Tính tHUẬN TIỆN :
63*(19191919 +88888)
21212121+99999
hAI DAU CỘNG GỘP THÀNH 1 NHA
tính nhanh 18.(19191919/21212121 + 88888/99999)
18 x [19191919/21212121 + 88888/99999] = ?
= 18 x \(\left(\frac{19.1010101}{21.1010101}+\frac{8.11111}{9.11111}\right)\)= 18 x ( \(\frac{19}{21}+\frac{8}{9}\)) = 9 x 2 ( \(\frac{57+56}{63}\))
= 9 x 2 x \(\frac{113}{63}\)=\(\frac{226}{7}\)
18 x (19191919/21212121 + 88888/99999)=?
\(=18x\frac{19x1010101}{21x1010101}+\frac{8x11111}{9x11111}=18x\frac{19}{21}+\frac{8}{9}\)
sao khong có kết quả hả bạn
\(18\cdot\left(\frac{19191919}{21212121}+\frac{88888}{99999}\right)\)
\(=18\cdot\left(\frac{19}{21}+\frac{8}{9}\right)\)
\(=18\cdot\frac{113}{63}\)
\(=\frac{678}{21}\approx32,286\)
18x(19191919/21212121+88888/99999)
Bạn hãy tính bằng cách nhanh nhất (GIẢI CÁCH LÀM)
18 x ( 19 x 1010101 / 21 x 1010101 + 8 x 11111/ 9x 11111)
= 18 x ( 19/21 + 8/9 )
= 18 x 19 / 21 + 18 x 8/9
= 6x3x19/7x3 + 9x2x8/9 = 6x19/7 + 16
= 226/7
tính nhanh :
18 x \(\left(\frac{19191919}{21212121}\ +\ \frac{88888}{99999}\ \right)\)
Tính nhanh:
a) 2006 x 2005 - 1 / 2004 x 2006 + 2005
b) 18 x ( 19191919 / 21212121 + 88888 / 99999 )
\(18\times\left(\frac{19191919}{21212121}+\frac{88888}{99999}\right)=?\)
\(=18\times\left(\frac{19}{21}+\frac{8}{9}\right)=18\times\frac{113}{63}=\frac{226}{7}\)
\(18\cdot\left(\frac{19191919}{21212121}+\frac{88888}{99999}\right)\)
\(18.\left(\frac{19191919}{21212121}+\frac{88888}{99999}\right)=18.\left(\frac{19}{21}+\frac{8}{9}\right)=18.\frac{113}{63}=\frac{226}{7}nha!!!!!\)
Tinh nhanh:
a, 1/2+1/4+1/8+1/16+1/32+1/64+1/128
b,18-(19191919 / 21212121+ 88888/ 99999)
Câu a:Đáp số 127/128
Câu b:Đáp số 1021/63
a) Đặt A= 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128 + 1/256
2A= 2(1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128 + 1/256)
= 1+1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128
=>A = 2A-A =1+1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128 -1/2 - 1/4 - 1/8 - 1/16 - 1/32 - 1/64 - 1/128 - 1/256
=1-1/256
=255/256
b) = 18 - (19/21 + 8/9) = 18 - 113/63 = 1021/63
a) Đặt A= 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128 + 1/256
2A= 2(1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128 + 1/256)
= 1+1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128
=>A = 2A-A =1+1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128 -1/2 - 1/4 - 1/8 - 1/16 - 1/32 - 1/64 - 1/128 - 1/256
=1-1/256
=255/256
b) sai đề