7/9:(2+3/4x)+5/9=23/27
a) 2/5 + 3/5 . ( 3x - 3,7 ) = -53/10
b) 7/9 : ( 2 + 3/4x ) + 5/9 = 23/27
a) \(\frac{2}{5}+\frac{3}{5}.\left(3x-3,7\right)=\frac{-53}{10}\)
=> \(\frac{3}{5}.\left(3x-3,7\right)=\frac{-53}{10}-\frac{2}{5}\)
=> \(\frac{3}{5}.\left(3x-3,7\right)=\frac{-57}{10}\)
=> \(\left(3x-3,7\right)=\frac{-19}{5}\)
=>\(3x=\frac{-19}{5}+\frac{37}{10}\)
=>\(3x=\frac{-1}{10}\)
=>\(x=\frac{-1}{30}\)
Ko biết đúng hay sai!!?
Tìm x biết :
7/9 : ( 2 + 3/4x ) + 5/9 = 23/ 27
7/9 : ( 2 + 3/4 x) + 5/9 = 23/27
7/9 : ( 2 + 3/4 x) = 23/27 - 5/9 = 8/27
2 + 3/4 x= 7/9 : 8/27 = 21/8
3/4x = 21/8 - 2 = 5/8
=> x = 5/8 : 3/4 = 5/6
=)7/9:(2+3/4x)=8/27
=)2+3/4x=21/8
=)3/4x=5/8
=)x=5/6
7/9 : (2 + 3/4x) +5/9 = 23/27
tìm x nha các bạn
\(\frac{7}{9}:\left(1+\frac{3}{4}x\right)+\frac{5}{9}=\frac{23}{27}\)
\(\frac{7}{9}:\left(1+\frac{3}{4}x\right)=\frac{8}{27}\)
\(\left(1+\frac{3}{4}x\right)=\frac{21}{8}\)
\(\frac{3}{4}x=\frac{13}{8}\)
\(x=\frac{13}{8}:\frac{3}{4}\)
\(x=\frac{13}{6}\)
Vậy \(x=\frac{13}{6}\)
\(\frac{7}{9}:\left(2+\frac{3}{4}x\right)+\frac{5}{9}=\frac{23}{27}\)
\(\frac{7}{9}:\left(2+\frac{3}{4}x\right)=\frac{23}{27}-\frac{5}{9}\)
\(2+\frac{3}{4}x=\frac{7}{9}:\frac{8}{27}=\frac{21}{8}\)
\(\frac{3}{4}x=\frac{21}{8}-2=\frac{5}{8}\)
\(x=\frac{5}{8}:\frac{3}{4}=\frac{5}{6}\)
Vậy x=5/6
2/3x-3/2x=5/12
b)2/5+3/5.(3x-3,7)=-53/10
c)7/9:(2+3/4x)+5/9=23/27
a) \(x=-\frac{1}{2}\)
b) \(x=-\frac{29}{15}\)
c) \(x=\frac{5}{6}\)
**** cho mình nhé
\(7/9:(2+3/4x)+5/9=23/27\)
Giúp mk nha ....
Mk c.ơn
7/9:(2+3/4x)=23/27-5/9
7/9:(2+3/4x)=8/27
2+3/4x=7/9:8/27
2+3/4x=21/8
3/4x=21/8-2
3/4x=5/8
x=5/8:3/4
x=5/6
\(\frac{7}{9}:\left(2+\frac{3}{4}x\right)+\frac{5}{9}=\frac{23}{27}\)
\(\Rightarrow\left(2+\frac{3}{4}x\right)+\frac{5}{9}=\frac{7}{9}:\frac{23}{27}=\frac{21}{23}\)
\(\Rightarrow2+\frac{3}{4}x=\frac{21}{23}-\frac{5}{9}=\frac{74}{207}\)
\(\Rightarrow\frac{3}{4}x=2-\frac{74}{207}=\frac{340}{207}\)
\(\Rightarrow x=\frac{340}{207}:\frac{3}{4}\)
\(\Rightarrow x=\frac{1360}{621}\)
Sr nãy nhầm >:(
\(\frac{7}{9}:\left(2+\frac{3}{4}x\right)+\frac{5}{9}=\frac{23}{27}\)
\(\Rightarrow\frac{7}{9}:\left(2+\frac{3}{4}x\right)=\frac{23}{27}-\frac{5}{9}=\frac{8}{27}\)
\(\Rightarrow2+\frac{3}{4}x=\frac{7}{9}:\frac{8}{27}=\frac{21}{8}\)
\(\Rightarrow\frac{3}{4}x=\frac{21}{8}-2=\frac{5}{8}\)
\(\Rightarrow x=\frac{5}{8}:\frac{3}{4}\)
\(\Rightarrow x=\frac{5}{6}\)
tìm x
a) x.3/1/4+(-7/6).x-1/2/3=5/12
b)2/5+3/5.(3x-3,7)=-53/10
c)7/9:(2+3/4x)+5/9=23/27
a,x.3\(\dfrac{1}{4}\)+(\(\dfrac{-7}{6}\)).x-1\(\dfrac{2}{3}\)=\(\dfrac{5}{12}\)
\(\Leftrightarrow\)\(\dfrac{13}{4}\)x+(\(\dfrac{-7}{6}\))x-\(\dfrac{5}{3}\)=\(\dfrac{5}{12}\)
\(\Leftrightarrow\)\(\dfrac{13}{4}\)x+(\(\dfrac{-7}{6}\))x=\(\dfrac{25}{12}\)
\(\Leftrightarrow\)\(\dfrac{25}{12}\)x=\(\dfrac{25}{12}\)
\(\Leftrightarrow\)x=1
Vậy x=1
b,\(\dfrac{2}{5}\)+\(\dfrac{3}{5}\).(3x-3,7)=\(\dfrac{-53}{10}\)
\(\Leftrightarrow\)\(\dfrac{3}{5}\).(3x-3,7)=\(\dfrac{-53}{10}\)-\(\dfrac{2}{5}\)
\(\Leftrightarrow\)\(\dfrac{9}{5}\)x-\(\dfrac{111}{50}\)=\(\dfrac{-57}{10}\)
\(\Leftrightarrow\)\(\dfrac{9}{5}\)x=\(\dfrac{-87}{25}\)
\(\Leftrightarrow\)x=\(\dfrac{-29}{15}\)
Vậy x=\(\dfrac{-29}{15}\)
c,\(\dfrac{7}{9}\):(2+\(\dfrac{3}{4}\)x)+\(\dfrac{5}{9}\)=\(\dfrac{23}{27}\)
\(\Leftrightarrow\)\(\dfrac{7}{9}\):(2+\(\dfrac{3}{4}\)x)=\(\dfrac{8}{27}\)
\(\Leftrightarrow\)\(\dfrac{7}{18}\)+\(\dfrac{28}{27}\)x=\(\dfrac{8}{27}\)
\(\Leftrightarrow\)\(\dfrac{28}{27}\)x=\(\dfrac{-5}{54}\)
\(\Leftrightarrow\)x=\(\dfrac{-5}{56}\)
Vậy x=\(\dfrac{-5}{56}\)
Bài 2. > , < , = ?
5/7… 4/3 2/5 …… 6/10 1/4 …… 3/12 27/36 ….. 2/9 7/6 …… 7/9
7/2 …… 2/7 15/23........1 27/9.......2 14/15........1 51/17........4
Bài 2. > , < , = ?
5/7 < 4/3 2/5 < 6/10 1/4 = 3/12 27/36 >
2/9 7/6 > 7/9
7/2 = 2/7 15/23 < 1 27/9 > 2 14/15 < 1 51/17 < 4
Tìm x biết:
2/5 + 3/5.(3x - 3,7) = -53/10
7/9 : (2+3/4x)+ 5/9 = 23/27
-2/3 . x + 1/5 = 3/10
|x| - 3/4 = 5/3
|2x- 1/3| + 5/6 = 1
4.x=29/12;-29/12
Câu cuối ban viết rõ lên nhé
\(a,\dfrac{3}{5}+\dfrac{-5}{9}\)
\(b,\dfrac{1}{3}+\dfrac{-4}{3};\dfrac{4}{7}\)
\(c,-\dfrac{27}{23}+\dfrac{5}{21}+\dfrac{4}{23}+\dfrac{16}{21}+\dfrac{1}{2}\)
\(d,\dfrac{-8}{9}+\dfrac{1}{9}.\dfrac{2}{9}+\dfrac{1}{9}.\dfrac{7}{9}\)
\(a,\dfrac{3}{5}+\dfrac{-5}{9}=\dfrac{27-25}{45}=\dfrac{2}{49}.\)
\(c,\dfrac{-27}{23}+\dfrac{5}{21}+\dfrac{4}{23}+\dfrac{16}{21}+\dfrac{1}{2}=\dfrac{-23}{23}+\dfrac{21}{21}+\dfrac{1}{2}=-1+1+\dfrac{1}{2}=\dfrac{1}{2}.\)
\(d,\dfrac{-8}{9}+\dfrac{1}{9}.\dfrac{2}{9}+\dfrac{1}{9}.\dfrac{7}{9}=\dfrac{-8}{9}+\dfrac{1}{9}.\left(\dfrac{2}{9}+\dfrac{7}{9}\right)=\dfrac{-8}{9}+\dfrac{1}{9}.1=\dfrac{-8+1}{9}=\dfrac{-7}{9}.\)