(4/3)^2018÷(16/9)^1008-x=0,6^3÷0,2^3
Những câu hỏi liên quan
x - 1 / 2018 + x-9 / 503 = x - 3 / 1008 + x - 9 / 670
tim x : (x+2)/2019 + (x+3)/2018 + (x+4)/2017 + (x+5)/1008 + (x+2076)/11 = 0
lam nhu the nao giup minh voi
Cho M=1-1/2+1/3-1/4+...-1/2018 N=1/1007+1/1008+...+1/2018 Tính (M/N)^2018
(0,6)^4 x 4^3 / (0,2)^5 x 6^5 = ?
(0,6)^4 x 4^3
(0,2)^% x 6^5
TÌM Y BIẾT:
a) y x 4/3= 16/9
b) (y-1/2)+0,5=3/4
c) 4/5-2/5 x y=0,2
d) (y+3/4)x5/7=10/9
e) y : 5/4=9/5+1/2
f) y x 1/2+3/2x y=4/5
a, y \(\times\) \(\dfrac{4}{3}\) = \(\dfrac{16}{9}\)
y = \(\dfrac{16}{9}\) : \(\dfrac{4}{3}\)
y = \(\dfrac{4}{3}\)
b, ( y - \(\dfrac{1}{2}\)) + 0,5 = \(\dfrac{3}{4}\)
y - 0,5 + 0,5 = \(\dfrac{3}{4}\)
y = \(\dfrac{3}{4}\)
c, \(\dfrac{4}{5}-\dfrac{2}{5}y\) = 0,2
0,8 - 0,4y = 0,2
0,4y = 0,8 - 0,2
0,4y = 0,6
y = 1,5
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d, (y + \(\dfrac{3}{4}\)) \(\times\) \(\dfrac{5}{7}\) = \(\dfrac{10}{9}\)
y + \(\dfrac{3}{4}\) = \(\dfrac{10}{9}\) : \(\dfrac{5}{7}\)
y + \(\dfrac{3}{4}\) = \(\dfrac{14}{9}\)
y = \(\dfrac{14}{9}\) - \(\dfrac{3}{4}\)
y = \(\dfrac{29}{36}\)
e, y : \(\dfrac{5}{4}\) = \(\dfrac{9}{5}\) + \(\dfrac{1}{2}\)
y : \(\dfrac{5}{4}\) = \(\dfrac{23}{10}\)
y = \(\dfrac{23}{10}\)
y = \(\dfrac{23}{8}\)
f, y \(\times\) \(\dfrac{1}{2}\) + \(\dfrac{3}{2}\) \(\times\) y = \(\dfrac{4}{5}\)
y \(\times\) ( \(\dfrac{1}{2}+\dfrac{3}{2}\)) = \(\dfrac{4}{5}\)
2y = \(\dfrac{4}{5}\)
y = \(\dfrac{2}{5}\)
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Bài 1:tìm x:
a) x+5*2-(32+16*3*6-15)= 0
b) (x*0,25+1999)*2000= (53+1999)*2000
c)x*2016=x:2016
d) (x+2)+(x+3)+.....................+ (x+100)= 5750-(x-1)
e) x+x:1/3:2/9+x:2/7= 252
g) 71+65*4=\(\frac{x+140}{x}\) + 260
h) x:0,1: 0,2: 0,3 :0,4 : 0,5 : 0,6 = 100000
Tìm x, biết:
\(\frac{x-1}{2018}\)+ \(\frac{x-7}{503}\)= \(\frac{x-3}{1008}\)+ \(\frac{x-9}{670}\)
Chứng minh :
1/2 + 1/4 + 1/8 + ...+ 1/1024 < 1
1/2 +1/3 +1/4 +....+1/63 >2
\(\frac{x-1}{2018}+\frac{x-7}{503}=\frac{x-3}{1008}+\frac{x-9}{670}\)
\(\Leftrightarrow\frac{x-1}{2018}-1+\frac{x-7}{503}-4=\frac{x-3}{1008}-2+\frac{x-9}{670}-3\)
\(\Leftrightarrow\left(x-2019\right)\left(\frac{1}{2018}+\frac{1}{503}-\frac{1}{1008}-\frac{1}{670}\right)=0\)
\(\Rightarrow x=2019\)
#CBHT
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Đặt A =1/2+1/4+1/8+...+1/1024
2A= 1+1/2+1/4+...+1/512
A= 1-1/1024
=>A<1hay ...
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1) 0,1 + 0,2 +...+ 0,18 + 0,19.
2) 0,24 x 1230 + 0,6 x 4567 x 4 + 1,2 x 5310 x 235
3) 0,9 x 438 x 2 + 0,18 x 2520 + 0,6 x 310 x 3
