ai làm giúp em với
A=\(4\sqrt{x}-\frac{\left(x+6\sqrt{x}+9\right)\left(\sqrt{x}-3\right)}{x-9}\)với 0<x khác 9
B=\(\frac{\sqrt{9x^2+12x+4}}{3x+2}\)với x khác \(-\frac{2}{3}\)
Những câu hỏi liên quan
Cho biểu thức P=\(\left(1-\frac{x-3\sqrt{x}}{x-9}\right):\left(\frac{\sqrt{x}-9}{2-\sqrt{x}}+\frac{\sqrt{x}-2}{3+\sqrt{x}}-\frac{9-x}{x+\sqrt{x}-6}\right)\)
với x>=0 ; x khác 9; x khác 4
Rút gọn biểu thức P
giúp mình với
Bài làm:
Ta có:
\(P=\left(1-\frac{x-3\sqrt{x}}{x-9}\right)\div\left(\frac{\sqrt{x}-9}{2-\sqrt{x}}+\frac{\sqrt{x}-2}{3+\sqrt{x}}-\frac{9-x}{x+\sqrt{x}-6}\right)\)
\(P=\frac{x-9-x+3\sqrt{x}}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}\div\left[\frac{\left(9-\sqrt{x}\right)\left(3+\sqrt{x}\right)+\left(\sqrt{x}-2\right)^2-9+x}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+3\right)}\right]\)
\(P=\frac{3\sqrt{x}-9}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}\div\frac{-x+6\sqrt{x}+27+x-4\sqrt{x}+2-9+x}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+3\right)}\)
\(P=\frac{3}{\sqrt{x}+3}\div\frac{x+2\sqrt{x}+20}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+3\right)}\)
\(P=\frac{3}{\sqrt{x}+3}\cdot\frac{\left(\sqrt{x}-2\right)\left(\sqrt{x}+3\right)}{x+2\sqrt{x}+20}\)
\(P=\frac{3\left(\sqrt{x}-2\right)}{x+2\sqrt{x}+20}=\frac{3\sqrt{x}-6}{x+2\sqrt{x}+20}\)
Rút gọn các biểu thức sau:
\(D=\left(\frac{5\sqrt{x-6}}{x-9}-\frac{2}{\sqrt{x}+3}\right):\left(1+\frac{6}{x-9}\right)\)
\(E=\left(\frac{\sqrt{x}}{3+\sqrt{x}}+\frac{9+x}{9-x}\right).\left(3\sqrt{x}-x\right)\)
Cho biểu thức: \(P=\left(\frac{\sqrt{x}-3}{2-\sqrt{x}}+\frac{\sqrt{x}+2}{3+\sqrt{x}}-\frac{9-x}{x+\sqrt{x}-6}\right):\left(1-\frac{3\sqrt{x}-9}{x-9}\right)\)
a)Rút gọn biểu thức
b)Tính P với \(x=\frac{\sqrt{4+2\sqrt{3}}\left(\sqrt{x}-1\right)}{\sqrt{6+2\sqrt{5}-\sqrt{5}}}\)
Mình ghi nhầm. \(x=\frac{\sqrt{4+2\sqrt{3}}.\left(\sqrt{3}-1\right)}{\sqrt{6+2\sqrt{5}}-\sqrt{5}}\)nhé
Mọi người cho em hỏi:left(frac{sqrt{x}}{left[sqrt{x}-3right]left[sqrt{x}+3right]}+frac{2}{sqrt{x}+3}-frac{3}{sqrt{x}-3}right):left(sqrt{x}-3+frac{12-x}{sqrt{x}+3}right)left(frac{sqrt{x}+2left[sqrt{x}-3right]-3left[sqrt{x}+3right]}{left[sqrt{x}-3right]left[sqrt{x}+3right]}right):left(frac{left[sqrt{x}-3right]left[sqrt{x}+3right]+12-x}{sqrt{x}-3}right)left(frac{sqrt{x}+2sqrt{x}-6-3sqrt{x}-9}{left[sqrt{x}+3right]left[sqrt{x}-3right]}right):left(frac{x+3sqrt{x}-3sqrt{x}-9+12-x}{sqrt{x}+3}right)left(...
Đọc tiếp
Mọi người cho em hỏi:
\(\left(\frac{\sqrt{x}}{\left[\sqrt{x}-3\right]\left[\sqrt{x}+3\right]}+\frac{2}{\sqrt{x}+3}-\frac{3}{\sqrt{x}-3}\right):\left(\sqrt{x}-3+\frac{12-x}{\sqrt{x}+3}\right)\)
\(\left(\frac{\sqrt{x}+2\left[\sqrt{x}-3\right]-3\left[\sqrt{x}+3\right]}{\left[\sqrt{x}-3\right]\left[\sqrt{x}+3\right]}\right):\left(\frac{\left[\sqrt{x}-3\right]\left[\sqrt{x}+3\right]+12-x}{\sqrt{x}-3}\right)\)
\(\left(\frac{\sqrt{x}+2\sqrt{x}-6-3\sqrt{x}-9}{\left[\sqrt{x}+3\right]\left[\sqrt{x}-3\right]}\right):\left(\frac{x+3\sqrt{x}-3\sqrt{x}-9+12-x}{\sqrt{x}+3}\right)\)
\(\left(\frac{-15}{\left[\sqrt{x}+3\right]\left[\sqrt{x}-3\right]}\right):\left(\frac{3}{\sqrt{x}+3}\right)\)
\(\left(\frac{-15}{\left[\sqrt{x}+3\right]\left[\sqrt{x}-3\right]}\right).\left(\frac{\sqrt{x}+3}{3}\right)\)
\(\frac{-5}{\sqrt{x}-3}\)
Rút gọn:
a, A frac{sqrt{x}}{sqrt{x}-6}-frac{3}{sqrt{x}+6}+frac{x}{36-x} (đk: x ≥ 0 và x ≠ 36)
b, B frac{9-x}{sqrt{x}+3}-frac{x-6sqrt{x}+9}{sqrt{x}-3}-6 (đk: x ≥ 0 và x ≠ 9)
c, C frac{a+b}{left(sqrt{a}-sqrt{b}right)^2}-frac{2}{sqrt{ab}}:left(frac{1}{sqrt{a}}-frac{1}{sqrt{b}}right)^2 (đk: a 0, b 0 và a ≠ b)
d, D left(frac{2-asqrt{a}}{2-sqrt{a}}+sqrt{a}right)left(frac{2-sqrt{a}}{2-a}right) (đk: a ≥ 0, a ≠ 2, a ≠ 4)
Đọc tiếp
Rút gọn:
a, A = \(\frac{\sqrt{x}}{\sqrt{x}-6}-\frac{3}{\sqrt{x}+6}+\frac{x}{36-x}\) (đk: x ≥ 0 và x ≠ 36)
b, B = \(\frac{9-x}{\sqrt{x}+3}-\frac{x-6\sqrt{x}+9}{\sqrt{x}-3}-6\) (đk: x ≥ 0 và x ≠ 9)
c, C = \(\frac{a+b}{\left(\sqrt{a}-\sqrt{b}\right)^2}-\frac{2}{\sqrt{ab}}:\left(\frac{1}{\sqrt{a}}-\frac{1}{\sqrt{b}}\right)^2\) (đk: a > 0, b > 0 và a ≠ b)
d, D = \(\left(\frac{2-a\sqrt{a}}{2-\sqrt{a}}+\sqrt{a}\right)\left(\frac{2-\sqrt{a}}{2-a}\right)\) (đk: a ≥ 0, a ≠ 2, a ≠ 4)
\(B=\frac{9-x}{\sqrt{x}+3}-\frac{x-6\sqrt{x}+9}{\sqrt{x}-3}-6\)(đk: x ≥ 0 và x ≠ 9)
\(B=\frac{\left(3-\sqrt{x}\right)\left(3+\sqrt{x}\right)}{\sqrt{x}+3}-\frac{\left(\sqrt{x}-3\right)^2}{\sqrt{x}-3}-6\)
\(B=\left(3-\sqrt{x}\right)-\left(\sqrt{x}-3\right)-6\)
\(B=3-\sqrt{x}-\sqrt{x}+3-6\)
\(B=-2\sqrt{x}\)
Đúng 0
Bình luận (0)
\(A=\frac{\sqrt{x}}{\sqrt{x}-6}-\frac{3}{\sqrt{x}+6}+\frac{x}{36-x}\)(đk: x ≥ 0 và x ≠ 36)
\(=\frac{\sqrt{x}}{\sqrt{x}-6}-\frac{3}{\sqrt{x}+6}-\frac{x}{x-36}\)
\(=\frac{\sqrt{x}}{\sqrt{x}-6}-\frac{3}{\sqrt{x}+6}-\frac{x}{x-36}\)
\(=\frac{\sqrt{x}\left(\sqrt{x}+6\right)-3\left(\sqrt{x-6}\right)-x}{(\sqrt{x}-6)\left(\sqrt{x}+6\right)}\)
\(=\frac{x+6\sqrt{x}-3\sqrt{x}+18-x}{(\sqrt{x}-6)\left(\sqrt{x}+6\right)}\)
\(=\frac{3\sqrt{x}+18}{(\sqrt{x}-6)\left(\sqrt{x}+6\right)}\)
\(=\frac{3(\sqrt{x}+6)}{(\sqrt{x}-6)\left(\sqrt{x}+6\right)}\)
\(=\frac{3}{\sqrt{x}-6}\)
Đúng 0
Bình luận (0)
Rút gọn biểu thức:
M = \(\left(\frac{\sqrt{x}+2}{x-9}-\frac{\sqrt{x}-2}{x+6\sqrt{x}+9}\right)\left(\sqrt{x}-\frac{9}{\sqrt{x}}\right)\) với x > 0 và x ≠ 9
link đây: )
https://www.pornhub.com/view_video.php?viewkey=ph5925b69f43688
Đúng 0
Bình luận (0)
Dleft ( frac{1}{3sqrt{x}-6} +frac{1}{x-2sqrt{x}}right )left ( frac{1}{6} +frac{1}{2sqrt{x}}right ) Dleft ( frac{1}{3left ( sqrt{x}-2 right )} +frac{1}{sqrt{x}left ( sqrt{x}-2 right )}right ).frac{sqrt{x}+3}{6sqrt{x}} Dfrac{sqrt{x}+3}{3sqrt{x}left ( sqrt{x}-2 right )}.frac{sqrt{x}+3}{6sqrt{x}} Dfrac{left ( sqrt{x}+3 right )^{2}}{18xleft ( sqrt{x}-2 right )} Dfrac{x+6sqrt{x}+9}{18xsqrt{x}-36x}
A/ Đúng
B/ Sai
Đọc tiếp
\[D=\left ( \frac{1}{3\sqrt{x}-6} +\frac{1}{x-2\sqrt{x}}\right )\left ( \frac{1}{6} +\frac{1}{2\sqrt{x}}\right )\\ D=\left ( \frac{1}{3\left ( \sqrt{x}-2 \right )} +\frac{1}{\sqrt{x}\left ( \sqrt{x}-2 \right )}\right ).\frac{\sqrt{x}+3}{6\sqrt{x}}\\ D=\frac{\sqrt{x}+3}{3\sqrt{x}\left ( \sqrt{x}-2 \right )}.\frac{\sqrt{x}+3}{6\sqrt{x}}\\ D=\frac{\left ( \sqrt{x}+3 \right )^{2}}{18x\left ( \sqrt{x}-2 \right )}\\ D=\frac{x+6\sqrt{x}+9}{18x\sqrt{x}-36x}\]
A/ Đúng
B/ Sai
Rút gọn:
\(A=\frac{x^2+5x+6+x\sqrt{9-x^2}}{3x-x^2+\left(x+2\right).\sqrt{9-x^2}}\)
\(B=\frac{x^2-5x+6+3\sqrt{x^2-6x+8}}{3x-12+\left(x-3\right).\sqrt{x^2-6x+8}}\)
\(C=\frac{\sqrt{2\sqrt{4-x^2}}.\left(\sqrt{\left(2+x\right)^3}-\sqrt{\left(2-x\right)^3}\right)}{4+\sqrt{4-x^2}}\)
Rút gọn:
\(A=\frac{x^2+5x+6+x\sqrt{9-x^2}}{3x-x^2+\left(x+2\right).\sqrt{9-x^2}}\)
\(B=\frac{x^2-5x+6+3\sqrt{x^2-6x+8}}{3x-12+\left(x-3\right).\sqrt{x^2-6x+8}}\)
\(C=\frac{\sqrt{2\sqrt{4-x^2}}.\left(\sqrt{\left(2+x\right)^3}-\sqrt{\left(2-x\right)^3}\right)}{4+\sqrt{4-x^2}}\)
