\(\frac{x+140}{x}\)+260+=21+65x4
tìm x
a, (x+20):99 =(1004+1)x\(\frac{2}{99}\)
b, \(\frac{x+140}{x}\)+260= 21+65x4
(x + 20) : 99 = (1004 + 1) x 2/99
=> 99x + 1980 = 1005 x 2/99
=> 99x = 99495/2 - 1980
=> 99x = 95535/2
=> x = 965/2
b. \(\frac{x+140}{x}\) + 260 = 21 + 65 x 4
=> \(\frac{x+140}{x}\)= 21 + 260 - 260
=> \(\frac{x+140}{x}\)= 21
=> 21x = x + 140
=> 20x = 140
=> x = 7
\(71+65x4=\frac{x+140}{x}+260\)
\(71+65\times4=\frac{x+140}{x}+260\)
\(71+260=\frac{x}{x}+\frac{140}{x}+260\)
\(71\) \(=1+\frac{140}{x}\)
\(70\) \(=\frac{140}{x}\)
\(x\) \(=2\)
71+65x4=x+140/x+260
71 + 65 x 4 = x + 140/x + 260
x + 140/x + 260 = 71 + 65 x 4
x + 140/x + 260 = 71 + 260
x + 140/x = 71
x/x + 140/x = 71
1 + 140/x = 71
140/x = 71 - 1
140/x = 70
x = 140/70
x = 2
71+ 65 x 4 = (X+14) /X + 260
71 + 260 = X : X + 14 : X + 260
71 = 1 + 14 : X (Cùng bớt 2 vế đi 260)
1 + 14 : X = 71 (đảo vế)
14 : X = 71 - 1
14 : X = 70
X = 14 : 70
X = 0,2
mik nha !!!
71+65x4=x+140:x=260
tìm x :71+65x4=x+140/x+260
Trả lời:
71+65.4=x+140/x+260
x+140/x+260=71+65.4
x+140/x+260=71+260
x+140/x=71
x/x+140/x=71
1+140/x=71
140/x=71-1
140/x=70
x=140/70
x=2
vậy x=2
cậu ơi cái chỗ 71+65x4 là nhân 4 hay là 65 nhân x nhân 4 ạ
là 65 nhân 4 nghe
tìm X
71+65x4=X+140/X+260
Tìm X:
71+65x4=X+140/X+260
71+65x4=x+140/x+260
71 + 65 x 4 = \(\frac{x+140}{x+260}\)
71 + 260 = \(\frac{x+140}{x+260}\)
331 = \(\frac{x+140}{x+260}\)
\(\Rightarrow x+140=331\left(x+260\right)\)
\(\Rightarrow x+140=331x+86060\)
\(\Rightarrow140-86060=331x-x\)
\(\Rightarrow330x=85920\)
\(\Rightarrow x=\frac{2864}{11}\)
tìm x biết
71 + 65x4=(x + 140):x +260
71+ 65x4 = (x+140) :x + 260
71 + 260 = x:x + 140:x + 260
71 + 260 - 1- 260 = 140x
70 = 140x
x= 70 : 140
x= 1/2