a, 3 \(\frac{14}{19}\)+ \(\frac{13}{17}\)+ \(\frac{35}{43}\)+ 6\(\frac{5}{19}\)+ \(\frac{8}{43}\)= \(\left(3\frac{14}{19}+6\frac{5}{19}\right)+\left(\frac{35}{43}+\frac{8}{43}\right)+\frac{13}{17}=\)\(9+1+\frac{13}{17}=8+\frac{13}{17}=8\frac{13}{17}\)

b, \(\frac{-5}{7}.\frac{2}{11}+\frac{-5}{7}.\frac{9}{11}+1\frac{5}{7}\)\(=\frac{-5}{7}\left(\frac{2}{11}+\frac{9}{11}\right)+1\frac{5}{7}\)\(=\frac{-5}{7}.1+1\frac{5}{7}\)\(=\frac{-5}{7}+\frac{12}{7}=\frac{7}{7}=1\)

Chúc bn học tốt

\(3\frac{14}{19}+\frac{13}{17}+\frac{35}{43}+6\frac{5}{19}+\frac{8}{43}\)

\(=\left(3\frac{14}{19}+6\frac{5}{19}\right)+\left(\frac{35}{43}+\frac{8}{43}\right)+\frac{13}{17}\)

\(=10+1+\frac{13}{17}=11+\frac{13}{17}=11\frac{13}{17}\)

\(\frac{-5}{7}.\frac{2}{11}+\frac{-5}{7}.\frac{9}{11}+1\frac{5}{7}\)

\(=\frac{-5}{7}.\frac{2}{11}+\frac{-5}{7}.\frac{9}{11}+1+\frac{-5}{7}.\left(-1\right)\)

\(=\frac{-5}{7}\left(\frac{2}{11}+\frac{9}{11}-1\right)+1\)

\(=\frac{-5}{7}.0+1==0+1=1\)

\(3\frac{14}{19}+\frac{13}{17}+\frac{35}{43}+6\frac{5}{19}+\frac{8}{43}\)

\(\left(3\frac{14}{19}+6\frac{5}{19}\right)+\left(\frac{35}{43}+\frac{8}{43}\right)+\frac{13}{17}\)

\(10+1+\frac{13}{17}=11+\frac{13}{17}=11\frac{13}{17}\)

\(11\frac{3}{13}-\left(2\frac{4}{7}+5\frac{3}{13}\right)\)

\(=11\frac{3}{13}-2\frac{4}{7}-5\frac{3}{13}\)

\(=\left(11\frac{3}{13}-5\frac{3}{13}\right)-2\frac{4}{7}\)

\(=6-2-\frac{4}{7}\)

\(=4-\frac{4}{7}=3\frac{3}{7}\)

a) \(3\frac{14}{19}\)\(+\)\(\frac{13}{17}\)\(+\)\(\frac{35}{43}\)\(+\)\(6\frac{5}{19}\)\(+\)\(\frac{8}{43}\)

\(=\)\(\left(3\frac{14}{19}+6\frac{5}{19}\right)\)\(+\)\(\left(\frac{35}{43}+\frac{8}{43}\right)\)\(+\)\(\frac{13}{17}\)

\(=\)\(\left[\left(3+6\right)\left(\frac{14}{19}+\frac{5}{19}\right)\right]+1+\frac{13}{17}\)

\(=\)\(10+1+\frac{13}{17}\)

\(=\)\(11+\frac{13}{17}\)

\(=\)\(\frac{200}{17}\)

b) \(11\frac{3}{13}\)\(-\)\(\left(2\frac{4}{7}+5\frac{3}{13}\right)\)

\(=\)\(11\frac{3}{13}\)\(-\)\(2\frac{4}{7}\)\(-\)\(5\frac{3}{13}\)

\(=\)\(\left(11\frac{3}{13}-5\frac{3}{13}\right)\)\(-\)\(2\frac{4}{7}\)

\(=\)\(6\)\(-\)\(\frac{18}{7}\)

\(=\)\(\frac{24}{7}\)

Giúp Mik ik mai nộp oy

c. N= \(\frac{-5}{7}\cdot\left(\frac{2}{11}+\frac{9}{11}\right)+\frac{12}{7}\)

N=1

\(3\frac{14}{19}+\frac{13}{17}+\frac{35}{43}+6\)

\(=\frac{71}{19}+\frac{13}{17}+\frac{35}{43}+6\)

\(=\frac{1454}{323}+\frac{35}{43}+6\)

\(=5,...+6\)

\(=11,...\)

\(Bai2a\)\(A=\frac{\sqrt{3}-\sqrt{6}}{1-\sqrt{2}}-\frac{2+\sqrt{8}}{1+\sqrt{2}}\)

\(=\frac{\sqrt{3}\left(1-\sqrt{2}\right)}{1-\sqrt{2}}-\frac{2\left(1+\sqrt{2}\right)}{1+\sqrt{2}}\)

\(=\sqrt{3}-2\) 

\(VayA=\sqrt{3}-2\)

\(3\frac{14}{19}+\frac{13}{17}+\frac{35}{43}+6\frac{5}{19}+\frac{8}{43}\)

\(=3+6+\left(\frac{14}{19}+\frac{5}{19}\right)+\left(\frac{35}{43}+\frac{8}{43}\right)+\frac{13}{17}\)

\(=9+1+1+\frac{13}{17}\)

\(=11+\frac{13}{17}\)

\(=\frac{200}{17}\)