Thuc hien phep tinh
(x-\(\frac{1}{2}\))(2x-1)
Những câu hỏi liên quan
thuc hien phep tinh :
\(\frac{1}{x-1}-\frac{x^3-x}{x^2+1}\left(\frac{1}{x^2-2x+1}+\frac{1}{1-x^2}\right)\)
thuc hien phep tinh:1/(x-1)-(x^3-x)/(x^2+1).(1/(x^2-2x+1)+1/(1-x^2))
1) thuc hien phep tinh:
\(\frac{4}{x+2}+\frac{2}{x-2}+\frac{5x-6}{4-x}\)
Ta có :\(\frac{4}{x+2}+\frac{2}{x-2}+\frac{5x-6}{4-x}\)
\(=\frac{4\left(x-2\right)\left(4-x\right)}{\left(x+2\right)\left(x-2\right)\left(4-x\right)}+\frac{2\left(x+2\right)\left(4-x\right)}{\left(x+2\right)\left(x-2\right)\left(4-x\right)}\)\(+\frac{\left(5x-6\right)\left(x+2\right)\left(x-2\right)}{\left(x+2\right)\left(x-2\right)\left(4-x\right)}\)
\(=\frac{24x-8x^2-32}{\left(x+2\right)\left(x-2\right)\left(4-x\right)}+\frac{4x-2x^2+16}{\left(x+2\right)\left(x-2\right)\left(4-x\right)}\)\(+\frac{5x^2+4x-12}{\left(x+2\right)\left(x-2\right)\left(4-x\right)}\)
\(=\frac{24x-8x^2-32+4x-2x^2+16+5x^2+4x-12}{\left(x+2\right)\left(x-2\right)\left(4-x\right)}\)
\(=\frac{32x-5x^2-28}{\left(x+2\right)\left(x-2\right)\left(4-x\right)}\)
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thuc hien phep tinh \(\frac{4x-8}{x+5}\)* \(\frac{25-x^2}{2x-x^2}\)
\(\frac{4x-8}{x+5}\)* \(\frac{25-x^x}{2x-x^2}\)
\(=\)\(\frac{4\left(x-2\right)\left(5-x\right)\left(5+x\right)}{\left(x+5\right)x\left(2-x\right)}\)
\(=\)\(\frac{-4\left(5-x\right)}{x}\)\(=\)\(\frac{x-20}{x}\)
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1) Thuc hien phep tinh cong 2 phan thuc \(\dfrac{2x}{x^2-2x+1}+\dfrac{x+1}{x-1}\) duoc ket qua la:
A. \(\dfrac{x^2+2x+1}{\left(x-1\right)^2}\) B. \(\dfrac{x^2+2x-1}{\left(x-1\right)^2}\) C. \(\dfrac{x^2-x-1}{\left(x-1\right)^2}\) D. \(\dfrac{x^2-2x-1}{\left(x-1\right)^2}\)
Thuc hien phep tinh
(2x-3)3-(2x-1)2x(2x+1)+3(x-9) (x-2)3-(x-1)x(x+1)-13x
khó quá!
mà x có giá trị là mấy vậy bạn!
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có BẠN NÀO ĐỒNG TÌNH VỚI MÌNH KO THÌ XIN CHO TÍCH ĐI
AZÔ!!!!!!!
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\(\frac{4x-8}{x+5}\)* \(\frac{25-^2}{2x-^2}\)thuc hien phep tinh nay ai giai giup mk vs
1.Thuc hien phep tinh sau:
a,(3x^2-4x+5)(2x^2-4)-2x(3x^3-4x^2+8)
b,(1-3x+x^2)(2-4x)+2x(2x^2+5)
a ) \(\left(3x^2-4x+5\right)\left(2x^2-4\right)-2x\left(3x^3-4x^2+8\right)\)
\(=\left(3x^2-4x+5\right).2x^2-4\left(3x^2-4x+5\right)-6x^4+8x^3-16x\)
\(=6x^4-8x^3+10x^2-12x^2+16x-20-6x^4+8x^3-16x\)
\(=\left(6x^4-6x^4\right)+\left(8x^3-8x^3\right)-\left(12x^2-10x^2\right)+\left(16x-16x\right)-20\)
\(=-2x^2-20\)
b ) \(\left(1-3x+x^2\right)\left(2-4x\right)+2x\left(2x^2+5\right)\)
\(=2\left(1-3x+x^2\right)-4x\left(1-3x+x^2\right)+4x^3+10x\)
\(=2-6x+2x^2-4x+12x^2-4x^3+4x^3+10x\)
\(=\left(4x^3-4x^3\right)+\left(12x^2+2x^2\right)+\left(10x-6x-4x\right)+2\)
\(=14x^2+2\)
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Thuc hien phep tinh
1) \(\frac{1}{x+2}+\frac{3}{x^2-4}+\frac{x-14}{\left(x^2+4x+4\right).\left(x-2\right)}\)
2) \(\frac{x+1}{x-3}-\frac{1-x}{x+3}-\frac{2x.\left(1-x\right)}{9-x^2}\)