60%x+2/3x=1/3.19/3
Những câu hỏi liên quan
Tìm x
a) 2|1/2x-1/3|-3/2=1/4
b) (3x-1).(-1/2x+5)=0
c) 60%.x+2/3x=1/3.19/
d) 1/4+1/3: (2x-1)=-5
e) 3(x-1/2)-5.(x+3/5)=-x+1/5
2^3.19-2^3.14+1^2020
10^2-[60:(5^6:5^4-3.5)]
160:{17+[3^2.5-(14=2^7:2^4)]}
798+100:[16-2(5^2022)]
t^2+5t-6 khi t=2
(a+b)^2-(b-a)^3+2012 khi a=5;b=a+1
x^3-3x^2y=3xy^2-y^3 khi x=3;y=2
23.19 - 23.14 + 12020
= 23.(19 - 14) + 1
= 8.5 + 1
= 41
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102 - [60: (56: 54 - 3.5)]
= 100 - [60: (52 - 15)]
= 100 - [60: (25 - 15)]
= 100 - [60 : 10]
= 100 - 6
= 94
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160: {17 + [32.5 - ( 14 + 27:24)]}
= 160: {17 + [9.5 - (14 + 23)]}
= 160: {17 + [45 - (14 + 8)]}
= 160: {17 + [45 - 22]}
= 160: {17 + 23}
= 160 : 40
= 4
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Xem thêm câu trả lời
3^2+2^4.3^3.19+3^5 giúp em với
\(3^2+2^4.3^3.19+3^5=9+16.27.19+243=9+8208+243=8460\)
32 + 24 . 33 .19 + 35
= 9 + 16 . 27 . 19 + 243
= 9 + 8208 + 243
= 8460
#Học tốt!!!
~NTTH~
60% . x+2/3x=1/3.6 1/3
60%x+2/3x=1/3 . 6/1/3
Tìm x
1) -5(x + 1/5) - 1/2(x -2/3) = 3/2x - 5/6
2) 3(x - 1/2) - 5(x + 3/5) = -x + 1/5
3) 3(3x - 1/2)3 + 1/9 = 0
4) 60% .x + 2/3x =1/3 . 6/1/3
\(-5\left(x+\frac{1}{5}\right)-\frac{1}{2}\left(x-\frac{2}{3}\right)=\frac{3}{2}x-\frac{5}{6}\)
\(\Leftrightarrow-5x-\frac{1}{5}-\frac{1}{2}x+\frac{1}{3}=\frac{3}{2}x-\frac{5}{6}\)
\(\Leftrightarrow\left(-5x-\frac{1}{2}x\right)+\left(\frac{1}{3}-\frac{1}{5}\right)=\frac{3}{2}x-\frac{5}{6}\)
\(\Leftrightarrow\left(\frac{-10}{2}x-\frac{1}{2}x\right)+\left(\frac{5}{15}-\frac{3}{15}\right)=\frac{3}{2}x-\frac{5}{6}\)
\(\Leftrightarrow\frac{-11}{2}x+\frac{2}{15}=\frac{3}{2}x-\frac{5}{6}\)
\(\Leftrightarrow\frac{-11}{2}x-\frac{3}{2}x=-\frac{5}{6}-\frac{2}{15}\)
\(\Leftrightarrow\frac{-14}{2}x=-\frac{25}{30}-\frac{4}{30}\)
\(\Leftrightarrow-7x=-\frac{29}{30}\)
\(\Leftrightarrow x=-\frac{29}{30}\times\frac{-1}{7}\)
\(\Leftrightarrow x=\frac{29}{210}\)
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\(3\left(x-\frac{1}{2}\right)-5\left(x+\frac{3}{5}\right)=-x+\frac{1}{5}\)
\(\Leftrightarrow3x-\frac{3}{2}-5x-3=\frac{1}{5}-x\)
\(\Leftrightarrow\left(3x-5x\right)-\left(\frac{3}{2}+3\right)=\frac{1}{5}-x\)
\(\Leftrightarrow-2x-\left(\frac{3}{2}+\frac{6}{2}\right)=\frac{1}{5}-x\)
\(\Leftrightarrow-2x-\frac{9}{2}=\frac{1}{5}-x\)
\(\Leftrightarrow-2x+x=\frac{1}{5}+\frac{9}{2}\)
\(\Leftrightarrow-x=\frac{2}{10}+\frac{45}{10}\)
\(\Leftrightarrow-x=\frac{47}{10}\)
\(\Leftrightarrow x=\frac{-47}{10}\)
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\(3\left(3x-\frac{1}{2}\right)^3+\frac{1}{9}=0\)
\(\Leftrightarrow3\left(3x-\frac{1}{2}\right)^3=0-\frac{1}{9}\)
\(\Leftrightarrow3\left(3x-\frac{1}{2}\right)^3=\frac{-1}{9}\)
\(\Leftrightarrow\left(3x-\frac{1}{2}\right)^3=\frac{-1}{9}\div3\)
\(\Leftrightarrow\left(3x-\frac{1}{2}\right)^3=\frac{-1}{9}\times\frac{1}{3}\)
\(\Leftrightarrow\left(3x-\frac{1}{2}\right)^3=\frac{-1}{27}\)
\(\Leftrightarrow\left(3x-\frac{1}{2}\right)^3=\left(\frac{-1}{3}\right)^3\)
\(\Leftrightarrow3x-\frac{1}{2}=\frac{-1}{3}\)
\(\Leftrightarrow3x=\frac{-1}{3}+\frac{1}{2}\)
\(\Leftrightarrow3x=\frac{-2}{6}+\frac{3}{6}\)
\(\Leftrightarrow3x=\frac{1}{6}\)
\(\Leftrightarrow x=\frac{1}{6}\div3\)
\(\Leftrightarrow x=\frac{1}{6}\times\frac{1}{3}\)
\(\Leftrightarrow x=\frac{1}{18}\)
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60%x+2/3x=1/3.6 1/3
a)2 ngũ 3.19:24+2 ngũ 3 .5
Tìm x
a) 1/3x + 2/5( x - 1 ) = 0
b) (2x - 3 )(6 - 2x ) =0
c) 2|1/2x - 1/3 | - 3/2 = 1/4
d) 3/4 - 2 . | 2x - 2/3 | = 2
e) ( 3x - 1)(-1/2x + 5 ) = 0
g)-5(x + 1/5 ) - 1/2(x - 2/3 ) = 2/3x - 5/6
h) 3(x - 1/2 ) - 5(x + 3/5 ) = -3 + 1/5
i) 60%x + 2/3x = 1/3. 6và1/3 ( 6và1/3 là hỗn số )
