cho 2011 số tự nhiên x₁;x₂;...;x₂₀₁₁ thỏa mãn đk:

\(\frac{1}{x_1^{11}}+\frac{1}{x_2^{11}}+...+\frac{1}{x_{2011}^{11}}=\frac{2011}{2048}\)  tính:

M=\(\frac{1}{x_1^1}+\frac{1}{x_2^2}+...+\frac{1}{x_{2011}^{2011}}\)

\(\frac{x_1-1}{2010}=\frac{x_2-2}{2009}=.....=\frac{x_{2010}-2010}{1}\)va \(x_1+x_2+x_3+...+x_{2011}=2\left(1+2+3+...+2011\right)\)

tìm \(x_1;x_2;x_3;......;x_{2011}\) biet 

\(\frac{x_1-1}{2010}=\frac{x_2-2}{2009}=.....=\frac{x_{2010}-2010}{1}\)va \(x_1+x_2+.....+x_{2011}=2\left(1+2+3+...+2010\right)\)

cho 2011 số tự nhiên x₁,x₂,x₃,....,x₂₀₁₁ thỏa mãn điều kiện 

\(\frac{1}{^{x^{11}}_1}+\frac{1}{_2x^{11}}+.....+\frac{1}{_{2011}x^{11}}=\frac{2011}{2048}\) tính tổng 

\(\frac{1}{_1x^1}+\frac{1}{_2x^2}+....+\frac{1}{_{2011}x^{2011}}\)

tìm \(x_1;x_2;x_3;......;x_{2011}\) biet 

\(\frac{x_1-1}{2010}=\frac{x_2-2}{2009}=.....=\frac{x_{2010}-2010}{1}\)va \(x_1+x_2+.....+x_{2011}=2\left(1+2+3+...+2010\right)\)

tìm \(x_1;x_2;x_3;......;x_{2011}\) biet 

\(\frac{x_1-1}{2010}=\frac{x_2-2}{2009}=.....=\frac{x_{2010}-2010}{1}\)va \(x_1+x_2+.....+x_{2011}=2\left(1+2+3+...+2010\right)\)

tìm \(x_1,x_2,x_3.......,x_9\)

\(\frac{x_{1-1}}{9}=\frac{x_{2-2}}{8}=\frac{x_3-3}{7}=....=\frac{x_{9-9}}{1}\) và \(x_1+x_2+x_3+...+x_9=90\)

Cho: 

\(\frac{x_1-1}{2017}=\frac{x_2-2}{2016}=\frac{x_3-3}{2015}=...=\frac{x_{2017}-2017}{1}vàx_1+x_2+...+x_{2017=2017\cdot2018.}Tìmx_1,x_2,x_{3,...,x_{2017}?}\)

Tìm các số \(x_1,x_2,...,x_{n-1},x_n\), biết rằng:
\(\frac{x_1}{a_1}=\frac{x_2}{a_2}=\frac{x_3}{a_3}=....=\frac{x_{n-1}}{a_{n-1}}=\frac{x_n}{a_n}\)và \(x_1+x_2+x_3+...+x_n=c\)
\(\left(a_1\ne0,a_2\ne0,....,a_n\ne0,a_1+a_2+....+a_n\ne0\right)\)