\(4^2.25^2+32.125/ 2^3.5^2 \)
/ là phần nhé ! Giúp mk đi
GIÚP MÌNH VỚI MÌNH CẦN GẤP
tính giá trị biểu thức sau : 4^2.25^2+32.125/2^3.5^2 ( / là phần nhé )
Tính hợp lý:
\(\dfrac{4^2.25^2+32.125}{2^3.5^2}\)
\(\dfrac{4^2.25^2+32.125}{2^3.5^2}=\dfrac{2^4.5^4+2^5.5^3}{2^3.5^2}=\dfrac{2^3.5^2\left(2.5^2+2^2.5\right)}{2^3.5^2}=2.5^2+2^2.5=50+20=70\)
Tính 4^2.25^2+32.125/2^3.5^2
\(\dfrac{4^2.25^2+32.125}{2^3.5^2}=\dfrac{2^4.5^4+2^5.5^3}{2^3.5^2}=\dfrac{2^4.5^3\left(5+2\right)}{2^3.5^2}=2.5\left(5+2\right)=10.7=70\)
Tính một cách hợp lí: \(\dfrac{4^2.25^2+32.125}{2^3.5^2}\)
\(\dfrac{4^2.25^2+32.125}{2^3.5^2}\)
\(=\dfrac{\left(2^2\right)^2.\left(5^2\right)^2+2^5.5^3}{2^3.5^2}\)
\(=\dfrac{2^4.5^4+2^5.5^3}{2^3.5^2}\)
\(=\dfrac{2^3.5^2\left(2.5^2+2^2.5\right)}{2^3.5^2}\)
\(=2.5^2+2^2.5\)
\(=2.25+4.5=50+20=70\)
rut gon bieu thuc sau : 4^2.25^2+32.125/2^3.5^2
\(\dfrac{4^2.25^2+32.125}{2^3.5^2}\)
=\(\dfrac{\left(2^2\right)^2.\left(5^2\right)^2+2^5.5^2}{2^3.5^2}\)
=\(\dfrac{2^4.5^4+2^5.5^2}{2^3.5^2}\)
=\(\dfrac{2^3.\left(2.5^4+2^2.5^2\right)}{2^3.5^2}\)
=\(\dfrac{5^2.\left(2.5^2+2^2\right)}{5^2}\)
=\(2.5^2+2^2=54\)
\(\frac{4^2.25^2+32.125}{2^3.5^2}\)
Làm
\(\frac{4^2.25^2+32.125}{2^3.5^2}=\frac{2^4.5^4+2^5.5^3}{2^3.5^2}=\frac{2^4.5^3\left(5+2\right)}{2^3.5^2}=2.5.7=70\)
\(\dfrac{4^2.25^2+32.125}{2^3.5^2}\)
\(\dfrac{4^2.25^2+32.125}{2^3.5^2}=\dfrac{2^4.5^4+2^5.5^3}{2^3.5^2}=\dfrac{2^3.5^2\left(2.5^2+2^2.5\right)}{2^3.5^2}\)
\(=2.5^2+2^2.5=2.25+4.5=50+20=70\)
B=\(\frac{4^2.25^2+32.125}{2^3.5^2}\)
\(B=\frac{4^2.25^2+32.125}{2^3.5^2}\)
\(=\frac{\left(2^2\right)^2.\left(5^2\right)^2+2^5.5^3}{2^3.5^2}\)
\(=\frac{2^4.5^4+2^5.5^3}{2^3.5^2}\)
\(=\frac{2^3.5^2.\left(2.5^2+2^2.5\right)}{2^3.5^2}\)
\(=2.5^2+2^2.5\)
\(=2.25+4.5\)
\(=50+20=70\)
\(B=\frac{2^4.5^4+2^5.5^3}{2^3.5^2}=\frac{2^4.5^3\left(5+2\right)}{2^3.5^2}=2.5.7=70\)