\(\frac{-11}{12}.x+0.25=\frac{5}{6}\)
Tính giá trị của biểu thức: \(A=\left(\frac{\frac{3}{7}+\frac{3}{11}-\frac{3}{13}}{\frac{5}{7}+\frac{5}{11}-\frac{5}{13}}+\frac{0.5+\frac{1}{3}-0.25}{\frac{5}{12}-\frac{5}{6}-\frac{5}{9}}\right):\frac{2016}{2017}\)
\(\frac{10\frac{1}{3}.\left(26\frac{1}{3}-\frac{176}{7}\right)-\frac{12}{11}\left(\frac{10}{3}-1.75\right)}{\frac{5}{\left(91-0.25\right).\frac{60}{11}-1}}\)
\(\frac{10\frac{1}{3}\left(26\frac{1}{3}-\frac{176}{7}\right)-\frac{12}{11}\left(\frac{10}{3}-1,75\right)}{\frac{5}{\left(91-0,25\right).\frac{60}{11}-1}}\)
\(\Leftrightarrow\left(\frac{31}{3}.\frac{25}{21}-\frac{12}{11}.\frac{19}{12}\right):\left(5:495-1\right)\)
\(\Leftrightarrow\left(\frac{775}{63}-\frac{19}{11}\right):\left(-\frac{98}{99}\right)\)
\(\Leftrightarrow x=-\frac{3664}{343}\)
\(B=2016:\left(\frac{0.4-\frac{2}{9}+\frac{2}{11}}{1.4-\frac{7}{9}+\frac{7}{11}}.\frac{-1\frac{1}{6}+0.875-0.7}{\frac{1}{3}-0.25+\frac{1}{5}}\right)\)
\(B=2016:\left(\frac{0.4-\frac{2}{9}+\frac{2}{11}}{1.4-\frac{7}{9}+\frac{7}{11}}.\frac{-1\frac{1}{6}+0.875-0.7}{\frac{1}{3}-0.25+\frac{1}{5}}\right)\)
<=>\(B=2016:\left(\frac{\frac{2}{5}-\frac{2}{9}+\frac{2}{11}}{\frac{7}{5}-\frac{7}{9}+\frac{7}{11}}.\frac{\frac{-7}{6}+\frac{7}{8}-\frac{7}{10}}{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}\right)\)
<=>\(B=2016:\left(\frac{2.\left(\frac{1}{5}.\frac{1}{9}.\frac{1}{11}\right)}{5.\left(\frac{1}{5}.\frac{1}{9}.\frac{1}{11}\right)}.\frac{\frac{7}{6}-\frac{7}{8}-\frac{7}{10}}{\frac{2}{6}-\frac{2}{8}-\frac{2}{10}}\right)\)
<=>\(B=2016:\left(\frac{2}{5}.\frac{7.\left(\frac{1}{6}-\frac{1}{8}-\frac{1}{10}\right)}{2.\left(\frac{1}{6}-\frac{1}{8}-\frac{1}{10}\right)}\right)\)
<=>\(B=2016:\left(\frac{2}{5}.\frac{7}{2}\right)\)
<=>\(B=2016:\frac{7}{5}\)
<=>\(B=2016.\frac{5}{7}\)
<=>\(B=1440\)
Vậy B=1440
k cho mink nha
Tính nhanh: \(B=\left(\frac{0.4-\frac{2}{9}+\frac{2}{11}}{1.4-\frac{7}{9}+\frac{7}{11}}-\frac{\frac{1}{3}-0.25+\frac{1}{5}}{1\frac{1}{6}-0.875+0.7}\right):\frac{2014}{2015}\)
A=\(\left(\frac{0.4-\frac{2}{9}+\frac{2}{11}}{1.4-\frac{7}{9}+\frac{7}{11}}-\frac{\frac{1}{3}-0.25+\frac{1}{5}}{1\frac{1}{6}-0.875+0.7}\right):\left(1^2+2^2+3^2+...+2015^2\right)\)
Trả lời
\(A=\left(\frac{\frac{2}{5}-\frac{2}{9}+\frac{2}{11}}{\frac{7}{5}-\frac{7}{9}+\frac{7}{11}}-\frac{2.\left(\frac{1}{6}-\frac{1}{8}-\frac{1}{10}\right)}{\frac{7}{6}-\frac{7}{8}-\frac{7}{10}}\right):\left(1^2+2^2+...+2015^2\right).\)
\(A=\left(\frac{2}{7}-\frac{2}{7}\right):\left(1^2+2^2+3^2+...+2015^2\right)\)
\(A=0:\left(1^2+2^2+3^2+.....+2015^2\right)\)
A=0
Study well
\(A=...\)
\(=\left(\frac{\frac{2}{5}-\frac{2}{9}+\frac{2}{11}}{\frac{7}{5}-\frac{7}{9}+\frac{7}{11}}-\frac{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}{\frac{7}{6}-\frac{7}{8}+\frac{7}{10}}\right):\left(1^2+2^2+...+2015^2\right)\)
\(=\left[\frac{2\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{11}\right)}{7\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{11}\right)}-\frac{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}{\frac{7}{2}\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{5}\right)}\right]:\left(1^2+2^2+...+2015^2\right)\)
\(=\left(\frac{2}{7}-\frac{1}{\frac{7}{2}}\right):\left(1^2+2^2+...+2015^2\right)\)
\(=\left(\frac{2}{7}-\frac{2}{7}\right):\left(1^2+2^2+...+2015^2\right)\)
\(=0:\left(1^2+2^2+...+2015^2\right)=0\)
\(M=\hept{\begin{cases}0.4-\frac{2}{9}+\frac{2}{11}-\frac{1}{3}-0.25+\frac{1}{5}\\1,4-\frac{7}{9}+\frac{7}{11}-1\frac{1}{6}-0.875+0.7\end{cases}}\left\{\right\}:\frac{2012}{2013}\)
cái dấu trước dấu chia mình ko biết cách đóng ngoặc nhọn lại nên mình viết như vậy
thực hiệ phép tính
A.\(\frac{1}{4}.\frac{2}{3}-\frac{3}{2}.\frac{1}{6}+\frac{1}{12}\)
B. \(2\frac{1}{3}+2\frac{5}{7}-1\frac{1}{3}\)
C.\(\left(2\frac{1}{3}+\frac{1}{9}\right):\left(-2\frac{1}{6}+0.25\right)+1\frac{11}{69}\)
CÁC BẠN LÀM ĐC CÂU NÀO THÌ LÀM NHA
\(\frac{1}{4}.\frac{2}{3}-\frac{3}{2}.\frac{1}{6}+\frac{1}{12}\)
\(=\frac{1}{6}+\frac{-1}{4}+\frac{1}{12}\)
\(=\frac{2}{12}+\frac{-3}{12}+\frac{1}{12}=\frac{0}{12}=0\)
~ Hok tốt ~
A, \(=\frac{1}{6}-\frac{5}{3}+\frac{1}{12}\)
\(=\frac{2}{12}-\frac{20}{12}+\frac{1}{12}\)
\(=\frac{2-20+1}{12}=-\frac{17}{12}\)
Hok tốt
\(2\frac{1}{3}+2\frac{5}{7}-1\frac{1}{3}\)
\(=\frac{7}{3}+\frac{19}{7}+\frac{-4}{3}\)
\(=\left(\frac{7}{3}+\frac{-4}{3}\right)+\frac{19}{7}\)
\(=1+\frac{19}{7}\)
\(=\frac{26}{7}\)
~ Hok tốt ~
a,\(\frac{1}{2}-\left(\frac{-2}{5}\right)+\frac{1}{3}+\frac{5}{7}-\left(\frac{-1}{6}\right)+\frac{-4}{35}+\frac{1}{41}\)
b,\(0,75.\frac{3}{37}-\frac{3}{4}.\frac{29}{37}-\frac{15}{20}.\frac{11}{37}-0.25\)
tính A= 10\(\frac{1}{3}\)(26\(\frac{1}{7}\).\(\frac{176}{7}\))-\(\frac{12}{11}\)(\(\frac{10}{3}\)-1.75) /(\(\frac{5}{91}\)-0.25).\(\frac{60}{11}\)-1