Tìm \(X\) biết :
\(X+Xx\frac{1}{4}:\frac{2}{7}+X:\frac{2}{9}=255\)
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Tìm x
a \(\frac{3}{4}+\frac{1}{4}xX=2\)
b X - \(\frac{2}{3}x\frac{9}{4}=2,5-\frac{1}{2}\)
c \(2xX+\frac{1}{3}=\frac{4}{3}\)
d \(X:\frac{2}{3}+0,75=\frac{9}{4}+3\)
e \(\frac{6}{4}:X+\frac{1}{2}=\frac{9}{4}x\frac{2}{3}\)
f \(Xx\frac{3}{5}-\frac{2}{5}=3\frac{3}{4}-1\)
a, 3/4 + 1/4.x=2
1/4.x = 2-3/4
1/4.x =5/4
x = 5/4:1/4
x = 5
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b, x-2/3.9/4=2,5-1/2
x-2/3.9/4=2
x-2/3 =2:9/4
x-2/3 =8/9
x = 8/9+2/3
x = 14/9
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c, 2.x+1/3=4/3
2.x =4/3-1/3
2.x =1
x =11:2
x = 1/2
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Tìm x biết : \(2\frac{1}{4}x-9\frac{1}{4}=-7\frac{1}{4}\)Tìm x biết: \(1-\left(6\frac{3}{8}+x-7\frac{5}{24}\right).16\frac{2}{3}=26\)
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1)
\(2\frac{1}{4}x-9\frac{1}{4}=-7\frac{1}{4}\)
\(2\frac{1}{4}x=\left(-7\frac{1}{4}\right)+9\frac{1}{4}\)
\(2\frac{1}{4}x=2\)
\(x=2:2\frac{1}{4}\)
\(x=\frac{8}{9}\)
Vậy \(x=\frac{8}{9}\)
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Tìm x biết: \(\frac{x+1}{9}+\frac{x+4}{6}+\frac{x+5}{5}=\frac{x+2}{8}+\frac{x+3}{7}+\frac{x+6}{4}.\)
\(\frac{x+1}{9}+\frac{x+4}{6}+\frac{x+5}{5}=\frac{x+2}{8}+\frac{x+3}{7}+\frac{x+6}{4}\)
\(\Rightarrow\frac{x+1}{9}+\frac{x+4}{6}+\frac{x+5}{5}+3=\frac{x+2}{8}+\frac{x+3}{7}+\frac{x+6}{4}+3\)
\(\Rightarrow\left(\frac{x+1}{9}+1\right)+\left(\frac{x+4}{6}+1\right)+\left(\frac{x+5}{5}+1\right)=\left(\frac{x+2}{8}+1\right)\)\(+\left(\frac{x+3}{7}+1\right)+\left(\frac{x+6}{4}\right)\)
\(\Rightarrow\frac{x+10}{9}+\frac{x+10}{6}+\frac{x+10}{5}=\frac{x+10}{8}+\frac{x+10}{7}+\frac{x+10}{4}\)
\(\Rightarrow\left(x+10\right)\left(\frac{1}{9}+\frac{1}{6}+\frac{1}{5}\right)=\left(x+10\right)\left(\frac{1}{8}+\frac{1}{7}+\frac{1}{4}\right)\)
\(\Rightarrow\left(x+10\right)\frac{43}{90}=\left(x+10\right)\frac{29}{56}\)
\(\Rightarrow x+10=0\)
\(\Rightarrow x=-10\)
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cộng 3 vào cả hai vế nên phương trình vẫn bằng nhau
Ta có \(\frac{x+1}{9}+1+\frac{x+4}{6}+1+\frac{x+5}{5}+1=\frac{x+2}{8}+1+\frac{x+3}{7}+1+\frac{x+6}{4}+1\)
\(\Leftrightarrow\frac{x+10}{9}+\frac{x+10}{6}+\frac{x+10}{5}=\frac{x+10}{8}+\frac{x+10}{7}+\frac{x+10}{4}\)
\(\Leftrightarrow\frac{x+10}{9}+\frac{x+10}{6}+\frac{x+10}{5}-\frac{x+10}{8}-\frac{x+10}{7}-\frac{x+10}{4}=0\)
\(\Leftrightarrow\left(x+10\right)\left(\frac{1}{9}+\frac{1}{6}+\frac{1}{5}-\frac{1}{8}-\frac{1}{7}-\frac{1}{6}\right)=0\)
mà \(\frac{1}{9}+\frac{1}{6}+\frac{1}{5}-\frac{1}{8}-\frac{1}{7}-\frac{1}{6}\ne0\)
\(\Rightarrow x+10=0\)
\(\Leftrightarrow x=-10\)
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Tìm x, biết
\(\frac{3}{2}-\frac{2}{7}< \frac{2}{3}x+\frac{3}{4}< \frac{1}{2}+\frac{7}{9}\)
Tìm x. biết:
\(\frac{3}{2}-\frac{2}{7}< \frac{2}{3}x+\frac{3}{4}< \frac{1}{2}+\frac{7}{9}\)
\(\frac{3}{2}-\frac{2}{7}< \frac{2}{3}x+\frac{3}{4}< \frac{1}{2}\)\(+\frac{7}{9}\)
=\(\frac{17}{14}< \frac{2}{3}x+\frac{3}{4}< \frac{23}{18}\)
=\(\frac{17}{14}-\frac{3}{4}< \frac{2}{3}x+\frac{3}{4}< \frac{23}{18}-\frac{3}{4}\)
=\(\frac{13}{28}< \frac{2}{3}x< \frac{19}{36}\)
=\(\frac{117}{252}< \frac{2}{3}x< \frac{133}{252}\)
=
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Tìm x biết
a) (8-5x).(x+2)+4.(x-2).(x+1)+2.(x-2).(x+2)=0
b)\(\left(-\frac{2}{5}+x\right):\frac{7}{9}+\left(-\frac{3}{5}+\frac{5}{6}\right):\frac{7}{9}=0\)
c)\(1+\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{2}{x\left(x+1\right)}=1\frac{2003}{2004}\)
Tìm x biết:
\(\frac{3}{5}-\frac{2}{7}< \frac{2}{3}x+\frac{3}{4}< \frac{1}{2}+\frac{7}{9}\)
Tìm x, biết
a) \(x\left(x-\frac{1}{2}\right)< 0\)
b) \(\frac{3}{5}-\frac{2}{7}< \frac{2}{3}x+\frac{3}{4}< \frac{1}{2}+\frac{7}{9}\)
Tìm x, biết
\(a.\frac{3}{2}-\frac{2}{7}< \frac{2}{3}x+\frac{3}{4}< \frac{1}{2}+\frac{7}{9}\)
\(b.\left(x-\frac{1}{3}\right).\left(x+\frac{2}{5}\right)>0\)