1+1=2
2+2=10
3+3=?
22-2*(5871/103+9*2-(1+1+6)*8)
a) So sánh: -22/45 và -51/103
b) Tính:
( 92 - 1/9 - 2/10 - 3/11 - ... - 92/100 ) : ( 1/45 + 1/50 + 1/55 + ... + 1/500 )
( 1/24 x 25 + 1/25 x 26 + ... + 1/29 x 30 ) x 150 + 103/100 [ 103/100 x ( X - 1 ) ] = 22
tính nhanh
a, 1-2+3-4+5-6+......+101-102+103
b, 2-4+6-8+10-21+.....+98-100+102
c, 16-18+20-22+.....+64-66+68
bai 1: tính tổng
1, 1+2+3+.....+99+100
2, 101+102+103+......+200+201
3, 2+5+8+11+......+294+206
4, 11+22+33+44+..........+99+110
5, 367+361+155+........+7+1
1 = 2
2 = 10
3 = 30
4 = 68
5 = ?
1 = 2
2 = 10
3 = 30
4 = 68
5 = 130
Chứng minh rằng: 1/5+1/20+1/21+1/22+1/23+1/24+1/25+1/101+1/102+1/103+1/104 +1/105<1/2
1/5+(1/20+1/21+1/22+1/23+1/24+1/25)+(1/101+1/102+103+104+105) Ta thấy 1/21;1/22;1/23;1/24;1/25 đều nhỏ hơn 1/20 nên 1/21+1/22+1/23+1/24+1/25<5×1/20<1/4 Tương tự 1/101+1/102+1/103+1/104+1/105<5×1/100<1/20 1/5+1/20+1/20=6/20=3/10 1/5+(<1/4)+(<1/20)<1/2 1/2=5/10 3/10<5/10 vậy suy ra điều cần chứng minh
Chứng minh rằng: 1/5+1/20+1/21+1/22+1/23+1/24+1/25+1/101+1/102+1/103+1/104 +1/105<1/2
1/5+(1/20+1/21+1/22+1/23+1/24+1/25)+(1/101+1/102+103+104+105)
Ta thấy 1/21;1/22;1/23;1/24;1/25 đều nhỏ hơn 1/20 nên
1/21+1/22+1/23+1/24+1/25<5×1/20<1/4
Tương tự
1/101+1/102+1/103+1/104+1/105<5×1/100<1/20
1/5+1/20+1/20=6/20=3/10
1/5+(<1/4)+(<1/20)<1/2
1/2=5/10
3/10<5/10 vậy suy ra điều cần chứng minh
S = 1/5 +1/21+1/22+1/23+1/24+1/25+1/101+1/102+1/103+1/104+1/105<1/2
vi 1/5+5/21+5/101 <1/5+5/20+5/100=1/2=> S<1/2
1 tính hợp lí
a 25.(17-19)+19.25+17.75
b -100/101-100/-101+2012 3/4-0,75
c (1/5-1/6-1/30).(21/22+22/23+.....+102/103
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