1. phan tich thanh nhan tu
x^4 - y^6
Phan tich thanh nhan tu
x^2 - y - y^2 - x
\(x^2-y-y^2-x=\left(x-y\right)\left(x+y\right)-\left(x+y\right)=\left(x+y\right)\left(x-y-1\right)\)
x2 - y - y2 - x
= (x2 - y2) - x - y
= (x - y)(x + y) - (x + y)
= (x - y - 1)(x + y)
phan tich da thuc thanh nhan tu
x(x-4)+5x-20
\(=x\left(x-4\right)+5\left(x-4\right)=\left(x+5\right)\left(x-4\right)\)
Phan tich thanh nhan tu
x^2 - 5x + 5
x2 - 5x + 5
= x2 - 5(x + 1)
= x2 - \(\left[\sqrt{5\left(x+1\right)}\right]^2\)
= [x - \(\sqrt{5\left(x+1\right)}\)][x + \(\sqrt{5\left(x+1\right)}\)]
x^4 -y^6: phan tich thanh nhan tu
\(=\left(x^2\right)^2-\left(y^3\right)^2=\left(x^2-y^3\right)\left(x^2+y^3\right)\)
phan tich da thuc thanh nhan tu -25x^6-y^8+10x^3y^4
Bạn trình bầy rõ ràng chút đi. Mk chẳng hiểu gì cả.
\(-25x^6-y^8+10x^3y^4\\ =-\left(25x^6-10x^3y^4+y^8\right)\\ =-\left[\left(5x^3\right)^2-2\cdot5x^3\cdot y^4+\left(y^4\right)^2\right]\\ \\ =\left(5x^3-y^4\right)^2\)
phan tich da thuc thanh nhan tu
4.x^4.y^4+1
phan tich da thuc thanh nhan tu
x^6+y^6+z^6
phan tich thanh nhan tu
x6-y6
x^6 - y^6 = (x^3 -y^3) (x^3 + y^3)
= (x-y)(x^2 + xy + y^2 )(x+y)(x^2 -xy+ y^2)
\(x^6-y^6\)
\(=\left(x^3-y^3\right)\left(x^3+y^3\right)\)
\(=\left(x.y\right)\left(x^2+xy+y^2\right)\left(x.y\right)\left(x^2-xy+y^2\right)\)
Chúc bạn học tốt!
phan tich da thuc thanh nhan tu B=\(\left(x^2-y^2+1\right)^3-x^6-y^6-1\)