(2^17+17^2).(9^15-3^15).(2^4-4^2)
( 2^17+17^2)×(9^15-3^15)×(2^4-4^2)
Giúp mk vs
Bài 13: Dấu <, =, >
10 … 10 + 3
11 + 2…. 2 + 11
9 … 10 + 9
10 … 10 + 0
17 – 4 … 14 - 3
18 – 4 … 12
15 … 15 – 1
17 + 1… 17 + 2
12+ 5 … 16
16 … 19 - 3
15 – 4 … 10 + 1
19 – 3 … 11
10 < 10 + 3
11 + 2=2 + 11
9 < 10 + 9
10 = 10 + 0
17 – 4 > 14 - 3
18 – 4 >12
15 > 15 – 1
17 + 1<17 + 2
12+ 5 > 16
16 =19 - 3
15 – 4 =10 + 1
19 – 3 >11
( 2 mũ 17 + 17 mũ 2 ) . ( 9 mũ 15 - 3 mũ 15 ) . ( 2 mũ 4 - 4 mũ 2 )
2 mũ 4 - 4 mũ 2=16-16=0
( 2 mũ 17 + 17 mũ 2 ) . ( 9 mũ 15 - 3 mũ 15 ).0=0
đ/s: 0
Giúp em với:
(2^17 + 17^2) . (9^15 - 3^15) . (2^4 - 4^2)
(13+2/9 - 15+2/3).(302 - 54)
(18+3/7 - 17+1/4).(25-12.52)
x Y=
2/11+3/13+4/15+5/17
4+1/11+5/13+9/15+13/17
[2 mu 17 + 17 mu 2 ] nhan [9 mu 15 - 3 mu 15] nhan [ 2 mu 4-4 mu 2]
(2 mũ 17 + 17 mũ 2 ).( 9 mũ 15 - 3 mũ 15). ( 2 mũ 4 - 4 mũ 20 )
a. (217 + 172) . (915 - 315) . (24 - 42)
= ( 2^17 + 17^2) . ( 9^15 - 3^15) . ( 16 - 16)
= ( 2^17 +17^2) . ( 9^ 15 - 3^15) . 0
= 0
Tính hợp lý
(2^17 +17^2 ) x (9^15 - 15^9 ) x ( 4^2 -2^4)
\(\left(2^{17}+17^2\right)\left(9^{15}-15^9\right)\left(4^2-2^4\right)\)
\(=\left(2^{17}+17^2\right)\left(9^{15}-15^9\right)\left(16-16\right)\)
\(=\left(2^{17}+17^2\right)\left(9^{15}-15^9\right).0\)
\(=0\)
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