đáp án là:A>B

chúc bn hok tốt

\(A=\frac{20032}{2004}+\frac{2004}{2005}=9,99600798+0,999501247=10,9955092\)

\(B=\frac{2003+2004}{2004+2005}=\frac{4007}{4009}\)

\(\text{Vì : }10,9955092>1\text{ mà }\frac{4007}{4009}< 1\text{ nên }10,9955092>\frac{4007}{4009}\)

\(\text{Vậy : }A>B\)

\(2004A=\frac{2004^{2004}+2004}{2004^{2004}+1}=1+\frac{2003}{2004^{2004}+1}\)

\(2004B=\frac{2004^{2005}+2004}{2004^{2005}+1}=1+\frac{2003}{2004^{2005}+1}\)

\(\frac{2003}{2004^{2004}+1}>\frac{2003}{2004^{2005}+1}\)

\(\Rightarrow2004A>2004B\)

\(\Rightarrow A>B\)

2004A=\(\frac{2004^{2004}+2004}{2004^{2004}+1}\)

\(\frac{2004^{2004}+2004}{2004^{2004}+1}-1=\frac{2003}{2004^{2004}+1}\)

2004B=\(\frac{2004^{2005}+2004}{2004^{2005}+1}\)

\(\frac{2004^{2005}+2004}{2004^{2005}+1}-1=\frac{2003}{2004^{2005}+1}\)

Ta thấy :\(\frac{2003}{2004^{2004}+1}>\frac{2003}{2004^{2005}+1}\)

=> \(2004A>2004B\)

Vậy \(A>B\)

c) 22/5 + 51/9 + 11/4 + 3/5 + 1/3 + 1/4
= 22/5 +3/5 +51/9 + 1/3 +11/4+1/4
= (22/5 +3/5) +(51/9 + 3/9) +(11/4+1/4)
= 25/5 +54/9 +12/4
= 5 +6 +3
= 14
d) (1/6 + 1/10 + 1/15) : (1/6 + 1/10 - 1/15) 
= (5/30 + 3/30 +2/30 ) :(5/30 +3/30 -2/30)
= 10/30 : 6/30
= 1/3 : 1/5
= 5/3

Ta có:

n = \(\frac{2003+2004}{2004+2005}\)

\(=>\) n = \(\frac{2003}{2004+2005}+\frac{2004}{2004+2005}\)

Vì \(\frac{2003}{2004}>\frac{2003}{2004+2005}\)

     \(\frac{2004}{2005}>\frac{2004}{2004+2005}\)

\(=>\frac{2003}{2004}+\frac{2004}{2005}>\frac{2003}{2004+2005}+\frac{2004}{2004+2005}\)

\(=>\)m > n

Chúc bạn học tốt :)

Alớn hơn nhé

a lớn hơn

a lớn hơn nha bạn k nha 

a )     \(\frac{55553}{55557}>\frac{555554}{555559}\)

b)    \(\frac{2003}{2004}+\frac{2004}{2005}+\frac{2006}{2004}>3\)