\(\frac{5}{7}:x+\frac{4}{5}=\frac{1}{6}tìmx\)
\(\left(\frac{1}{2}\right)^{x-1}+\left(\frac{1}{2}\right)^{x-4}=\frac{5}{4}.Tìmx\)
\(\frac{3}{2}x-\frac{11}{5}=\frac{7}{8}\times\frac{64}{49}tìmx\)
\(\frac{3}{2}x-\frac{11}{5}=\frac{7}{8}.\frac{64}{49}\)
\(\frac{3}{2}x-\frac{11}{5}=\frac{8}{7}\)
\(\frac{3}{2}x=\frac{8}{7}+\frac{11}{5}=\frac{117}{35}\)
\(x=\frac{117}{35}:\frac{3}{2}=\frac{78}{35}\)
\(\frac{3}{2}x-\frac{11}{5}=\frac{7}{8}.\frac{64}{49}\)
\(\frac{3}{2}x-\frac{11}{5}=\frac{8}{7}\)
\(\frac{3}{2}x=\frac{8}{7}+\frac{11}{5}\)
\(\frac{3}{2}x=\frac{117}{35}\)
\(x=\frac{117}{35}:\frac{3}{2}\)
\(x=\frac{78}{35}\)
\(tìmx;y;z, biết :\frac{x}{3}=\frac{y}{5}=\frac{z}{7} và 2x+3y-z=-14\)
A= 2^2019-2^2018-...-2^2-2^1-1
??????
ÁP dụng tc dãy tỉ số bằng nhau ta có:
\(\frac{x}{3}=\frac{y}{5}=\frac{z}{7}=\frac{2x}{6}=\frac{3y}{15}=\frac{z}{7}=\frac{2x+3y-z}{6+15-7}=\frac{-14}{14}=-1\)
\(\Rightarrow x=-3;y=-5;z=-7\)
Đặt \(\frac{x}{3}=\frac{y}{5}=\frac{z}{7}=k\)
\(\Rightarrow x=3k;y=5k;z=7k\)
\(2x+3y-z=-14\)
\(\Leftrightarrow6k+15k-7k=-14\)
\(\Leftrightarrow14k=-14\)
\(\Leftrightarrow k=-1\)
\(\Rightarrow x=-3;y=-5;z=-7\)
\(\frac{-2}{3}\times x+\frac{1}{5}=\frac{3}{10}tìmx\)
\(\frac{-2}{3}.x+\frac{1}{5}=\frac{3}{10}\)
\(\frac{-2}{3}.x=\frac{3}{10}-\frac{1}{5}=\frac{1}{10}\)
\(x=\frac{1}{10}:\frac{-2}{3}=-\frac{3}{20}\)
\(Tìmx \)
\(\frac{1}{6}x+\frac{1}{10}x-\frac{4}{15}x+1=0\)
Ta có : \(\frac{1}{6}x+\frac{1}{10}x-\frac{4}{15}x+1=0\)
<=> \(\frac{1}{6}x+\frac{1}{10}x-\frac{4}{15}x=-1\)
<=> \(\left(\frac{1}{6}+\frac{1}{10}-\frac{4}{15}\right)x=-1\)
<=> \(0.x=-1\)
=> x thuộc rỗng
\(\frac{1}{6}x+\frac{1}{10}x-\frac{4}{15}x+1=0\)
\(\Leftrightarrow\left(\frac{1}{6}+\frac{1}{10}-\frac{4}{15}\right)x+1=0\)
\(\Leftrightarrow\left(\frac{5}{30}+\frac{3}{30}-\frac{8}{30}\right)x+1=0\)
\(\Leftrightarrow\frac{5+3-8}{30}x+1=0\)
\(\Leftrightarrow0x=-1\)(vô lí)
vậy không có giá trị nào của x thỏa mãn.
a) tìm x,y biết : 2^x-2^y=256
b) tìm x,y nguyên biết: x^2.y-x+x.y=6
c) tìmx,y sao cho:\(\frac{5}{x}-\frac{y}{3}=\frac{1}{6}\)
\(\left(\frac{2}{5}\right)^x>\left(\frac{5}{2}\right)^{-3}.\left(-\frac{2}{5}\right).Tìmx\)
x=4 cách lm tính vế trái sau đó đc -16/625 suy ra x= 4
\(1\frac{1}{3}x-\frac{1}{3}=\left(2x-1\right):\left(1-\frac{2}{5}\right)tìmx\)
Từ đề bài ta có:
4/3x - 1/3 = (2x-1) : 3/5
=> 4/3x -1/3 = (2x-1) * 5/3
=> 4/3x -1/3= 10/3x - 5/3
Chuyển vế đổi dấu
Ta được:
=> -2x = -4/3
=> x= 2/3
Vậy x= 2/3
\(1\frac{1}{3}x=\left(2x-1\right):\left(1-\frac{2}{5}\right)\)
\(\frac{4}{3}x=\left(2x-1\right):\left(\frac{3}{5}\right)\)
\(\frac{4}{3}x.\frac{3}{5}=\left(2x-1\right)\)
\(\frac{4}{5}x=\left(2x-1\right)\)
\(x=\left(2x-1\right):\frac{4}{5}\)
\(x=\left(2x-1\right).\frac{5}{4}\)
\(x=2x.\frac{5}{4}-1.\frac{5}{4}\)
\(x=\)\(2x.\frac{5}{4}-\frac{5}{4}\)
\(x=2.\frac{5}{4}.x-\frac{5}{4}\)
\(x=\left(\frac{5}{2}.x\right)-\frac{5}{4}\)
\(x=\frac{5}{2}-\frac{5}{4}.x-\frac{5}{4}\)
\(x=\frac{5}{4}.x-\frac{5}{4}\)
\(x=x\left(\frac{5}{4}-\frac{5}{4}\right)\)
\(x=x.0\)
\(=>x=0\)
tìm x, x\(\in\)Q:
a) \(\frac{\left(x+\frac{3}{4}\right).\frac{7}{2}-\frac{1}{6}}{-\left(\frac{4}{5}+\frac{1}{3}\right).\frac{1}{2}+1}=2\frac{33}{52}\)
b) \(\frac{\left(5-\frac{2}{7}\right).\frac{7}{9}:\frac{3}{5}}{\left(3x-\frac{5}{6}\right):\frac{1}{7}}=5\frac{5}{21}\)