[(-20,83) . 0,2 + (-9,17) . 0,2] : [2,47 . 0,5 -(-3,53) . 0,5]
  =[0,2 . (-20,83 + (-9,17))] : [0,5 . (2,47 -(-3,53)]
  =[0,2 . (-30)] : [0,5 . 6]
  = -6 : 3 = -2

vào câu hỏi tương tự

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câu hỏi tương tự thì chỉ có 1 câu thôi

câu hỏi tương tự Nguyễn Trung Hiếu lại xin lik-e kìa

a) (-2,5 . 0,38 . 0,4) - [0,125 . 3,15 . (-8)]
  =[-2.5 . 0,4 . 0,38] - [-8 . 0,125 . 3,15 ]
  =(-1 . 0,18) - (-1 . 3,15)
  = -0,18 - (-3,15) = 0,567
b) [(-20,83) . 0,2 + (-9,17) . 0,2] : [2,47 . 0,5 -(-3,53) . 0,5]
  =[0,2 . (-20,83 + (-9,17))] : [0,5 . (2,47 -(-3,53))]
  =[0,2 . (-30)] : [0,5 . 6]
  = -6 : 3 = -2

a) (-2,5. 0,38. 0, 4) - ( 0,125. 3,15. (-8))

=((-2,5.0,4).0,38) - ((-8.0,125).3,15)

= ((-1).0,38) - ((-1).3,15)

= -0,38 - (-3,15)  

= 2.77

b)  ((-20,83) .0,2 + (-9,17).0,2) : ( 2,47.0,5 - (-3,53).0,5)

= ((-20,83 - 9,17).0,2) : ((2,47 + 3,53).0,5)

= (-6) : 3

= -2

a, ( -2,5.0,38.0,4) - [0,125.3,15.(-8)

    =[(-2,5).0,4].0,38-[0,125.(-8)].3,15

    =(-1).0,38-(-1).3,15

    =(-0,38)+3,15

    =2,77

b,[(-20,83).0,2+(-9,17).0,2] : [2,47.0,5-(-3,53).0,5 ]

   ={[(-20,83)+(-9,17)].0,2}:[2,47.0,5-3,53.0,5]

   ={0,2.30}:[(2,47-3,53).0,5]

   =6:[(-1,06).0,5]

   =6:-0,53

    =\(-\frac{600}{53}\)

a) (-2,5. 0,38. 0, 4) - ( 0,125. 3,15. (-8))

=((-2,5.0,4).0,38) - ((-8.0,125).3,15)

= ((-1).0,38) - ((-1).3,15)

= -0,38 - (-3,15)

= 2.77

b) ((-20,83) .0,2 + (-9,17).0,2) : ( 2,47.0,5 - (-3,53).0,5)

= ((-20,83 - 9,17).0,2) : ((2,47 + 3,53).0,5)

= (-6) : 3

= -2

a)\(\left(-2,5.0,38.0,4\right)-\left[0,125.3,15\left(-8\right)\right]\)

\(=-20.0,125.0,38.0,4-0,125.3,15\left(-20\right).0,4\)

\(=-20.0,125.0,4\left(0,38-3,15\right)\)

\(=-1\left(-2,77\right)=2,77\)

b)\(\left[-20,83.0,2+\left(-9,17.0,2\right)\right]:\left[2,47.0,5-\left(-3,53\right).0,5\right]\)

\(=\left[0,2\left(-20,83-9,17\right)\right]:\left[0,5\left(2,47+3,53\right)\right]\)

\(=\dfrac{0,2\left(-30\right)}{0,5.6}=\dfrac{-6}{3}=-2\)

a) (-2,5. 0,38. 0, 4) - ( 0,125. 3,15. (-8))

=((-2,5.0,4).0,38) - ((-8.0,125).3,15)

= ((-1).0,38) - ((-1).3,15)

= -0,38 - (-3,15)

= 2.77

b) ((-20,83) .0,2 + (-9,17).0,2) : ( 2,47.0,5 - (-3,53).0,5)

= ((-20,83 - 9,17).0,2) : ((2,47 + 3,53).0,5)

= (-6) : 3

= -2

a) (-2,5. 0,38. 0, 4) - ( 0,125. 3,15. (-8))

=((-2,5.0,4).0,38) - ((-8.0,125).3,15)

= ((-1).0,38) - ((-1).3,15)

= -0,38 - (-3,15)

= 2.77

b) ((-20,83) .0,2 + (-9,17).0,2) : ( 2,47.0,5 - (-3,53).0,5)

= ((-20,83 - 9,17).0,2) : ((2,47 + 3,53).0,5)

= (-6) : 3

= -2

a) ( -2,5 \(\times\) 0,38 \(\times\) 0,4 ) \(-\) [0.125 \(\times\) 3,15 \(\times\) (-8)]

= [ ( -2,5 \(\times\) 0,4 ) \(\times\) 0,38] \(-\) [ ( -8 \(\times\) 0,125 ) \(\times\) 3,15]

= ( - 10 \(\times\) 0,38 ) \(-\) ( -1 \(\times\) 3,15 )

= -38 + 3,15

= -34,85

b) [( -20,83) .0,2 + ( -9,17) .0,2] : [ 2,47 .0,5 - (-3,53) .0,5]

= {[ -20,83 + ( -9,17)] .0,2} : {[ 2,47 - (-3,53)] .0,5}

= [ -30 .0,2] : [ 6 .0,5]

= -6 : 3

= -2