(10x + 120) - 138 = 262

10x+120=262+138

10x+120=400

10x=400-120

10x=280

x=280:10

x=28

\(2\left(x-5\right)+10=20\)

\(\Leftrightarrow2\left(x-5\right)=10\)

\(\Leftrightarrow x-5=5\)

\(\Leftrightarrow x=10\)

\(\left(3x+1\right)-17=5\)

\(\Leftrightarrow3x+1=22\)

\(\Leftrightarrow3x=21\)

\(\Leftrightarrow x=7\)

\(\left(10x+120\right)-138=262\)

\(\Leftrightarrow10x+120=400\)

\(\Leftrightarrow10x=280\)

\(\Leftrightarrow x=28\)

\(4\left(x+1\right)-12=8\)

\(\Leftrightarrow4\left(x+1\right)=20\)

\(\Leftrightarrow x+1=5\)

\(\Leftrightarrow x=4\)

\(2x+2\frac{1}{3}=\frac{1}{2}:\frac{3}{2}\)

\(\Leftrightarrow2x+\frac{7}{3}=\frac{1}{3}\)

\(\Leftrightarrow2x=-2\)

\(\Leftrightarrow x=-1\)

\(2\left(x-5\right)+10=20\)

\(2x-10+10=20\)

\(2x=20\)

\(x=10\)

\(\left(3x+1\right)-17=5\)

\(3x+1-17=5\)

\(3x-16=5\)

\(3x=21\)

\(x=\frac{21}{3}=7\)

\(\left(10x+120\right)-138=262\)

\(10x+120-138=262\)

\(10x-18=262\)

\(10x=280\)

\(x=28\)

\(4\left(x+1\right)-12=8\)

\(4x+4-12=8\)

\(4x-8=8\)

\(4x=16\)

\(x=4\)

2.(x-5)+10 = 20

2.(x-5) = 20 - 10

2.(x-5) = 10

x-5 = 10 : 2

x-5 = 5

x = 5 + 5

x = 10

(3x+1)-17 = 5

3x+1 = 5 + 17

3x+1 = 22

3x = 22 - 1

3x = 21

x = 21 : 3

x = 7

(10x+120)-138 = 262

10x+120 = 262 + 138

10x+120 = 400

10x = 400-120

10x = 280

x = 280 : 10

x = 28

4.(x+1)-12 = 8

4.(x+1) = 8 + 12

4.(x+1) = 20

x+1 = 20 : 4

x+1 = 5

x = 5 - 1

x = 4

\(2x+2\frac{1}{3}=\frac{1}{2}:\frac{3}{2}\)

\(2x+\frac{7}{3}=\frac{1}{3}\)

\(2x=\frac{1}{3}-\frac{7}{3}\)

\(2x=-2\)

x = (-2) : 2

x = -1

2.(x-5)+10=20

2.(x-5)=20-10

2.(x-5)=10

x-5=5

\(\Rightarrow\)x=10

(3x+1)-17=5

3x+1=22

3x=21

\(\Rightarrow\)x=7

(10x+120)-138=262

(10x+120)=400

10x=280

\(\Rightarrow\)x=28

4.(x+1-10)=8

x+1-10=2

x+1=12

\(\Rightarrow\)x=11

\(2x+2\frac{1}{3}=\frac{1}{2}:\frac{3}{2}\)

\(2x+\frac{7}{3}=\frac{1}{3}\)

\(2x=\frac{-6}{3}=-2\)

\(\Rightarrow x=-1\)

Ta có : \(\frac{x}{2}=\frac{y}{3}\Rightarrow\frac{x}{10}=\frac{y}{15}\)

            \(\frac{y}{5}=\frac{z}{7}\Rightarrow\frac{y}{15}=\frac{z}{21}\)

Do đó : \(\frac{x}{10}=\frac{y}{15}=\frac{z}{21}\)

Ta có : \(\frac{x}{10}=\frac{y}{15}=\frac{z}{21}=\frac{x+y+z}{10+15+21}=\frac{138}{46}=3\)

Nên : \(\frac{x}{10}=3\Rightarrow x=30\)

           \(\frac{y}{15}=3\Rightarrow y=45\)

           \(\frac{z}{21}=3\Rightarrow z=63\)

Vậy x = 30 ; y = 45 ; z = 63

=568,54

262 x 2,17 = 568.54

x = 4586