Tìm x , biết
1) x-1998 = 2002 2) x - 2012 = 2013 3) x : 18 = 25 4) x : 23 = 72
5) (135 + 2012).x=0 6) x.(1972 + 2013) = 0 7) x.(x-1) =0 8) (x-9).(x-15) = 0
tìm x
a ,x-7/4+x-6/3+x-5/3+x+81/7=0
b,x-1/2013+x-2/2012+x+3/2011+...+x-2012/2=2012
c(1/1x101=1/2x102+1/3x103+1/4x164+1/10x110)x X =(1/1x11+1/2x12+...+1/100x110)
ai nhanh mình tick
a) 2x-1/11+2x-2/12+2x-3/13=2x+5/5+2x+6/4+2x+7/3
b) x-1/2016+x-2/2015+x-3/2014+x-4/2013+x-5/2012 -5=0
c) x+2017/2+x+2015/3+x+2013/4+x+2011/5+8=0
Câu1
( x-7/4)+( x-6/3)+( x-5/2)+( x+81/7)=0
Câu2
( 1/1×101)+( 1/2×102)+( 1/3×103)+(1/10×11×X=(1/1×11)+(1/2×12)+...+(1/100×110)
Câu3
( x-1/2013)+( x-2/2012)+( x-3/2011)+...+( x-2012/2) =2012
Tìm x :
6x(1-3x)+9x(2x-7)+171=0
tập hợp x:x+1/2015+x+2/2014=x+3/2013+x+4/2012
\(6x\left(1-3x\right)+9x\left(2x-7\right)+171=0\)
\(\Leftrightarrow6x-18x^2+18x^2-63x+171=0\)
\(\Leftrightarrow-57x=-171\)
\(\Leftrightarrow x=3\)
\(\frac{x+1}{2015}+\frac{x+2}{2014}=\frac{x+3}{2013}+\frac{x+4}{2012}\)
\(\Leftrightarrow\left(\frac{x+1}{2015}+1\right)+\left(\frac{x+2}{2014}+1\right)-\left(\frac{x+3}{2013}+1\right)-\left(\frac{x+4}{2012}+1\right)=0\)
\(\Leftrightarrow\)\(\frac{x+2016}{2015}+\frac{x+2016}{2014}-\frac{x+2016}{2013}+\frac{x+2016}{2012}=0\)
\(\Leftrightarrow\left(x+2016\right)\left(\frac{1}{2015}+\frac{1}{2014}-\frac{1}{2013}-\frac{1}{2012}\right)=0\)
\(\Leftrightarrow x+2016=0\) ( vì \(\frac{1}{2015}+\frac{1}{2014}-\frac{1}{2013}-\frac{1}{2012}\ne0\) )
\(\Leftrightarrow x=-2016\)
Tìm x biết:
x+1/2014 + x+2/2013 + x+3/2012 + x+4/2011 + 4=0
x=
a) 2x-1/11+2x-2/12+2x-3/13=2x+5/5+2x+6/4+2x+7/3
b) x-1/2016+x-2/2015+x-3/2014+x-4/2013+x-5/2012 -5=0
c) x+2017/2+x+2015/3+x+2013/4+x+2011/5+8=0
giúp mình với mọi người làm ơn đi mình cần gấp lắm!!!!
a) 2x-1/11+2x-2/12+2x-3/13=2x+5/5+2x+6/4+2x+7/3
b) x-1/2016+x-2/2015+x-3/2014+x-4/2013+x-5/2012 -5=0
c) x+2017/2+x+2015/3+x+2013/4+x+2011/5+8=0
giúp mình với mọi người làm ơn đi mình cần gấp lắm!!!!
Cho x1+x2=x3+x4=x5+x6=.......=x2011=x2012=2 và x1+x2+...............+x2013=0
Tìm x2013
\(x_1+x_2+...+x_{2013}=0\)
=> \(\left(x_1+x_2\right)+\left(x_3+x_4\right)+...+\left(x_{2011}+x_{2012}\right)+x_{2013}=0\)
=> \(2+2+...+2+x_{2013}=0\)
=> \(2.1006+x_{2013}=0\Rightarrow2012+x_{2013}=0\Rightarrow x_{2013}=-2012\)
2x-1/11+2x-2/12+2x-3/13=2x+5/5+2x+6/4+2x+7/3
b) x-1/2016+x-2/2015+x-3/2014+x-4/2013+x-5/2012 -5=0
c) x+2017/2+x+2015/3+x+2013/4+x+2011/5+8=0
giúp mình với mọi người làm ơn đi mình cần gấp lắm!!!! bài nào cũng được nhé các bạn