26 x 84 + 74 x 85

= 26 x 84 + 74 x 84 + 74

= 84 x (26 + 74) + 74

= 84 x 100 + 74

= 840 + 74

= 914

\(\frac{2017\times2018+2019}{2019\times2018-2017}\)

= \(\frac{2019\times2018-2\times2018+2019}{2019\times2018-2017}\)

= \(\frac{2019\times2018-4036+2019}{2019\times2018-2017}\)

= \(\frac{2019\times2018-2017}{2019\times2018-2017}\)

= 1

dung may tinh la duoc roi

Dùng máy tính đó

Hoặc động cái não mà nghĩ đi với

nhân chia trước cộng trừ sau
cứ thế mà tính

nhanh nhanh các bạn ơi

26x84+74x85=8474

2017x2018+2019/2019x2018-2017=4070307

câu trả lời đấy cu

\(\frac{x-4}{2021}+\frac{x-3}{2020}=\frac{x-2}{2019}+\frac{x-1}{2018}\)

\(\Leftrightarrow\left(\frac{x-4}{2021}+1\right)+\left(\frac{x-3}{2020}+1\right)=\left(\frac{x-2}{2019}+1\right)+\left(\frac{x-1}{2018}+1\right)\)

\(\Leftrightarrow\frac{x+2017}{2021}+\frac{x+2017}{2020}=\frac{x+2017}{2019}+\frac{x+2017}{2018}\)

\(\Leftrightarrow\frac{x+2017}{2021}+\frac{x+2017}{2020}-\frac{x+2017}{2019}-\frac{x+2017}{2018}=0\)

\(\Leftrightarrow\left(x+2017\right)\left(\frac{1}{2021}+\frac{1}{2020}-\frac{1}{2019}-\frac{1}{2018}\right)=0\)

Mà \(\left(\frac{1}{2021}+\frac{1}{2020}-\frac{1}{2019}-\frac{1}{2018}\right)\ne0\)

\(\Leftrightarrow x+2017=0\)

\(\Leftrightarrow x=-2017\)

Vậy ..

=> (x-4/2021 +1) + (x-3/2020 +1) = (x-2/2019 +1)+ (x-1/2018 +1)

=> x+2017/2021 + x+2017/2020 = x+2017/2019 + x+2017/2018

=> x+2017/2018 + x+2017/2018 - x+2017/2020 - x+2017/2021 = 0

=> (x+2017).(1/2018+1/2019+1/2020+1/2021) = 0

=> x+2017 = 0 ( vì 1/2018+1/2019+1/2020+1/2021 > 0 )

=> x=-2017

Vậy x=-2017

k mk nha

\(\frac{x-4}{2021}+\frac{x-3}{2020}=\frac{x-2}{2019}+\frac{x-1}{2018}\)

\(\left(\frac{x-4}{2021}+1\right)+\left(\frac{x-3}{2020}+1\right)=\left(\frac{x-2}{2019}+1\right)+\left(\frac{x-1}{2018}+1\right)\)

\(\frac{x-2017}{2021}+\frac{x-2017}{2020}=\frac{x-2017}{2019}+\frac{x-2017}{2018}\)

\(\frac{x-2017}{2021}+\frac{x-2017}{2020}-\frac{x-2017}{2019}-\frac{x-2017}{2018}=0\)

\(\left(x-2017\right).\left(\frac{1}{2021}+\frac{1}{2020}-\frac{1}{2019}-\frac{1}{2018}\right)=0\)

vì \(\frac{1}{2021}+\frac{1}{2020}-\frac{1}{2019}-\frac{1}{2018}\ne0\)nên x - 2017 = 0 \(\Rightarrow\)x = 2017

a, 2x+2y/x+y=2

=> 2(x+y)/x+y=2

=>2/1=2

=> đpcm

Câu b thì mình nghĩ nó không thể bằng được đâu bạn

Đề bài sai nha:\(x^{2019}\times y^{2018}\)Ko phải chia đâu

\(\hept{\begin{cases}\left(x+1\right)^{2018}\ge0\\\left|y-1\right|\ge0\end{cases}}\Rightarrow\left(x+1\right)^{2018}+\left|y-1\right|\ge0\)

dấu = xảy ra khi \(\hept{\begin{cases}\left(x+1\right)^{2018}=0\\\left|y-1\right|=0\end{cases}}\Rightarrow\hept{\begin{cases}x+1=0\\y-1=0\end{cases}\Rightarrow\hept{\begin{cases}x=-1\\y=1\end{cases}}}\)

\(P=x^{2019}.y^{2018}=\left(-1\right)^{2019}.1^{2018}=-1.1=-1\)

\(\dfrac{2020}{2019}-\dfrac{2019}{2018}+\dfrac{1}{2019}x2018\)
\(=\dfrac{2020}{2019}-\dfrac{2019}{2018}+\dfrac{2018}{2019}=2-\dfrac{2019}{2018}=\dfrac{2017}{2018}\)

Ta có : x = 99

=> 100 = x + 1 

Thay vào A ta có : A = x²⁰¹⁸ - 100x²⁰¹⁷ + 100x²⁰¹⁶ - ...... + 100x² - 100x + 2019

=> A = x²⁰¹⁸ - (x + 1)x²⁰¹⁷ + (x + 1)x²⁰¹⁶ - ...... + (x + 1)x² - (x + 1)x + 2019

=> A = x²⁰¹⁸ - x²⁰¹⁸ - x²⁰¹⁷ + x²⁰¹⁷ + x²⁰¹⁶ -.......+ x³ + x² - x² + x + 2019

=> A = x + 2019

=> A = 99 + 2019

=> A = 2118

P/s : ko cần ! :D 

Theo đề bài ra ta có :

x = 99  

Thay vào A ta có :

A = x²⁰¹⁸ - 100x²⁰¹⁷ + 100x²⁰¹⁶ - ... + 100x² - 100x + 2019

\(\Rightarrow\) A = x²⁰¹⁸ - ( x + 1 ) x²⁰¹⁷ + ( x + 1 ) x²⁰¹⁶ - ... + ( x + 1 ) x² - ( x + 1 ) x + 2019

\(\Rightarrow\) A = x²⁰¹⁸ - x²⁰¹⁸ - x²⁰¹⁷ + x²⁰¹⁷ + x²⁰¹⁶- ... + x³ + x² - x² + x + 2019

\(\Rightarrow\) A = x + 2019

\(\Rightarrow\) A = 99 + 2019

\(\Rightarrow\) A = 2118 

a)

Ta có \(\dfrac{2x+2y}{x+y}=\dfrac{2\left(x+y\right)}{x+y}=2\)

\(\left(x+y\ne0\right)\)

b) Cậu xem lại đề nhé, sai rồi kìa