= 1 nha

giải ra luôn

\(\frac{2003\cdot2005+200}{2004\cdot2004+199}\)=  \(\frac{4016015+200}{4016016+199}\)  =  \(\frac{4016215}{4016215}\)  = 1

Chúc bạn Hk tốt!!!!!

2003x2005+200=4016215

2004x2004+199=4016215

= 4016215

=4016215

(2004-1)(2004+1)+200/2004.2004+199

=2004^2-1+200/2004^2+199

=2004^2+199/2004^2+199

=1

\(\frac{2003.2005+200}{2004.2004+199}\)

= \(\frac{2003.\left(2004+1\right)+200}{\left(2003+1\right).2004+199}\)

= \(\frac{2003.2004+2003+200}{2003.2004+2004+199}\)

= \(\frac{2003.2004+2203}{2003.2004+2203}\)

= \(1\)

                 ~~~~Hok tốt~~~~

Dấu ^ có nghĩa là gì vậy bạn

S = ( 1 + 2 - 3 - 4 ) + ( 5 + 6 - 7 - 8 ) + ... + ( 2001 + 2001 - 2003 - 2004 ) + ( 2005 + 2006 )

S = ( - 4 ) + ( - 4 ) + .... + ( - 4 ) + ( 2005 + 2006 )

Dãy S có : 2004 - 1 : 1 + 1 = 2004 số hạng

Dãy số S : 2004 : 4  = 501 số ( - 4 )

Dãy đó S = -4 x 501 = -2004 

S = -2004 + ( 2005 + 2006 ) 

S = -2004 + 4011

S = 2007

(4367+3633)-(501+199)=8000-700=7300 dốt vừa thôi em nhé!

Thằng Kiệt mất dạy!

\(\frac{2004\times13+1990+2002\times2003}{2003+2003\times501+506\times2003}=\frac{2004\times13+1990+2002}{\left(2003+1\right)\times501+506}=\frac{2004\times4205}{2004\times1007}=\frac{4205}{1007}\)

y=\(\frac{2006x2005-1}{2004x2006+2005}=\frac{2006x2005-1}{\left(2005-1\right)x2006+2005}=\frac{2006x2005-1}{2005x2006-2006+2005}=\frac{2006x2005-1}{2005x2006-1}=1\)

2003x2005+\(\frac{200}{2004}\)x2004+199

=2003x2005+\(\frac{200x2004}{2004}\)+199

=4016015+200+199

=4016414

=199x3+199x7

=199x(3+7)

=199x10

=1990

hok tốt

= 199 x ( 3 + 7 )

= 199 x 10

= 1990

 199 + 199 + 199 + 199 x 7

=  199 x 1 + 199 x 1 + 199 x 1 + 199 x 7

= 199 x ( 1 + 1 + 1 + 7 )

= 199 x 10

= 1990

 Hok tốt