9) | x –3| –7 = 13
10) 72 –3.|x + 1| = 9
11) 17 –(43 –x) = 45
12) 3| x –1| –5 = 7
I x-3I-7=13
72-3*I x+1 I=9
17-(43-x)=45
3 Ix-1 I-5=7
|x-3|-7=13 72-3.|x+1|=9
|x-3| =13+7 3.|x+1|=72-9
|x-3| =6 3.|x+1|=63
=> x-3=6 hoặc x-3=-6 |x+1|=63:3
Ta có: x-3=6 x-3=-6 |x+1|=21
x =6+3 x =(-6)+3 => x+1=21 hoặc x+1=-21
x =9 x =-3 Ta có: x+1=21 x+1=-21
Vậy x thuộc 9; -3 x =21-1 x =(-21)-1
x =20 x =(-21)+(-1)
x =-20
Vậy x thuộc 20;-20
17-(43-x)=45 3.|x-1|-5=7
43-x =17-45 3.|x-1| =7+5
43-x =-28 3.|x-1| =12
x =43-(-28) |x-1| =12:3
x =43+28 |x-1| =4
x =71 => x-1=4 hoặc x-1=-4
Ta có: x-1=4 x-1=-4
x =4+1 x=(-4)+1
x =5 x=-3
Vậy x thuộc 5;-3
|x-3|=20
x-3 = 20
x-3 =-20
x=20+3
x=-20=3
x=23
x=-17
|x-3|=20
x-3 = 20
x-3 =-20
x=20+3
x=-20=3
x=23
x=-17
Tìm x thuộc z, biết
a)|x-2|=3 c)72-3.|x+1|=9 e)|x|<3
b)|x-3|-7=13 d)17 -(43-|x|)=45 f)3|x-1|-5=7
a,|x-2|=3
=>x-2= 3 hoặc -3
-với x -2 =3 =>x=1
-với x-2 = -3 =>x= -1
Vậy x ∈ {1;-1}
b, |x-3|-7=13
=>|x-3|=13-7=6
=>x-3=6 hoặc -6
-với x-3 =6 => x=9
-với x-3= -6 => x=-3
Vậy x ∈ {9;-3}
c,72-3.|x+1|=9
=>3.|x+1|=72-9=63
=>|x+1|=63:3=21
=>x+1 = 21 hoặc -21
-với x+1 = 21 => x=20
-với x+1 = -21 => x= -22
Vậy x ∈ {20;-21}
d,17-(43-|x|)=45
=>43-|x|=17-45= -28
=>|x|=43-(-28)=71
=> x =71 hoăc -71
Vậy x ∈ {71;-71}
f, 3|x-1|-5=7
=>3|x-1|=7+5=12
=>|x-1|=12:3=4
=>x-1=4 hoặc -4
-với x-1=4 =>x=5
-với x-1=-4=>x=-3
Vậy x ∈ {5;-3}
CHÚC BẠN LÀM BÀI TÔT NHA
a) \(\left|x-2\right|=3\\ \Rightarrow\left[{}\begin{matrix}x-2=3\\x-2=-3\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=3+2\\x=-3+2\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=5\\x=-1\end{matrix}\right.\)Vậy \(x\in\left\{5;-1\right\}\)
b) \(\left|x-3\right|-7=13\\ \left|x-3\right|=13+7\\ \left|x-3\right|=20\\ \Rightarrow\left[{}\begin{matrix}x-3=20\\x-3=-20\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=20+3\\x=-20+3\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=23\\x=-17\end{matrix}\right.\)
Vậy \(x\in\left\{23;-17\right\}\)
c) \(72-3\cdot\left|x+1\right|=9\\ 3\left|x+1\right|=72-9\\ 3\left|x+1\right|=63\\ \Rightarrow\left[{}\begin{matrix}x+1=63\\x+1=-63\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=63-1\\x=-63-1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=62\\x=-64\end{matrix}\right.\)
Vậy \(x\in\left\{62;-64\right\}\)
d) \(17-\left(43-\left|x\right|\right)=45\\ 43-\left|x\right|=17-45\\ 43-\left|x\right|=-28\\ \left|x\right|=43-\left(-28\right)\\ \left|x\right|=43+28\\ \left|x\right|=71\\ \Rightarrow x\in\left\{71;-71\right\}\)Vậy \(x\in\left\{71;-71\right\}\)
e) \(\left|x\right|< 3\\ \left|x\right|\in\left\{0;1;2\right\}\\ \Rightarrow x\in\left\{0;\pm1;\pm2\right\}\)Vậy \(x\in\left\{0;\pm1;\pm2\right\}\)
f) \(3\left|x-1\right|-5=7\\ 3\left|x-1\right|=7+5\\ 3\left|x-1\right|=12\\ \left|x-1\right|=12:3\\ \left|x-1\right|=4\\ \Rightarrow\left[{}\begin{matrix}x-1=4\\x-1=-4\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=4+1\\x=-4+1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=5\\x=-3\end{matrix}\right.\)
Vậy \(x\in\left\{5;-3\right\}\)
tìm xez , biết
a) |x - 3 | - 7 = 13
b) 72 - 3 . | x + 1 | = 9
c) 17 - ( 43 - |x| ) = 45
d) 3 | x - 1 | - 5 = 7
e) -12 ( x - 5 ) + 7 (3 - x ) = 5
a. \(\left|x-3\right|-7=13\Leftrightarrow\left|x-3\right|=20\)
TH1: \(x-3=20\Leftrightarrow x=23\)
TH2: \(x-3=-20\Leftrightarrow x=-17\)
b. \(72-3.\left|x+1\right|=9\Leftrightarrow\left|x+1\right|=21\)
TH1: \(x+1=21\Leftrightarrow x=20\)
TH2: \(x+1=-21\Leftrightarrow x=-22\)
c. \(17-\left(43-\left|x\right|\right)=45\Leftrightarrow\left|x\right|=71\)
TH1: \(x=71\)
TH2: \(x=-71\)
d. \(3\left|x-1\right|-5=7\Leftrightarrow\left|x-1\right|=4\)
TH1: \(x-1=4\Leftrightarrow x=5\)
TH2: \(x-1=-4\Leftrightarrow x=-3\)
e. \(-12\left(x-5\right)+7\left(3-x\right)=5\Leftrightarrow-12x+60+21-7x=5\Leftrightarrow-19x=-76\Leftrightarrow x=4\)
a.
\(\left|x-3\right|-7=13\)
\(\left|x-3\right|=13+7\)
\(\left|x-3\right|=20\)
\(x-3=\pm20\)
\(x-3=20\)\(x=20+3\)
\(x=23\)
\(x-3=-20\)\(x=-20+3\)
\(x=-17\)
Vậy x = 23 hoặc x = - 17.
b.
\(72-3\times\left|x+1\right|=9\)
\(3\times\left|x+1\right|=72-9\)
\(3\times\left|x+1\right|=63\)
\(\left|x+1\right|=63\div3\)
\(\left|x+1\right|=21\)
\(x+1=\pm21\)
\(x+1=21\)\(x=21-1\)
\(x=20\)
\(x+1=-21\)\(x=-21-1\)
\(x=-22\)
Vậy x = 20 hoặc x = - 22.
c.
\(17-\left(43-\left|x\right|\right)=45\)
\(43-\left|x\right|=17-45\)
\(43-\left|x\right|=-28\)
\(\left|x\right|=43-\left(-28\right)\)
\(\left|x\right|=71\)
\(x=\pm71\)
Vậy x = 71 hoặc x = - 71.
d.
\(3\times\left|x-1\right|-5=7\)
\(3\times\left|x-1\right|=7+5\)
\(3\times\left|x-1\right|=12\)
\(\left|x-1\right|=12\div3\)
\(\left|x-1\right|=4\)
\(x-1=\pm4\)
\(x-1=4\)\(x=4+1\)
\(x=5\)
\(x-1=-4\)\(x=-4+1\)
\(x=-3\)
Vậy x = 5 hoặc x = - 3.
e.
\(-12\times\left(x-5\right)+7\times\left(3-x\right)=5\)
\(-12\times x+\left(-12\right)\times\left(-5\right)+7\times3-7\times x=5\)
\(-12\times x+60+21-7\times x=5\)
\(-19\times x+81=5\)
\(-19\times x=5-81\)
\(-19\times x=-76\)
\(x=\frac{-76}{-19}\)
\(x=4\)
Chúc bạn học tốt
I x-3 I - 7 = 13
I x - 3 I= 13+7
I x - 3 I= 30
x - 3 =30
x= 30+3
x= 33
1)x –2 = –6
2) –5x –(–3) = 13
3) 15–( x –7 ) = –21
4) 3x + 17 = 2
5) 45 –( x–9) = –35
6) (–5) + x = 15
7) 2x –(–17) = 15
8) |x –2| = 3.
9) | x –3| –7 = 13
10) 72 –3.|x + 1| = 9
11) 17 –(43 –x) = 45
12) 3| x –1| –5 = 7
1) x - 2 = -6
x = - 6 + 2
x = -4
2) -5x-(-3)=13
-5x+3=13
-5x=13-3=10
x=10:(-5)
x=-2
3) 15-(x-7)=21
15-x+7=21
15-x=21-7=14
x=15-14=1
4) 3x+17=2
3x=2-17=-15
x=-15:3=-5
5) 45-(x-9)=-35
45-x+9=-35
45-x=-35-9=-44
x=45-(-44)=89
6) -5+x=15
x=15-(-5)
x=20
7) 2x-(-17)=15
2x+17=15
2x=15-17=-2
x=-2:2=-1
8) \(\left|x-2\right|=3\\ \Rightarrow x-2=\pm3\)
+) x - 2 = 3
x = 5
+) x - 2 = -3
x = -1
\(\Rightarrow x\in\left\{5;-1\right\}\)
Các câu 9; 10; 12 tương tự câu 8; còn câu 11 tương tự câu 3; 5
Chúc bạn học tốt!
Tìm x € Z
a. |x - 2| = 3
b. |x - 3| - 7 = 13
c. 72 - 3 . | x + 1| =9
d. 17 - (43 - |x|) = 45
e. 3|x - 1| - 5 = 7
a.\(\Rightarrow\)\(\left\{{}\begin{matrix}x-2=3\\x-2=-3\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=5\\x=-1\end{matrix}\right.\)
b.\(\Rightarrow\)\(\left\{{}\begin{matrix}x-3=20\\x-3=-20\end{matrix}\right.\)
\(\Rightarrow\)\(\left\{{}\begin{matrix}x=23\\x=-17\end{matrix}\right.\)
c.
a) \(\left|x-2\right|=3\)
\(\circledast\) TH1: x-2=3
x=3+2
x=5
\(\circledast\) TH2: x-2=-3
x=-3+2
x=-1
Vậy x\(\in\){-1;5}.
b) \(\left|x-3\right|-7=13\)
\(\left|x-3\right|=13+7\)
\(\left|x-3\right|=20\)
\(\circledast\) TH1: x-3=20
x=20+3
x=23
\(\circledast\) TH2: x-3=-20
x=-20+3
x=-17
Vậy x\(\in\){-17;23}.
c) \(72-3\cdot\left|x+1\right|=9\)
\(3\cdot\left|x+1\right|=72-9\)
\(3\cdot\left|x+1\right|=63\)
\(\left|x+1\right|=\dfrac{63}{3}\)
\(\left|x+1\right|=21\)
\(\circledast\) TH1: x+1=21
x=21-1
x=20
\(\circledast\) TH2: x+1=-21
x=-21-1
x=-22
Vậy x\(\in\){-22;20}.
d) \(17-\left(43-\left|x\right|\right)=45\)
\(43-\left|x\right|=17-45\)
\(43-\left|x\right|=-28\)
\(\left|x\right|=43-\left(-28\right)\)
\(\left|x\right|=71\)
x=71 hoặc x=-71
Vậy x\(\in\){-71;71}.
e) \(3\left|x-1\right|-5=7\)
\(3\left|x-1\right|=7+5\)
\(3\left|x-1\right|=12\)
\(\left|x-1\right|=\dfrac{12}{3}\)
\(\left|x-1\right|=4\)
\(\circledast\) TH1: x-1=4
x=4+1
x=5
\(\circledast\) TH2: x-1=-4
x=-4+1
x=-3
Vậy x\(\in\){-3;5}.
1, 72-3./x+1/=9
2, 17-(43-/x/)=45
3, 3/x-1/-5=7
4, -12.(x-5)+7.(3-x)=5
5, (x-2) . (x+4)=0
6, (x-2).(x+15)=0
7, (7-x).(x+19)=0
8, -5<x<1
9, /x/<3
10, (x.3).(x-5)<0
Tìm x thuộc Z:
1) -5x - (-3) = 13
2) 15 - ( x - 7) = -21
3) 45 - ( x - 9) = -35
4) | x - 2 | = 3
5) | x - 3| - 7 = 13
6) 72 - 3 . | x + 1 | = 9
7) 17 - ( 43 - | x | ) = 45
8) 3| x - 1| - 5 = 7
9) -12( x - 5) + 7( 3 -x) = 5
10) (x - 2) . ( x + 4 ) = 0
1) -5x - (-3) = 13
\(\Rightarrow-5x+3=13\)
\(\Rightarrow-5x=10\)
\(\Rightarrow x=-2\)
Vậy: \(x=-2\)
2) 15 - ( x - 7) = -21
\(\Rightarrow15-x+7=-21\)
\(\Rightarrow15+7-x=-21\)
\(\Rightarrow22-x=-21\)
\(\Rightarrow x=-22-21=-43\)
Vậy: \(x=-43\)
3) 45 - ( x - 9) = -35
\(\Rightarrow45-x+9=-35\)
\(\Rightarrow45+9-x=-35\)
\(\Rightarrow54-x=-35\)
\(\Rightarrow x=-54-35=-89\)
Vậy: \(x=-89\)
4)/x-2/=3\(\Rightarrow\)ta có 2 t/h:
t/h1: x-2=3\(\Rightarrow\)x=2+3=5
t/h2: x-2=-3\(\Rightarrow\)x=2+(-3)=-1
Vậy x=5 hoặc -1
Các bạn ơi trả lời giúp mk mấy câu hỏi này đi mk đang cần rất gấp ngay bây giờ?
72-3.|x+1|=9
17-(43-|x|)=45
3|x-1|-5=7
Giúp mk vs các bạn ơi
a) 72 - 3.|x+1| = 9
=> 3.|x+1| = 63
=> |x+1| = 21 => \(\left[{}\begin{matrix}x+1=21\\x+1=-21\end{matrix}\right.=>\left[{}\begin{matrix}x=20\\x=-22\end{matrix}\right.\)
b) 17 - (43 - |x|) = 45
=> 43 - |x| = -28
=> |x| = 71 => \(\left[{}\begin{matrix}x=71\\x=-71\end{matrix}\right.\)
c) 3|x-1|-5=7
=> 3|x-1|=12
=> |x-1| = 4 => \(\left[{}\begin{matrix}x-1=4\\x-1=-4\end{matrix}\right.=>\left[{}\begin{matrix}x=5\\x=-3\end{matrix}\right.\)
Chúc bn học tốt
a) \(72-3\cdot\left|x+1\right|=9\)
\(3\cdot\left|x+1\right|=72-9\)
\(3\cdot\left|x+1\right|=63\)
\(\left|x+1\right|=\dfrac{63}{3}\)
\(\left|x+1\right|=21\)
\(\circledast\)TH1: x+1=21
x=21-1
x=20
\(\circledast\)TH2: x+1=-21
x=-21-1
x=-22
Vậy \(x\in\left\{-22;20\right\}\).
b) \(17-\left(43-\left|x\right|\right)=45\\
17-43+\left|x\right|=45\\
-26+\left|x\right|=45\\
\left|x\right|=45-\left(-26\right)\\
\left|x\right|=71\)
x=71 hoặc x=-71
Vậy \(x\in\left\{-71;71\right\}\).
c) \(3\left|x-1\right|-5=7\\ 3\left|x-1\right|=7+5\\ 3\left|x-1\right|=12\\ \left|x-1\right|=\dfrac{12}{3}\\ \left|x-1\right|=4\)
\(\circledast\)TH1: x-1=4
x=4+1
x=5
\(\circledast\)TH2: x-1=-4
x=-4+1
x=-3
Vậy \(x\in\left\{-3;5\right\}\).
Giúp mình với các bạn xin các bạn làm hết nhe
A) (-5)+x=15
b) 2x-(-17)=15
c) |x-2|=3
d) |x-3|-7=13
e) 72-3|x+1|=9
j) 17-(43|x|)=45
3|x-1|-5=7
a)x=15+5=20
b)x=(15-17):2=-1
c)=>x-2=+-3
th1x=-3+2=-5
th2x=3+2=5
d)x-3=+-8
th1x=-8+3=-5
th2x=8+3=11
e)x+1=(72-9):3=+-21
th1x=-21-1=-22
th2x=21-1=20
j)lxl=(17-45):43=-28/43
=>x\(\in\Phi\)
x-1=(7+5):3=+-4
th1x=-4+1=-3
th2x=4+1=5
mk làm tắt đó tự suy luận ra mk làm
1, tìm x thuộc z biết
-12.(x-5)+7.(3-x)=5
72-(43-|x|)=45
3.|x-1|-5=7
72-3.|x+1|=9
a)-12(x-5)+7(3-x)=5
-12x-(-60)+21-7x=5
-12x+60+21-7x=5
-12x-7x=5-60-21
-19x=-76
x=-76/-19
x=4. Vậy x=4
ặc, bạn ghi ít ít thôi, ghi thế này nhiều quá