rút gọn biểu thức
a) A=16^8 -1/(2+1)(2^2+1)(2^4+1)(2^8+1(3^16+1)
b) B=(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)/9^16-1
giúp mk vs ah mk đang cần gấp ah
Bài 1:Tính:
a)(1/27.x^3-y^3)
b)(2x^2-3y^3)
bài 2:Rút gọn biểu thức:
a)(6x+1)^2+(6x-1)^2-2.(1+6x).(1+6x)
b)3(2^2+1).(2^2-1).(2^8+1).(2^16+1)
c)C=12(5^2+1).(5^4+1).(5^8+1).(5^16+1)
giúp mk vx, mk cần gấp...T^T
Bài 1 không có cơ sở để tính biểu thức.
Bài 2:
a.
$(6x+1)^2+(6x-1)^2-2(6x+1)(6x-1)$
$=[(6x+1)-(6x-1)]^2=2^2=4$
b.
$3(2^2+1)(2^4+1)(2^8+1)(2^{16}+1)$
$=(2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^{16}+1)$
$=(2^4-1)(2^4+1)(2^8+1)(2^{16}+1)$
$=(2^8-1)(2^8+1)(2^{16}+1)$
$=(2^{16}-1)(2^{16}+1)=2^{32}-1$
c.
$2C=(5^2-1)(5^2+1)(5^4+1)(5^8+1)(5^{16}+1)$
$=(5^4-1)(5^4+1)(5^8+1)(5^{16}+1)$
$=(5^8-1)(5^8+1)(5^{16}+1)$
$=(5^{16}-1)(5^{16}+1)=5^{32}-1$
$\Rightarrow C=\frac{5^{32}-1}{2}$
Các bạn giúp mk vs ak mk đag cần gấp lắm
Rút gọn biểu thức : a) (3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)
b) 2x(2x-1)^2 - 3x(x+3)(x-3) - 4x(x+1)^2
rút gọn các biểu thức sau:
a \(\sqrt[3]{8\sqrt{5}-16}.\sqrt[3]{8\sqrt{5}+16}\)
b \(\sqrt[3]{7-5\sqrt{2}}-\sqrt[6]{8}\)
c \(\sqrt[3]{4}.\sqrt[3]{1-\sqrt{3}}.\sqrt[6]{4+2\sqrt{3}}\)
d \(\dfrac{2}{\sqrt[3]{3}-1}-\dfrac{4}{\sqrt[3]{9}-\sqrt[3]{3}+1}\)
`c)root{3}{4}.root{3}{1-sqrt3}.root{6}{(sqrt3+1)^2}`
`=root{3}{4(1-sqrt3)}.root{3}{1+sqrt3}`
`=root{3}{4(1-sqrt3)(1+sqrt3)}`
`=root{3}{4(1-3)}=-2`
`d)2/(root{3}{3}-1)-4/(root{9}-root{3}{3}+1)`
`=(2(root{3}{9}+root{3}{3}+1))/(3-1)-(4(root{3}{3}+1))/(3+1)`
`=root{3}{9}+root{3}{3}+1-root{3}{3}-1`
`=root{3}{9}`
`a)root{3}{8sqrt5-16}.root{3}{8sqrt5+16}`
`=root{3}{(8sqrt5-16)(8sqrt5+16)}`
`=root{3}{320-256}`
`=root{3}{64}=4`
`b)root{3}{7-5sqrt2}-root{6}{8}`
`=root{3}{1-3.sqrt{2}+3.2.1-2sqrt2}-root{6}{(2)^3}`
`=root{3}{(1-sqrt2)^3}-sqrt2`
`=1-sqrt2-sqrt2=1-2sqrt2`
Bài 1: tính giá trị biểu thức
a) 6/7 + 5/8 : 5 - 3/16 .(-2) ^2
b) 2/3 + 1/3 . ( - 4/9 + 5/6) : 7/12
giúp mk vs mk đg cần gấp
6/7+5/8÷5-3/16×(-2)²
=6/7+1/8-3/4
=55/56-3/4
=13/56
b.2/3 + 1/3.( -4/9 + 5/6 ) : 7/12
=2/3 + 1/3. ( -8/18 + 15/18 ) : 7/12
=2/3 + 1/3 . 7/18 : 7/12
=2/3 + 7/54 : 7/12
= 2/3 + 2/9
=6/9 + 2/9
= 8/9
rút gọn biểu thức sau :
( 3 + 1 ) x ( 3^2 + 1 ) x ( 3^4 + 1 ) x ( 3^8 +1 ) x ( 3^16 +1 ) x ( 3^32 +1 ) x ( 3^64 +1 )
các bạn giúp mk vs nhé ! cảm ơn nhiều !!!
Đặt biểu thức đã cho là A.
Ta có: 2A = (3 - 1) * (3 + 1) * (3^2 + 1) * .... * (3^64 + 1)
= (3^2 - 1) * (3^2 + 1) * ... * (3^64 + 1) (hằng đẳng thức a^2 - b^ 2 = (a+b)(a-b))
Rút gọn triệt tiêu ta được 2A=3^64 - 1
=> A = (3^64 - 1)/2
Rút gọn: A = 8( 3^2 + 1)(3^4 + 1)(3^8 + 1)(3^16 + 1) - 81^16.
\(A=8\left(3^2+1\right)\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)-81^{16}\)
\(A=\left(3^2-1\right)\left(3^2+1\right)\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)-81\)
\(A=\left(3^4-1\right)\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)-81^{16}\)
\(A=\left(3^8-1\right)\left(3^8+1\right)\left(3^{16}+1\right)-81^{16}\)
\(A=\left(3^{16}-1\right)\left(3^{16}+1\right)-81^{16}\)
\(A=3^{32}-1-81^{16}\)
A = 8.( 32 + 1 ).( 34 + 1 ).( 38 + 1).( 316 + 1 ) - 8116
A = ( 32 - 1).( 32 + 1 ).( 34 + 1 ).( 38 + 1).( 316 + 1 ) - 8116
A = ( 34 - 1 ).( 34 + 1 ).( 38 + 1).( 316 + 1 ) - 8116
A = ( 38 - 1 ).( 38 + 1).( 316 + 1 ) - 8116
A = ( 316 - 1 ).( 316 + 1 ) - 8116
A = ( 332 - 1 ) - 8116
A = -364
Rút gọn biểu thức:
a) (x-2)(x^2-2x+4)(x+2)(x^2+2x+4)
b)(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)
Chứng minh rằng: a)\(\frac{1}{2}-\frac{1}{4}+\frac{1}{8}-\frac{1}{16}+\frac{1}{32}-\frac{1}{64}< \frac{1}{3}\)
b)\(\frac{1}{3}-\frac{2}{3^2}+\frac{3}{3^3}-\frac{4}{3^4}+...+\frac{99}{3^{99}}-\frac{100}{3^{100}}< \frac{3}{16}\)
Nhanh lên nhé! Mk đang cần gấp.
\(3B=1-\frac{2}{3}+\frac{3}{3^2}-\frac{4}{3^3}+...+\frac{99}{3^{98}}-\frac{100}{3^{99}}\)
\(B=\frac{1}{3}-\frac{2}{3^2}+\frac{3}{3^3}-\frac{4}{3^4}+...+\frac{99}{3^{99}}-\frac{100}{3^{100}}\)
\(\Rightarrow4B=3B+B=1-\frac{1}{3}+\frac{1}{3^2}-\frac{1}{3^3}+...+\frac{1}{3^{98}}-\frac{1}{3^{99}}-\frac{100}{3^{100}}\)
+ Đặt \(M=1-\frac{1}{3}+\frac{1}{3^2}-\frac{1}{3^3}+...+\frac{1}{3^{98}}-\frac{1}{3^{99}}\)
\(3M=3-1+\frac{1}{3}-\frac{1}{3^2}+...+\frac{1}{3^{97}}-\frac{1}{3^{98}}\)
\(\Rightarrow4M=3M+M=3-\frac{1}{3^{99}}\)
\(\Rightarrow M=\frac{3}{4}-\frac{1}{3^{99}\cdot4}\)
\(\Rightarrow4B=M-\frac{100}{3^{100}}=\frac{3}{4}-\frac{1}{3^{99}\cdot4}-\frac{100}{3^{100}}\)
\(\Rightarrow B=\frac{3}{16}-\frac{1}{3^{99}\cdot16}-\frac{100}{3^{100}\cdot4}\) \(\Rightarrow B< \frac{3}{16}\)
a) \(2A=1-\frac{1}{2}+\frac{1}{2^2}-\frac{1}{2^3}+\frac{1}{2^4}-\frac{1}{2^5}\)
\(A=\frac{1}{2}-\frac{1}{2^2}+\frac{1}{2^3}-\frac{1}{2^4}+\frac{1}{2^5}-\frac{1}{2^6}\)
\(\Rightarrow3A=2A+A=1-\frac{1}{2^6}\)
\(\Rightarrow A=\frac{1}{3}-\frac{1}{2^6\cdot3}< \frac{1}{3}\) ( đpcm )
Tính giá trị của biểu thức:
B=1+1/2(1+2)+1/3(1+2+3)+....+1/16(1+2+3+...+16)
Giúp mk với ! Mk đang cần gấp ,thank nhìu