-(a+b-c+d)+(a-b-c-d)=-a-b+c-d+a-b-c-d=(-a+a)-(b+b)+(c-c)-(d+d)=0-2b+0-2d=-2b+(-2)d=-2(b+d)

 -(a+b-c+d)+(a-b-c-d)

= -a-b+c-d+a-b-c-d

= -2b-2d

Nhấn đúng cho mk nha!!!!!!!!!!!

(a+b-c)+(a-b+c)-(b+c-a)-(a-b-c)

= a + b - c + a - b + c - b - c + a - a + b + c

= ( a - a ) + ( b - b ) - ( c - c ) + ( a + a ) - ( b + b ) + ( c + c )

=     0      +      0     -      0    +      2a    -      2b    +      2c

=               2a - 2b + 2c

 (a+b) . (c+d) - (a+d). (b+c)

=(a+b)c+(a+b)d-(a+d)b+[-(a+d)c]

=ac+bc+ad+bd-ab-db-ac-dc

=(ac-ac)+(bd-db)+bc+ad-ab-dc

=0+0+bc+ad-ab-dc

=bc+ad-ab-dc

=(ad-ab)-(dc-bc)

=a(d-b)-c(d-b)

=(d-b).(a-c)

nhớ ủng hộ cho mình 1 đúng nhe

\(\text{-(a+b)-(b-c)-(a+c) }\)

\(-a-b-b+c-a-c\)

\(=-2a-2b\)

Đó là câu 1

Học tốt

\(-\left(a+b\right)-\left(b-c\right)-\left(a+c\right)=-a+b-b+c-a-c\)

\(=-2a\)

2\(-\left(-2a+b\right)+\left(b-c\right)-\left(-c+a\right)\)

\(=2a-b+b-c+c-a\)

\(=a\)

\(\text{1,-(a+b)-(b-c)-(a+c)= -a-b-b+c-a-c=-2a-2b }\)

\(\text{2,-(-2a-b)+(b-c)-(-c+a)}=2a+b+b-c+c-a=a+2b\)

- (a + b - c) + (b - c + d) - (-a + b + d)

= -a -b + c + b - c + d + a - b - d

= -b 

a) - ( - a + c – d ) – ( c – a + d ) 

= a - c - d - c + a + d

= (a + a) + (-c - c) + (-d + d)

= 2a - 2c               

b) – ( a + b  - c + d ) + ( a – b – c –d )

= - a - b + c - d + a - b - c - d

= (-a + a) + (-b - b) + (c - c) + (-d - d)

= -2b - 2d

a) - ( - a + c - d) - ( c - a + d )

= a - c + d - c + a - d 

= 2a

b) - ( a+ b - c + d ) + ( a -b -c -d )

= - a-b+c-d+a-b-c-d

=-2d -2b

c) a(b-c-d) - a(b+c-d)

= a(b-c-d-b-c+d)

= ab-ac-ad-ab-ac+ad

= -2ab-2ac

d) (a+b)(c+d)-(a+d)(b+c)

= ac+ad+bc+bd - (ab+ac+bd+cd)

= ac+ad+bc+bd-ab-ac-bd-cd

=ad+bc-ab-cd

a) - ( - a + c - d) - ( c - a + d )

= a - c + d - c + a - d 

= 2a

b) - ( a+ b - c + d ) + ( a -b -c -d )

= - a-b+c-d+a-b-c-d

=-2d -2b

c) a(b-c-d) - a(b+c-d)

= a(b-c-d-b-c+d)

= ab-ac-ad-ab-ac+ad

= -2ab-2ac

d) (a+b)(c+d)-(a+d)(b+c)

= ac+ad+bc+bd - (ab+ac+bd+cd)

= ac+ad+bc+bd-ab-ac-bd-cd

=ad+bc-ab-cd

e)(a+b)(c-d)-(a-b)(c+d)

= ac-ad+bc-bd-ac-ad+bc+bd

= 2bc-2ad

f) ( a + b )² – ( a – b )²

= a²+2ab+b² - (a²+2ab-b²)

=a²+2ab+b² - a²-2ab+b²

=2b²

1) -a(-a+c-d)-(c-a+d)

=ad-ac+a²-c+a-d

2) -(a+b)-(c+d)+(a-b-c-d)

=-a-b-c-d+a-b-c-d

=-2b-2c-2d

3) a(b-c-a)-a(b+c-d)

=-ac+ab-a²+ad-ac-ab

=ad-2ac-a²

\(-\left(a+c-d\right)-\left(c-a+d\right)\)

=\(-a-c+d-c+a-d\)

=\(\left(-a+a\right)-\left(c-c\right)+\left(d-d\right)\)

=\(0-0+0\)

\(=0\)

-(a+c-d)-(c-a+d)

=-a-c+d-c+a-d

= -2c

Đ/s : -2c

--(a+c-d)-(c-a+d)

=-a -c+d-c+a-d

=(-a+a)+(d-d)-(c+c)

=-2c