tim gia tri cua a de nghiem cua pt
\(\frac{a^2-4}{2x-5}=2+a\) la so nguyen duong nhung nho hon 2
cho m la so nguyen duong nho hon 30. co bao nhieu gia tri cua m de da thuc x2+mx+72 la tich cua 2 da thuc bac nhat voi he so nguyen ?
hai so nguyen duong x,y co tong la 51
a tim gia tri lon nhat cua x.y
b tim gia tri nho nhat cua tich x,y, biet rang x va y deu lon hon 1
Cho truoc diem a va duong thang d di qua diem a ve 2018 duong thang phan biet . goi x la so duong thang vuong goc voi d, y la so duong thang khong vuong goc void trong 2018 duong thang da cho..
Tim gia tri nguyen lon nhat cua x, y
Tim gia tri nguyen nho nhat cua x,y
cho phan thuc 4x-4/2x^2-2 :
a) Tim dieu kiem xac dinh
b)cho gia tri cua x=-2 tinh phan thuc
c) Tim gia tri cua x de gia tri phan thuc la so nguyen
Phân thức xác định
\(\Leftrightarrow2x^2-2\ne0\)
\(\Leftrightarrow2\left(x^2-1\right)\ne0\)
\(\Leftrightarrow\left(x-1\right)\left(x+1\right)\ne0\)
\(\Leftrightarrow\hept{\begin{cases}x-1\ne0\\x+1\ne0\end{cases}}\Leftrightarrow\hept{\begin{cases}x\ne1\\x\ne-1\end{cases}}\)
Vậy phân thức xác định \(\Leftrightarrow\hept{\begin{cases}x\ne1\\x\ne-1\end{cases}}\)
Đặt \(A=\frac{4x-4}{2x^2-2}=\frac{4\left(x-1\right)}{2\left(x^2-1\right)}=\frac{2\left(x-1\right)}{\left(x-1\right)\left(x+1\right)}=\frac{2}{x+1}\)
Thay x=-2 vào A ta có: \(A=\frac{2}{-2+1}=\frac{2}{-1}=-2\)
Vậy \(A=-2\)tại x=-2
Ta có: \(x\in Z\Rightarrow x+1\in Z\)
\(A\in Z\Leftrightarrow\left(x+1\right)\in\text{Ư}\left(2\right)=\left\{\pm1;\pm2\right\}\)
đến đây b tự làm nhé~
Tim cac gia tri nguyen cua x de cac gia tri bieu thuc sau la so nguyen
a, 9-2x/x-3
b,3x-5/x-2
c,-3/4-x
Cho A=n+3/n+2 voi n€z
a)tim dieu kien cua so nguyen n de A la phan so
b)tinh gia tri cua phan so A khi n=1;n=-1
c)tim so nguyen n de phan so A co gia tri la so nguyen
gia tri cua a de pt a(x-1)/5+6x-17/10+2-3x/4=0 vo nghiem la a=?
tim cac gia tri nguyen cua x de cac gia tri bieu thuc sau la so nguyen
a,9-2x/x-3
b,3x-5/x-2
c,-3/4-x
tim cac gia tri nguyen cua x de gia tri bieu thuc y=2x^2+1/2x-1 la so nguyen