\(x:25\%+x:0,5+x\cdot5=270\)

\(x\cdot4+x\cdot2+x\cdot5=270\)

\(x\cdot\left(4+2+5\right)=270\)

\(x\cdot11=270\)

\(x=\dfrac{270}{11}\)

X : 25% + X : 0,5 + X x 5 - X = 270

X : \(\dfrac{1}{4}\) + X : \(\dfrac{1}{2}\) + X x 5 -X =270

X x 4 +X x 2 +X x 5 -X = 270

X x ( 4+ 2+ 5 -1 ) = 270

x x 10 = 270

X         = 270 : 10

X          = 27

X x 4 + X x 2 +X x 5 - X= 270

X x (4+2+5)-x =270

X x 11- X x1= 270

X x (11-1) =270

X x10=270

       X=270 :10

         X=27

\(\frac{1}{5}x+\frac{2}{5}x=x-4\)

             \(\frac{3}{5}x=x-4\) 

     \(\frac{3}{5}x-x=-4\)

         \(-\frac{2}{5}x=-4\)

                  \(x=10\)

\(\frac{1}{5}x+\frac{2}{5}x\)= x - 4

\(\frac{3}{5}x\)= x - 4 

\(\frac{3}{5}x\)- x = - 4 

\(\frac{-2}{5}x\)= -4

x = -4 : \(\frac{-2}{5}\)

x = 10 

Ta thấy:
\(70-5\left(x-3\right)=40\)
\(\Rightarrow5\left(x-3\right)=70-40\)
\(\Rightarrow5\left(x-3\right)=30\)
\(\Rightarrow x-3=30\div5\)
\(\Rightarrow x-3=6\)
\(\Rightarrow x=6+3\)
\(\Rightarrow x=9\)

 70 - 5 ( x - 3 ) = 40

       5 ( x - 3 ) = 70 - 40

       5 ( x - 3 ) = 30

              x - 3 = 30 :5

              x - 3 = 6

                   x = 6+ 3

                   x = 9

x=65(x-3)=40

x= x-(65-3) =40

x-62=40

x=40+62

x=102

\(\frac{x}{3}=\frac{5}{8}+\frac{1}{8}\)

\(\frac{x}{3}=\frac{6}{8}=\frac{3}{4}\)

\(\Rightarrow x\cdot4=3^2\)\(x=\frac{9}{4}\)hay\(x=2.25\)

á lộn 

x/3-1/8=5/8

x/3      = 6/8

x /3         =3/4

x.4=3.3

x.4=9

x=9/4

\(\frac{x}{3}-\frac{1}{8}=\frac{5}{8}\)

\(\frac{x}{3}=\frac{1}{8}+\frac{5}{8}\)

\(\frac{x}{3}=\frac{3}{4}\)

x/2-x/6-17/3=12-5

3x/6-x/6-17/3=7

2x/6-17/3=7

2x/6=7+17/3

2x/6=38/3

x/3=38/3

=>x=38

vậy x=38

2x là 2 nhân x nhe

k mk nha

Mk cảm ơn bn nha!

\(\frac{x}{2}+5-\left(\frac{x}{6}+\frac{17}{3}\right)=\)\(12\)

     \(\frac{x}{2}+5-\frac{x}{6}-\frac{17}{3}=12\)

     \(\frac{x}{2}-\frac{x}{6}+5-\frac{17}{3}=12\)

       \(\frac{x}{2}-\frac{x}{6}+\left(\frac{-2}{3}\right)=12\)

                   \(x.\frac{1}{2}-x.\frac{1}{6}=12-\left(\frac{-2}{3}\right)\)

                 \(x.\left(\frac{1}{2}-\frac{1}{6}\right)=12,\left(6\right)\)

                                 \(x.\frac{1}{3}=12,\left(6\right)\)

                                       \(x=12,\left(6\right):\frac{1}{3}\)

                                       \(x=38\)

a, x(x+3) = 0

\(\Rightarrow\orbr{\begin{cases}x=0\\x+3=0\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=0\\x=-3\end{cases}}\)

Vậy \(x\in\left\{0;-3\right\}\)

b, (x-2)(5-x)=0

\(\Rightarrow\orbr{\begin{cases}x-2=0\\5-x=0\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=2\\x=5\end{cases}}\)

Vậy \(x\in\left\{2;5\right\}\)

a) x(x+3)=0

*x=0

*x+3=0

      x=0-3

      x=-3

Vậy x=-3

b) (x-2)(5-x)=0

=> x-2=0 hoặc 5-x=0

=>    x=2 hoặc    x=5

Vậy x=2 hoặc x=5

a, x(x+3)=0

<=> \(\orbr{\begin{cases}x=0\\x=-3\end{cases}}\)

vậy ........

b, (x-2)(5-x)=0

<=> \(\orbr{\begin{cases}x=2\\x=5\end{cases}}\)

vậy ........

\(\left(x-5\right)^{2016}=x-5\)

\(\Rightarrow\left(x-5\right)^{2016}-\left(x-5\right)=0\)

\(\Rightarrow\left(x-5\right)\left[\left(x-5\right)^{2015}-1\right]=0\)

\(\Rightarrow\orbr{\begin{cases}x-5=0\\\left(x-5\right)^{2015}-1=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=5\\\left(x-5\right)^{2015}=1\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=5\\x-5=1\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=5\\x=6\end{cases}}\)

\(Vậy\)\(x\in\left\{5;6\right\}\)

(x - 5)²⁰¹⁶ = x - 5

=> (x - 5)²⁰¹⁶ - (x - 5) = 0

=> (x - 5).[(x - 5)²⁰¹⁵ - 1] = 0

=> \(\orbr{\begin{cases}x-5=0\\\left(x-5\right)^{2015}-1=0\end{cases}\Rightarrow\orbr{\begin{cases}x=5\\\left(x-5\right)^{2015}=1^{2015}\end{cases}\Rightarrow}\orbr{\begin{cases}x=5\\x-5=1\end{cases}\Rightarrow}\orbr{\begin{cases}x=5\\x=6\end{cases}}}\)

Vậy x = 5;x= 6