a) \(\left(\frac{3}{7}\right)^{21}:\left(\frac{3}{7}^3\right)^6\)

\(=\left(\frac{3}{7}\right)^{21}:\left(\frac{3}{7}\right)^{18}\)

\(=\left(\frac{3}{7}\right)^{21-18}\)

\(=\left(\frac{3}{7}\right)^3\)

\(=\frac{27}{343}\)

biết rồi bạn đăng lên làm gì

khắc ngọc nam mk có biết đâu

\(\left(\frac{3}{7}\right)^{21}\div\left(\frac{9}{49}\right)^6=\left(\frac{3}{7}\right)^{21}\div\left[\left(\frac{3}{7}\right)^2\right]^6=\left(\frac{3}{7}\right)^{21}\div\left(\frac{3}{7}\right)^{12}=\left(\frac{3}{7}\right)^9\)

Bn chỉnh lại đề đi sao lại tiếng anh hả vào toán đi ko được tick đâu

(\(\frac{3}{7}\))²¹ : (\(\frac{9}{49}\))⁶       

  ^{=(\(\frac{3}{7}\))21 : [(\(\frac{3}{7}\))2]6}

   ^{= ( \(\frac{3}{7}\)})^{21 : (\(\frac{3}{7}\))12} 

   ^{= ( \(\frac{3}{7}\)})^{21-12  =} (\(\frac{3}{7}\))⁹ 

\(\left(\frac{3}{7}\right)^{21}:\left(\frac{9}{49}\right)^6=\left(\frac{3}{7}\right)^{21}:\left(\left(\frac{3}{7}\right)^2\right)^6=\left(\frac{3}{7}\right)^{21}:\left(\frac{3}{7}\right)^{2.6}=\left(\frac{3}{7}\right)^{21}:\left(\frac{3}{7}\right)^{12}\)

\(=\left(\frac{3}{7}\right)^{21-12}=\left(\frac{3}{7}\right)^9\)

\(\left(\frac{3}{7}\right)^{21}:\left(\frac{9}{49}\right)^6\\ =\left(\frac{3}{7}\right)^{21}:\left(\frac{3}{7}^2\right)^6\\ =\left(\frac{3}{7}\right)^{21}:\left(\frac{3}{7}\right)^{2.6}\\ =\left(\frac{3}{7}\right)^{21}:\left(\frac{3}{7}\right)^{12}\\ =\left(\frac{3}{7}\right)^{21-12}\\ =\left(\frac{3}{7}\right)^9\)

k nha 

\(\left(\frac{3}{7}\right)^{21}:\left[\left(\frac{3}{7}\right)^2\right]^6=\left(\frac{3}{7}\right)^{21}:\left(\frac{3}{7}\right)^{12}=\left(\frac{3}{7}\right)^{21-12}=\left(\frac{3}{7}\right)^9\)

b, \(\left(\frac{3}{7}\right)^{21}:\left(\frac{9}{49}\right)^6=\left(\frac{3}{7}\right)^{21}:\left[\left(\frac{3}{7}\right)^2\right]^6=\left(\frac{3}{7}\right)^{21}:\left(\frac{3}{7}\right)^{12}=\left(\frac{3}{7}\right)^{21-12}=\left(\frac{3}{7}\right)^9\)

a) \(25^3:5^2=5^6:5^2=5^4=625\)

b) \(\left(\frac{3}{7}\right)^{21}:\left(\frac{9}{49}\right)^6=\left(\frac{3}{7}\right)^{21}:\left(\frac{3}{7}\right)^{12}=\left(\frac{3}{7}\right)^9\)

c) \(3-\left(-\frac{6}{7}\right)^0+\left(\frac{1}{2}\right)^2:2=3-1+\frac{1}{8}=\frac{17}{8}\)

a) \(25^3:5^2=5^6:5^2=5^{6-2}=5^4\)

\(\left(\frac{3}{7}\right)^{21}:\left(\frac{9}{49}\right)^6\)\(=\left(\frac{3}{7}\right)^{21}:\left(\frac{3}{7}\right)^{2^6}\)\(=\left(\frac{3}{7}\right)^{21}:\left(\frac{3}{7}\right)^{12}\)

                                  \(=\left(\frac{3}{7}\right)^{21-12}\)\(=\left(\frac{3}{7}\right)^9\)

\(\left(\frac{3}{7}\right)^{21}:\left(\frac{9}{49}\right)^6\)

\(=\left(\frac{3}{7}\right)^9.\left(\frac{3}{7}\right)^{12}:\left[\left(\frac{3}{7}\right)^2\right]^6\)

\(=\left(\frac{3}{7}\right)^9.\left(\frac{3}{7}\right)^{12}:\left(\frac{3}{7}\right)^{12}\)

\(=\left(\frac{3}{7}\right)^9=\frac{3^9}{7^9}=\frac{19683}{40353607}\)

(3/7)²¹:(3/7²)⁶

(3/7)²¹:(3/7)¹²

(3/7)^21-12

(3/7)⁹