jimmmmmmmmmmmmmmmmmmmmmmmmmmm

he he he he he he

bài 1:

bn lấy giá trị của √(4^2-3,9^2) là dc

bài 2

AB+BC=2√(3^2+4^2)=??

A = 0 nha bạn

A= 0 nha bạn

\(S=1+2+2^2+2^3+...+2^{2020}+2^{2021}\)

\(=\left(1+2\right)+\left(2^2+2^3\right)+...+\left(2^{2020}+2^{2021}\right)\)

\(=3+2^2\left(1+2\right)+...+2^{2020}\left(1+2\right)\)

\(=3+2^2.3+...+2^{2020}.3⋮3\)

     VẬY \(S⋮3\)

Trả lời :...........................................

SCSH: (2021 - 1) : 1 = 2020

Tổng: (2021 + 1) : 2 = 1011

Hk tốt,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,

k nhé

\(S=1+2+2^2+2^3+...+2^{2020}+2^{2021}\)

\(\text{Số số hạng của S là 2022 số , chia làm 1011 cặp , mỗi cặp 2 số .}\)

\(\Leftrightarrow S=\left(1+2\right)+\left(2^2+2^3\right)+...+\left(2^{2020}+2^{2021}\right)\)

\(\Leftrightarrow S=3+2^2\left(1+2\right)+...+2^{2020}\left(1+2\right)\)

\(\Leftrightarrow S=3+2^2\times3+...+2^{2020}\times3\)

\(\Leftrightarrow S=3\left(1+2^2+...+2^{2020}\right)\)

\(\Rightarrow S⋮3\left(đpcm\right)\)

ta có:

\(-\frac{x}{2}=\frac{-y}{4}=\frac{6}{-8}\)

=>\(\frac{-x}{2}=\frac{6}{-8}\)

=>-8.(-x)=6.2

=>8x=12

=>x=3/2

lại có:

\(\frac{-y}{4}=\frac{6}{-8}\)

=>-8.(-y)=6.4

=>8y=24

=>y=3

Vậy x=3/2; y=3

làm như thế này mới nhanh

\(\frac{-x}{2}=\frac{-y}{4}=\frac{6}{-8}\)

=>\(\frac{-x}{2}=-y=\frac{6.4}{-8}\)

=>\(\frac{-x}{2}=-y=-3\)

=>\(\frac{-x}{2}=\frac{-3}{1}=>-x=\frac{-3.2}{1}=-6\)

=>x=-6 ;y=-3