37.13+13

24+37.12

=13.(37-1)

đăng nhầm

\(\frac{37.13-13}{24+37.12}=\frac{13-13}{24+12}=\frac{1}{36}\)

Bai lam

\(3^{x+1}=9^x\Leftrightarrow3^{x+1}=3^{2x}\)

\(\Leftrightarrow x-1=2x\Leftrightarrow-x-1=0\Leftrightarrow x=-1\)

( 37 . 13 - 13 ) : ( 24 + 37 . 12 )

=  ( 481 - 13 ) : ( 24 + 444 )

= 468 : 468

= 1

\(\left(37.13-13\right):\left(24+37.12\right)\)

 \(=468:468\)

  \(=1\)

\(\left(37.13-13\right):\left(24+37.12\right)\)

\(=468:468\)

 \(=1\)

\(A=\frac{37\cdot13-13}{24+37\cdot12}=\frac{37\cdot\left(12+1\right)-13}{24+37\cdot12}=\frac{37\cdot12+37-13}{24+37\cdot12}=\frac{37\cdot12+24}{24+37\cdot12}=1\)

BẠN VÔ fx mà ghi

\(A=\frac{37.12+37-13}{24+37.12}\)\(=\frac{37.12+24}{24+37.12}\)\(=1\)

câu này giống bài của mình,cầu mong các bạn giúp đỡ   ^-^

TH1: \(x\le-\frac{1}{2}\)

pt <=> \(\left[-\left(x-1\right)\right]-\left[-\left(2x+1\right)\right]=13\)<=>1-x+2x+1=13 <=> 2+x=13 <=> x=11 (loại)

TH2: \(-\frac{1}{2}< x\le1\)

pt <=> \(\left[-\left(x-1\right)\right]-\left(2x+1\right)=13\) <=> 1-x-2x-1=13 <=> -3x=13 <=> x=-13/3 (loại)

TH3: x > 1

pt <=> (x-1)-(2x+1)=13 <=> x-1-2x-1=13 <=> -x-2=13 <=> x=-15 (loại)

Vậy pt vô nghiệm

\(\frac{13.\left(37-1\right)}{12\left(2+37\right)}=\frac{13.36}{12.39}=\frac{13.4.3.3}{4.3.3.13}=1\)

học tốt nhé

ủng hộ nhé

\(\frac{37.13-13}{24+37.12}=\frac{37.12+37-13}{24+37.12}=\frac{37.12+\left(37-13\right)}{24+37.12}=\frac{37.12+24}{24+37.12}=1\)

\(\frac{37.13-13}{24+37.12}\)= \(\frac{37.12+37-13}{24+37.12}\)= \(\frac{37.12+24}{24+37.12}\) = 1