3^2=9\)
Study well
Bài 1: \(\frac{2^7.9^3}{6^5.8^2}=\frac{2^7.3^6}{2^5.3^5.2^6}=\frac{3}{2^4}=\frac{3}{16}\)
Bài 2:
a)\(\frac{1}{2}-\frac{1}{3}+\frac{1}{12}=\frac{6}{12}-\frac{4}{12}+\frac{1}{12}=\frac{6-4+1}{12}=\frac{1}{4}\)
b)\(\frac{9^9.27^4}{3^8.81^5}=\frac{9^9.3^{12}}{3^8.9^{10}}=\frac{3^4}{9}=\frac{3^4}{3^2}=3^2=9\)
Tìm giá trị của các biểu thức sau :
a)\(\frac{4^2.4^3}{2^{10}}\); b)\(\frac{\left(0,6\right)^5}{\left(0,2\right)^6}\)
c)\(\frac{2^7.9^3}{6^5.8^2}\); d)\(\frac{6^3+3.6^2+3^3}{-13}\)
a) \(\frac{4^2.4^3}{2^{10}}=\frac{\left(2^2\right)^2.\left(2^2\right)^3}{2^{10}}=\frac{2^4.2^6}{2^{10}}=\frac{2^{10}}{2^{10}}=1\)
b) \(\frac{\left(0,6\right)^5}{\left(0,2\right)^6}=\frac{\left(0,2.3\right)^5}{\left(0,2\right)^6}=\frac{3^5.0,2^5}{0,2^6}=\frac{3^5}{0,2}=\frac{243}{0,2}=1215\)
c) \(\frac{2^7.9^3}{6^5.8^2}=\frac{2^7.\left(3^2\right)^3}{2^5.3^5.\left(2^3\right)^2}=\frac{2^7.3^6}{2^5.3^5.2^6}=\frac{2^7.3}{2^{11}}=\frac{3}{2^4}=\frac{3}{16}\)
d) \(\frac{6^3+3.6^2+3^3}{-13}=\frac{6^2\left(6+3\right)+3^3}{-13}=\frac{6^2.9+3^2}{-13}=\frac{3^2\left(6^2+1\right)}{-13}=\frac{9.37}{-13}=\frac{333}{-13}\)
Tìm giá trị của các biểu thức sau :
a) \(\frac{4^2.4^3}{2^{10}}\)
b) \(\frac{\left(0,6\right)^5}{\left(0,2\right)^6}\)
c) \(\frac{2^7.9^3}{6^5.8^2}\)
d) \(\frac{6^3+3.6^2+3^3}{-13}\)
a,\(\frac{4^2.4^3}{2^{10}}=\frac{4^5}{2^{10}}=\frac{4^5}{4^5}=1\)
\(\frac{\left(0.6\right)^5}{\left(0.2\right)^6}=1215\)
còn lại làm đc mà
Tìm giá trị của các biểu thức sau :
a)\(\frac{4^2.4^3}{2^{10}}\)
b) \(\frac{(0,6)^5}{(0,2)^6}\)
c)\(\frac{2^7.9^3}{6^5.8^2}\)
d)\(\frac{6^3+3.6^2+3^3}{-13}\)
Giúp Min đi mà T_T
\(\frac{4^2.4^3}{2^{10}}=\frac{\left(2^2\right)^2.\left(2^2\right)^3}{2^{10}}=\frac{2^4.2^6}{2^{10}}=\frac{2^{10}}{2^{10}}=1\)
a, \(\frac{4^2.4^3}{2^{10}}=\frac{\left(2^2\right)^2.\left(2^2\right)^3}{2^{10}}=\frac{2^4.2^6}{2^{10}}=\frac{2^{4+6}}{2^{10}}=\frac{2^{10}}{2^{10}}=1\)
b,\(\frac{\left(0,6\right)^5}{\left(0,2\right)^6}=\frac{\left(0,2.3\right)^5}{\left(0,2\right)^6}=\frac{\left(0,2\right)^5.3^5}{\left(0,2\right)^6}=\frac{3^5}{0,2}\)
c, \(\frac{2^7.9^3}{6^5.8^2}=\frac{2^7.\left(3^2\right)^3}{\left(2.3\right)^5.\left(2^3\right)^2}=\frac{2^7.3^6}{2^5.3^5.2^6}=\frac{2^7.3^6}{3^5.2^{11}}=\frac{3}{2^4}\)
d, \(\frac{6^3+3.6^2+3^3}{-13}=\frac{\left(2.3\right)^3+3\left(2.3\right)^2+3^3}{-13}=\frac{2^3.3^3+3.2^2.3^2+3^3}{-13}\)
\(=\frac{2^3.3^3+3^3.2^2+3^3}{-13}=\frac{3^9\left(2^3+2^2+1\right)}{-13}=\frac{3^3.13}{-13}=3^3=27\)
a) \(\frac{4^2.4^3}{2^{10}}=\frac{4^{2+3}}{2^{10}}=\frac{\left(2^2\right)^5}{2^{10}}=\frac{2^{10}}{2^{10}}=1\) b) \(\frac{\left(0,6\right)^5}{\left(0,2\right)^6}=\frac{\left(3.0,2\right)^5}{\left(0,2\right)^6}=\frac{3^5.0,2^5}{\left(0,2\right)^6}=\frac{3^5}{0,2}=1215\)
c) \(\frac{2^7.9^3}{6^5.8^2}=\frac{2^7.\left(3^2\right)^3}{\left(2.3\right)^5.\left(2^3\right)^2}=\frac{2^7.3^6}{2^5.3^5.2^6}=\frac{3}{2^4}=\frac{3}{16}\) d)\(\frac{6^3+3.6^2+3^3}{-13}=\frac{\left(2.3\right)^3+3.\left(2.3\right)^2+3^3}{-13}=\frac{2^3.3^3+3.2^2.3^2+3^2}{-13}=\frac{3^3.\left(2^3+2^2+1\right)}{-13}=\frac{3^3.13}{-13}=-3^3\)