A=\(\frac{2006x\left(2004+1\right)-1}{2006x2004+2005}=\frac{2006x2004+2006-1}{2006x2004+2005}\)

= \(\frac{2006x2004+2005}{2006x2004+2005}=1\)

\(\frac{2006\times2005-1}{2004\times2006+2005}=\frac{2006\times\left(2004+1\right)-1}{2004\times2006+2005}=\frac{2006\times2004+2006\times1-1}{2004\times2006+2005}=\frac{2006\times2004+2005}{2006\times2004+2005}=1\)

\(\frac{2006\times2005-1}{2004\times2006+2005}=\frac{2006\times\left(2004+1\right)-1}{2004\times2006+2005}=\frac{2004\times2006+2006\times1-1}{2004\times2006+2005}\)

\(=\frac{2004\times2006+2005}{2004\times2006+2005}=1\)

\(\frac{2006x2005-1}{2004x2006+2005}\)

\(=\frac{2006x\left(2004+1\right)-1}{2004x2006+2005}\)

\(=\frac{2006x2004+2006-1}{2004x2006+2005}\)

\(=\frac{2006x2004+2005}{2004x2006+2005}\)

\(=1\)

\(\frac{2006.2005-1}{2004.2006+2005}\)

\(=\frac{2006\left(2004+1\right)-1}{2004.2006+2005}\)

\(=\frac{2006.2004+2006-1}{2004.2006-2005}\)

\(=\frac{2006.2004+2005}{2004.2006+2005}=1\)

nha

bn Nguyễn Minh Anh bn nói rõ hơn đc ko?

giải chi tiết r đó bn

Ta chỉ việc tách ra thôi VD ta thấy L

           2006x2005 = 2006x2004+2006x 1

Vây ta sẽ có cách làm như sau :
                \(\frac{2006\cdot2005-1}{2004\cdot2006+2005}\)

             \(=\frac{2006\cdot2004+2006\cdot1-1}{2004\cdot2006+2005}\)

               \(=\frac{2006\cdot2004+2006-1}{2006\cdot2004+2005}\)

                \(=\frac{2006\cdot2004+2005}{2004\cdot2006+2005}=1\)

\(\frac{2006\cdot2005-1}{2004\cdot2006+2005}=\frac{2006\cdot\left(2004+1\right)}{2004\cdot2006+2005}=\frac{2006\cdot2004+2006\cdot1-1}{2004\cdot2006+2005}=\frac{2006\cdot2004+2005}{2004\cdot2006+2005}=1\)

\(\frac{2006x2005-1}{2004x2006+2005}=\frac{2006x\left(2004+1\right)-1}{2004x2006+2005}\)

\(=\frac{2006x2004+2006-1}{2004x2006+2005}\)

\(=\frac{2006x2004+2005}{2004x2006+2005}\)

\(=1\)

Giải như mình là chuẩn rồi đó :)