\(729=\frac{x^8}{9}\)
\(729=\frac{x^8}{9}\)
Tìm x,biết:
a) \(\frac{x^7}{81}\) = 27
b) \(\frac{x^8}{9}\) 729
a) Ta có: \(\frac{x^7}{81}=27\)
\(\Rightarrow x^7=27.81=2187\)
Mà \(2187=3^7\) \(\Rightarrow x^7=3^7\Leftrightarrow x=3\)
Vậy x = 3
b) Ta có: \(\frac{x^8}{9}=729\)
\(\Rightarrow x^8=729.9=6561\)
Mà \(6561=3^8\) \(\Rightarrow x^8=3^8\Leftrightarrow x=3\)
Vậy x = 3
CHÚC BẠN HỌC TỐT
\(\frac{x^7}{81}=27\Rightarrow27.81=x^7\Rightarrow x=3\)
\(\frac{x^8}{9}=729\Rightarrow x^8=729.9\Rightarrow x=3\)
tíc mình
nha
\(a.\)\(\frac{x^7}{81}=27\)
\(\Rightarrow x^7=27.81\)
\(\Leftrightarrow x^7=2187\)
\(\Leftrightarrow x^7=3^7\)
\(\Leftrightarrow x=3\)
\(b.\)\(\frac{x^8}{9}=729\)
\(\Rightarrow x^8=729.9\)
\(\Leftrightarrow x^8=6561\)
\(\Leftrightarrow x^8=3^8\)
\(\Leftrightarrow x=3\)
Vậy : Ở cả 2 câu x đều bằng 3 nhé.
~ Rất vui vì giúp đc bn ~
tinh
\(\frac{\text{2181 x 729 + 243 x 81 x 27}}{\text{3^2 x 9^2 x 243 +18 x 54 x 162 x 9 +723 x 729}}\)
KQ=1165795659
minh tinh may tinh ko sai dau
k cho minh nhe
Tìm x sao cho x^8/9=729
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\(\frac{x^8}{9}=729\Leftrightarrow x^8=729.9\)
\(\Leftrightarrow x^8=6561\)
\(\Leftrightarrow x^8=\left(\pm3\right)^8\)
\(\Rightarrow x=3;-3\)
Nếu bạn chưa học số âm thì\(x=3\)
Học rồi toán lớp 7 mà pham trung thanh
Thanks^_^
a) \(\left(2x+3\right)^2=\frac{9}{144}\)
\(\Leftrightarrow\left(2x+3\right)^2=\left(\frac{1}{4}\right)^2=\left(-\frac{1}{4}\right)^2\)
\(\Rightarrow\orbr{\begin{cases}2x+3=\frac{1}{4}\\2x+3=\frac{-1}{4}\end{cases}\Leftrightarrow\orbr{\begin{cases}2x=\frac{-11}{4}\\2x=\frac{-13}{4}\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=\frac{-11}{8}\\x=\frac{-13}{8}\end{cases}}}\)
Vậy ...
b) Ta có: \(\left(3x-1\right)^3=\frac{-8}{27}=\left(\frac{-2}{3}\right)^3\)
\(\Leftrightarrow3x-1=\frac{-2}{3}\Leftrightarrow3x=\frac{1}{3}\Leftrightarrow x=\frac{1}{9}\)
Vậy ....
c) \(x^{10}=25x^8\Leftrightarrow x^{10}:x^8=25\Leftrightarrow x^2=25\Leftrightarrow x=\left\{5;-5\right\}\)
Vậy ...
d) \(\frac{x^7}{81}=27\Leftrightarrow x^7=27.81=2187\)
Mà 37 = 2187 => x7 = 37 => x = 3
Vậy ....
e) \(\frac{x^8}{9}=729\Leftrightarrow x^8=729.9=6561\)
Mà 38 = (-3)8 = 6561
=> x8 = 38 = (-3)8
=> x = {-3;3}
Vậy ...
x^7/81 = 27
x^8/9= 729
\(\frac{x^7}{81}\) = 27
x7 : 81 = 27
x7 = 27 . 81 = 33 . 34
x7 = 37
Suy ra : x = 3
Bài 2 :
\(\frac{x^8}{9}\) = 729
x8 : 9 = 729
x8 = 729 . 9
x8 = 36 . 32
x8 = 38
Suy ra : x = 3
x8/9=729
tìm x
\(\frac{x^8}{9}=729\)
\(x^8=729\times9\)
\(x^8=6561\)
\(x^8=3^8\)
\(\Rightarrow x=3\)
Vậy \(x=3\).
\(\frac{x^8}{9}=729\)
\(x^8=729.9\)
\(x^8=6561\)
\(x^8=3^8\)
\(\Rightarrow x=3\)
k imk nha
x8/9=729
x8=729.9
x8=6561
x8=38
=>x=3
k mik nhé
Tìm x, biết:
a, x^7/81 = 27
b, x^8/9 = 729
a) \(\frac{x^7}{81}=27\)
=> x7 = 27.81
=> x7 = 33.34
=> x7 = 37
=> x = 3
Vậy x = 3
b) \(\frac{x^8}{9}=729\)
=> x8 = 729.9
=> x8 = 36.32
=> x8 = 38 = (-3)8
=> \(x\in\left\{3;-3\right\}\)
Vậy \(x\in\left\{3;-3\right\}\)
tìm x biết : a,\(\frac{x^7}{81}=27\); b,\(\frac{x^8}{9}=729\); c.\(^{\left[x-\frac{1}{2}\right]^0}\); d,\(\left[X-2\right]^2=1\); e, \(\left[2X-1\right]^3=8\); f,\(\left[X+\frac{1}{2}\right]^2\)=\(\frac{1}{16}\)