Với x>0

\(\Rightarrow x+2016+x+2017+2018=3x\)

\(\Rightarrow x=2016+2017+2018\)

\(\Rightarrow x=6051\)(t/m)

Với x<0

\(\Rightarrow2016-x+2017-x+2018=3x\)

\(\Rightarrow6051-2x=3x\)

\(\Rightarrow x=\frac{6051}{5}\)(loại)

       | x+2016 | + | x+2017 |+2018=3x

\(\Rightarrow\)x + 2016 + x + 2017 = 2018

\(\Rightarrow\)x2 + 2016 + 2017 + 2018 = 3x

\(\Rightarrow\)x2 + 6051 = 3x

\(\Rightarrow\)3x - 2x = 6051

\(\Rightarrow\)1x =6051

\(\Rightarrow\)x = 6051

Bạn Đạt cho mink hỏi tí t/m là gì

Ta có: \(\frac{x-2019}{2018}+\frac{x-2018}{2017}=\frac{x-2017}{2016}+\frac{x-2016}{2015}\)

\(\Leftrightarrow\left(\frac{x-2019}{2018}+1\right)+\left(\frac{x-2018}{2017}+1\right)=\left(\frac{x-2017}{2016}+1\right)+\left(\frac{x-2016}{2015}+1\right)\)

\(\Leftrightarrow\frac{x-1}{2018}+\frac{x-1}{2017}=\frac{x-1}{2016}+\frac{x-1}{2015}\)

\(\Leftrightarrow\frac{x-1}{2018}+\frac{x-1}{2017}-\frac{x-1}{2016}-\frac{x-1}{2015}=0\)

\(\Leftrightarrow\left(x-1\right)\left(\frac{1}{2018}+\frac{1}{2017}-\frac{1}{2016}-\frac{1}{2015}\right)=0\)

\(\Leftrightarrow x-1=0\)( vì \(\frac{1}{2018}+\frac{1}{2017}-\frac{1}{2016}-\frac{1}{2015}\ne0\))

\(\Leftrightarrow x=1\)

Vạy x=1

vế trái dương =>x>0

<=>x+2016+x+2017+2018=3x

x=2016+2017+2018=3.2017

\(|x+2016|+|x+2017|+2018=3x\)

\(x=2016+2017+2018\)\(\Rightarrow x=6051\)

|x+2016|+|x+2017|+2018=3x

<=>  x + 2016 + x + 2017 + 2018 = 3x

<=> x + x - 3x                                = -2018 -2017-2016

<=>  (1 + 1 - 3) x                           =   - 6051 

<=>      -1x                                    =  -6051

<=>        x                                     =\(\frac{-6051}{-1}\)

<=>      x                                       =  6051 

Đáp án là : 

Tìm x : 

x = -2019 

x= -2019