a) \(-\frac{1}{4}.13\frac{9}{11}-0,25.6\frac{2}{11}\)

\(=-\frac{1}{4}.13\frac{9}{11}-\frac{1}{4}.6\frac{2}{11}\)

\(=-\frac{1}{4}\left(13\frac{9}{11}+6\frac{2}{11}\right)\)

\(=-\frac{1}{4}.20\)

\(=-5\)

b) \(B=\frac{-5}{6}.\frac{4}{19}+\frac{-7}{12}.\frac{4}{19}-\frac{40}{57}\)

\(=\frac{4}{19}\left(\frac{-5}{6}+\frac{-7}{12}\right)-\frac{40}{57}\)

\(=\frac{4}{19}.\frac{-17}{12}-\frac{40}{57}\)

\(=\frac{-17}{57}-\frac{40}{57}\)

\(=-1\)

c)  \(\frac{3}{7}.\frac{9}{26}-\frac{1}{14}.\frac{1}{13}-\frac{1}{7}\)

\(=\frac{3}{7}.\frac{9}{26}-\frac{1}{2}.\frac{1}{7}.\frac{1}{13}-\frac{1}{7}\)

\(=\frac{1}{7}\left(3.\frac{9}{26}-\frac{1}{2}.\frac{1}{13}-1\right)\)

\(=\frac{1}{7}.0\)

\(=0\)

d) \(\frac{4}{9}:\left(-\frac{1}{7}\right)+6\frac{5}{9}:\left(-\frac{1}{7}\right)\)

\(=\left(\frac{4}{9}+6\frac{5}{9}\right):\left(-\frac{1}{7}\right)\)

\(=7:\left(-\frac{1}{7}\right)\)

\(=-49\)

\(A=-\frac{1}{4}x3\frac{9}{11}-0,25x6\frac{2}{11}\)

\(A=-0,25x3\frac{9}{11}-0,25x6\frac{2}{11}\)

\(A=-0,25x\left(\frac{9}{11}+\frac{2}{11}\right)\)

\(A=-0,25x1\)

\(A=-0,25\)

\(B=-\frac{5}{6}x\frac{4}{19}+-\frac{7}{12}x\frac{4}{19}-\frac{40}{57}\)

\(B=-\frac{5}{6}x\frac{4}{19}+-\frac{7}{12}x\frac{4}{19}-\frac{4}{19}x190\)

\(B=\frac{4}{19}x\left(-\frac{5}{6}-\frac{7}{12}-190\right)\)

\(B=\frac{4}{19}x\left(-\frac{2297}{12}\right)\)

\(B=\frac{-2297}{57}\)

\(C=\frac{3}{7}x\frac{9}{26}-\frac{1}{14}x\frac{1}{13}-\frac{1}{7}\)

\(C=\frac{1}{7}x3x\frac{9}{26}-\frac{1}{7}x\frac{1}{2}x\frac{1}{13}-\frac{1}{7}\)

\(C=\frac{1}{7}x\left(3x\frac{9}{26}-\frac{1}{2}x\frac{1}{13}-1\right)\)

\(C=\frac{1}{7}x0\)

\(C=\frac{1}{7}\)

\(D=\frac{4}{9}:\left(-\frac{1}{7}\right)+6\frac{5}{9}:\left(-\frac{1}{7}\right)\)

\(D=\left(\frac{4}{9}+6\frac{5}{9}\right):\left(-\frac{1}{7}\right)\)

\(D=7:\left(-\frac{1}{7}\right)\)

\(D=-49\)

A=\([\)\(\frac{2}{7}\)\(\times\)(\(\frac{1}{4}-\frac{1}{3}\))\(]\)\(\div\)\([\)(\(\frac{2}{7}\times\)(\(\frac{3}{9}-\frac{2}{5}\))\(]\)
  =(\(\frac{2}{7}\times\)\(\frac{-1}{12}\))\(\div(\)\(\frac{2}{7}\times\)\(\frac{-1}{15}\))
=\(\frac{-1}{42}\)\(\div\)\(\frac{-2}{35}\)
=\(\frac{-1}{42}\)\(\times\)\(\frac{35}{-2}\)
=\(\frac{5}{12}\)

\(a.\) \(\frac{4}{15}.\frac{7}{9}+\frac{4}{15}.\frac{2}{9}\)

\(=\frac{4}{15}\left(\frac{7}{9}+\frac{2}{9}\right)\)

\(=\frac{4}{15}.\frac{9}{9}\)

\(=\frac{4}{15}.1\)

\(=\frac{4}{15}\)

\(b.\) \(\frac{13}{19}.\frac{23}{11}-\frac{13}{19}.\frac{8}{11}-\frac{13}{19}.\frac{4}{11}\)

\(=\frac{13}{19}\left(\frac{23}{11}-\frac{8}{11}-\frac{4}{11}\right)\)

\(=\frac{13}{19}.\frac{11}{11}\)

\(=\frac{13}{19}.1\)

\(=\frac{13}{19}\)

a)4/15 x(7/9+2/9)=4/15x1=4/15

b)13/19x(23/11-8/11-4/11)13/19x1=13/19

A) \(\frac{4}{15}x\frac{7}{9}+\frac{4}{15}x\frac{2}{9}\)

\(=\frac{28}{135}+\frac{8}{135}\)

\(=\frac{36}{135}=\frac{4}{15}\)

B) \(\frac{13}{19}x\frac{23}{11}-\frac{13}{19}x\frac{8}{11}-\frac{13}{19}x\frac{4}{11}\)

\(=\frac{299}{209}-\frac{104}{209}-\frac{52}{209}\)

\(=\frac{143}{209}\)

a.5/6 - 26/5 X 1/13 = 13/30

b.( 19/23 - 22/46 ) X 23/46 = 3/23

c.25/8 x 14/30 = 35/24

d.( 3/4 x 5/7 ) x ( 20/9 x 14/15 ) = 10/9

e.4/35 x 25/32 x 38/24 = 95/672

g. 1/2 x 3/4 x 2/3 x 4/5 = 1/5

h.5/6 x 11/4 - 5/4 x 23/6 = -5/2

i.9/16 x 13/4 - 9/4 x 5/16 + 9/16 x 17/4 = 225/64

k.( 7 x 1/3 ) x ( 1/7 x 6 ) = 2

m.2/3 x ( 3/5 + 3/7 ) = 34/35

n.4/5 x ( 5/8 + 7/4 ) = 19/10

p.( 1/33 + 31/333 - 341/3333 ) x ( 1/2 - 1/3 - 1/6 ) = 0

mih giành cả nửa tiếng để giải đó , k nha

ghi ca cach lam nhe

có một số con nhân thì bạn rút gọn chéo , cộng trừ thì bn đổi chỗ các số hạng .Còn nếu như không đc thì bn tính thường thôi

\(=-\frac{5}{7}\cdot\left(\frac{2}{11}+\frac{9}{14}\right)+\frac{12}{7}\)

\(=-\frac{5}{7}\cdot\frac{127}{154}+\frac{12}{7}\)

\(=-\frac{635}{1078}+\frac{12}{7}=\frac{1213}{1078}\)

kt lại đề bài xem hình như sai ở đâu mà số to thế

=-5/7.(2/11+9/14)+1 5/7

=-5/7.127/154+12/7

=635/1078+12/7

=2483/1078

MK ko chắc nữa nha

Sai đề bạn ơi , phải là :

\(C=-\frac{5}{7}.\frac{2}{7}+-\frac{5}{7}.\frac{9}{11}+1\frac{5}{7}\)

\(C=-\frac{5}{7}.\left(\frac{2}{11}+\frac{9}{11}\right)+\frac{12}{7}\)

\(C=-\frac{5}{7}.1+\frac{12}{7}\)

\(C=-\frac{5}{7}+\frac{12}{7}\)

\(\Rightarrow C=1\)

Vậy C=1

Hok_Tốt

#Thiên_Hy

a) \(\frac{1}{3}.\frac{-6}{13}.\frac{-9}{10}.\frac{-13}{36}\)

\(=\left(\frac{1}{3}.\frac{-9}{10}\right)\left(\frac{-6}{13}.\frac{-13}{36}\right)\)

\(=\frac{-3}{10}.\frac{1}{6}\)

\(=\frac{-1}{20}\)

b) \(\frac{-1}{3}.\frac{-15}{17}.\frac{34}{45}\)

\(=\frac{-1}{3}.\frac{-2}{3}\)

\(=\frac{2}{9}\)

c) \(\left(1-\frac{1}{5}\right)\left(\frac{-3}{10}+\frac{1}{5}\right)\)

\(=\frac{4}{5}.\frac{-1}{10}\)

\(=\frac{-2}{25}\)

d) \(A=\frac{1}{3}.\frac{4}{5}+\frac{1}{3}.\frac{6}{5}+\frac{2}{3}\)

\(=\frac{1}{3}\left(\frac{4}{5}+\frac{6}{5}\right)+\frac{2}{3}\)

\(=\frac{1}{3}.2+\frac{2}{3}\)

\(=\frac{2}{3}+\frac{2}{3}\)

\(=\frac{4}{3}\)

e)  \(11\frac{1}{4}-\left(2\frac{5}{7}+5\frac{1}{4}\right)\)

\(=\left(11\frac{1}{4}-5\frac{1}{4}\right)-2\frac{5}{7}\)

\(=6-2\frac{5}{7}\)

\(=5\frac{7}{7}-2\frac{5}{7}\)

\(=3\frac{2}{7}\)

-377 / 70

ick mình

Phải làm đúng mới k

\(\frac{3}{7}.\frac{9}{26}-\frac{1}{14}.\frac{1}{13}+\frac{6}{7}\)

=\(\frac{3}{7}.\frac{9}{26}-\frac{1}{26}.\frac{1}{7}+\frac{6}{7}\)

=\(\frac{1}{7}.\frac{27}{26}-\frac{1}{26}.\frac{1}{7}+6.\frac{1}{7}\)

=\(\frac{1}{7}.\left(\frac{27}{26}-\frac{1}{26}+6\right)\)

=\(\frac{1}{7}.7\)

=1

a,\(\frac{21}{25}.\frac{11}{9}.\frac{5}{7}=\frac{21.11.5}{25.9.7}=\frac{3.7.11.5}{5^2.3^2.7}=\frac{11}{5.3}=\frac{11}{15}\)

b,\(\frac{5}{23}.\frac{17}{26}+\frac{5}{23}.\frac{9}{26}=\frac{5}{23}.\left(\frac{17}{26}+\frac{9}{26}\right)=\frac{5}{23}.1=\frac{5}{23}\)

c, \(\left(\frac{3}{29}-\frac{1}{5}\right).\frac{29}{3}=\frac{3}{29}.\frac{29}{3}-\frac{1}{5}.\frac{29}{3}=1-\frac{29}{15}=-\frac{14}{15}\)

a , \(\frac{21}{25}\times\frac{11}{9}\times\frac{5}{7}\) 

\(=\frac{21\times11\times5}{25\times9\times7}\)

\(=\frac{3\times7\times11\times5}{5\times5\times3\times3\times7}\) 

\(=\frac{11}{5\times3}\) 

\(=\frac{11}{15}\) 

b ,   \(\frac{5}{23}\times\frac{17}{26}+\frac{5}{23}\times\frac{9}{26}\) 

\(=\frac{5}{23}\times\left(\frac{17}{26}+\frac{9}{26}\right)\)

\(=\frac{5}{23}\times\frac{26}{26}\) 

\(=\frac{5}{23}\times1\) 

\(=\frac{5}{23}\) 

c , \(\left(\frac{3}{29}-\frac{1}{5}\right)\times\frac{29}{3}\) 

\(=\frac{3}{29}\times\frac{29}{3}-\frac{1}{5}\times\frac{29}{3}\) 

\(=1-\frac{29}{15}\)