con lon ct dg hong

\(\frac{x-1}{21}=\frac{3}{x+1}\)

=> \(\left(x-1\right)\left(x+1\right)=21\cdot3\)

=> \(x^2-1=63\)

=> \(x^2=64\)

=> \(\orbr{\begin{cases}x^2=8^2\\x^2=\left(-8\right)^2\end{cases}\Rightarrow}\orbr{\begin{cases}x=8\\x=-8\end{cases}}\)

\(2\frac{7}{9}-\frac{12}{13}x=\frac{7}{9}\)

=> \(\frac{12}{13}x=2\)

=> \(x=\frac{13}{6}\)

d, \(\frac{x-1}{21}=\frac{3}{x+1}\)

\(\Leftrightarrow\left(x-1\right)\left(x+1\right)=63\)

\(\Leftrightarrow x^2-1=63\Leftrightarrow x^2=64\Leftrightarrow x=\pm8\)

e, \(2\frac{7}{9}-\frac{12}{13}x=\frac{7}{9}\)

\(\Leftrightarrow\frac{12}{13}x=2\Leftrightarrow x=\frac{13}{6}\)

-5.(x+1/5) -1/2.(x-2/3)=3/2x-5/6

-5x + (-1) -1/2x -1/3=3/2x-5/6

-5x-1/2x-3/2x=1+1/3-5/6

x.(-5-1/2-3/2)= 6/6+2/6+(-5/6)

x.(-10/2+(-1/2)+(-3/2))=3/6

x.6/2=1/2

x=1/2:6/2

x=1/6

Vậy x = 1/6

Biến x đâu bạn ?

-1/5

nha

>: kệ đề bài nhá, bài cho j lm cái đó.

a, \(\frac{-5}{7}+\frac{3}{4}+\frac{-1}{5}+\frac{-2}{7}+\frac{1}{4}\)

\(\frac{-5}{7}+\frac{3}{4}-\frac{1}{5}-\frac{2}{7}+\frac{1}{4}=-1+1-\frac{1}{5}=-\frac{1}{5}\)

b, \(\frac{-3}{31}+\frac{-6}{17}+\frac{1}{25}+\frac{-28}{31}+\frac{-11}{17}+\frac{-1}{5}\)

\(=\frac{-3}{31}-\frac{6}{17}+\frac{1}{25}-\frac{28}{31}-\frac{11}{17}-\frac{1}{5}=-1-1-\frac{4}{25}==-2-\frac{4}{25}=-\frac{54}{25}\)

Sai j sửa hộ.