(2 x - 3) - (x + 2) = ( x - 2)-3(x - 5)

\(\Leftrightarrow\)2x - 3 - x - 2 = x - 2 - 3x + 15

\(\Leftrightarrow\)x - 5 = 13 - 2x

\(\Leftrightarrow\)3x = 18

\(\Leftrightarrow\)x = 6

  Vậy x = 6 là giá trị cần tìm

sai đề hay sao ý tính ra lẻ

x/3 - 4/9 = 1/5

=> x/3 = 1/5 + 4/9

=> x/3 = 29/45

=> 15x/45 = 29/45

=> 15x = 29

=> x = 29/15

x/3 - 4/9 = 1/5

x/3 = 1/5 + 4/9

x/3 = 29/45

15x/49 = 29/45

15x = 29

x = 29/15

các số nguyên x thỏa mãn là:11,12,13,14

|-3|+|-7|<_x<_|-3|.|5|

= 3+7<_x<_3.5

=10<_x<_15

vậy x =11; 12 ;13 ;14

1. Tìm x

a) 1+2+3+...+x = 210

=> \(\frac{x\left(x+1\right)}{2}=210\)

=> x = 20

b) \(32.3^x=9.3^{10}+5.27^3\)

=>\(32.3^x=9.3^{10}+5.3^9\)(\(27^3=\left(3^3\right)^3=3^9\))

=>\(32.3^x=9.3.3^9+5.3^9\)

=>\(32.3^x=3^9\left(9.3+5\right)\)

=>\(32.3^x=3^9.32\)

=>x = 9

2.

Ta có 2A = 3A - A

=> 2A = \(3\left(1+3+3^2+3^3+....+3^{10}\right)\)\(-\)\(1-3-3^2-3^3-....-3^{10}\)

=> 2A = \(3+3^2+3^3+.....+3^{11}-\)\(1-3-3^2-3^3-...-3^{10}\)

=> 2A = \(3^{11}-1\)

=> 2A+1 = \(3^{11}-1+1\)=\(3^{11}\)

=> n = 11

Ta có : a)1 + 2 + 3 + ... + x = 210

=> \(\frac{x\left(x+1\right)}{2}=210\)

=> x(x + 1) = 420

=> x(x + 1) = 20.21

=> x = 20

1/ 

a) \(1+2+3+...+x=210\)

\(\Rightarrow\frac{x.\left(x+1\right)}{2}=210\)

\(\Rightarrow x.\left(x+1\right)=210.2=420\)

\(\Rightarrow x^2+x=420\)

\(\Rightarrow x^2+x=400+20=20^2+20\Leftrightarrow x=20\)

b) \(32.3^x=9.3^{10}+5.27^3\)

\(\Rightarrow32.3^x=629856\)

\(\Rightarrow3^x=629856:32=19683=3^9\)

\(\Rightarrow x=9\)

2/

\(A=1+3+3^2+3^3+...+3^{10}\)

\(\Rightarrow A=3^0+3^1+3^2+3^3+...+3^{10}\)

\(\Rightarrow A=\frac{3^{10+1}-1}{3-1}=88573\)

Tìm n:

\(2.A+1=3^n\Rightarrow2.88573+1=3^n\)

\(\Rightarrow177147=3^n\Leftrightarrow3^{11}=3^n\Leftrightarrow n=11\)

(x+3)³:3-1=-10

(x+3)³:3=1-10

(x+3)³:3=-9

(x+3)³=(-9).3

(x+3)³=-27

(x+3)³=3³

x+3=3

x=3-3

x=0

Ta có : ( x + 3 ) ³ : 3  - 1 = -10

<=> (  x + 3 ) ³ : 3            = ( -10 ) + 1 

<=> ( x + 3 ) ³  : 3            = ( -9)

<=> ( x + 3 )³                    =(- 9 ) . 3 

<=> ( x + 3 )³                   = (-27 )

<=> x + 3                          = (-3)

<=> x                                 = ( - 3) - 3

<=> x                                 = -6

Vậy x = -6

(x + 3)³ : 3 - 1 = -10

(x - 3)³  : 3      = -10 + 1

(x - 3)³  : 3      = -9

(x - 3)³            = -9 x 3

(x - 3)³            = -27

(x - 3)³            = -3³

 x - 3               = -3

 x                    = -3 + 3

x                     = 0

Vậy x = 0

\(\left|x-1\right|+\left|y+2\right|+\left|z-3\right|=0\)

Ta có: \(\hept{\begin{cases}\left|x-1\right|\ge0\forall x\\\left|y+2\right|\ge0\forall x\\\left|z-3\right|\ge0\forall x\end{cases}\Rightarrow\left|x-1\right|+\left|y+2\right|+\left|z-3\right|\ge0\forall x;y;z}\)

Mà \(\left|x-1\right|+\left|y+2\right|+\left|z-3\right|=0\)

\(\hept{\begin{cases}\left|x-1\right|=0\\\left|y+2\right|=0\\\left|z-3\right|=0\end{cases}}\Leftrightarrow\hept{\begin{cases}x=1\\y=-2\\z=3\end{cases}}\)

Vậy \(x=1;y=-2;z=3\)

10^x:5^y=20^y

=>2^x.5^x:5^y=4^y.5^y

=>2^x.5^x-y=2^2y.5^y

=>x=2y:x-y=y

=>x=2y

vậy x=2y  ;   y=x:2

bạn ko biết câu a àk?

bạn ơi ý a còn điều kiện x+y=6

a, \(\left(3x-5\right)\left(x+1\right)-\left(3x-1\right)\left(x+1\right)=x-4\)

\(\Leftrightarrow\left(x+1\right)\left(3x-5-3x+1\right)=x-4\Leftrightarrow-4\left(x+1\right)=x-4\)

\(\Leftrightarrow-4x-4=x-4\Leftrightarrow-4x-x=0\Leftrightarrow x=0\)

b, \(\left(x-2\right)\left(x+3\right)-\left(x+4\right)\left(x-7\right)=5-x\)

\(\Leftrightarrow x^2+x-6-x^2-3x+28=5-x\Leftrightarrow-2x+22=5-x\Leftrightarrow x=17\)

c,  thiếu đề 

d, \(3\left(x-7\right)\left(x+7\right)-\left(x-1\right)\left(3x+2\right)=13\)

\(\Leftrightarrow3x^2-147-3x^2+x+2=13\Leftrightarrow x=11+147=158\)

a.\(3x^2-2x-5-\left(3x^2+2x-1\right)=x-4\)

\(\Leftrightarrow-5x=0\Leftrightarrow x=0\)

b.\(x^2+x-6-\left(x^2-3x-28\right)=5-x\)

\(\Leftrightarrow5x=-17\Leftrightarrow x=-\frac{17}{5}\)

c.\(5\left(x^2-10x+21\right)-\left(5x^2-9x-2\right)=0\)

\(\Leftrightarrow-41x+107=0\Leftrightarrow x=\frac{107}{41}\)

d.\(3\left(x^2-49\right)-\left(3x^2-x-2\right)=13\Leftrightarrow x=158\)

sửa dòng 2 phần b ;-; 

\(x^2+x-6-x^2+3x+28=5-x\)

\(\Leftrightarrow4x+22=5-x\Leftrightarrow5x=-17\Leftrightarrow x=-\frac{17}{5}\)