a, 1/210+1/240+1/272+1/306

= 1/14.15 + 1/15.16 + 1/16.17 +1/17.18

= 1/14 - 1/15 + 1/15 - 1/16  +1/16 - 1/17 + 1/17 - 1/18 

= 1/14 - 1/18 = 1/63 

a) \(\frac{1}{210}+\frac{1}{240}+\frac{1}{272}+\frac{1}{306}\)

=\(\frac{1}{14.15}+\frac{1}{15.16}+\frac{1}{16.17}+\frac{1}{17.18}\)

=\(\frac{1}{14}-\frac{1}{15}+\frac{1}{15}-\frac{1}{16}+\frac{1}{16}-\frac{1}{17}+\frac{1}{17}-\frac{1}{18}\)

=\(\frac{1}{14}-\frac{1}{18}=\frac{1}{63}\)

b)\(\frac{191}{210}+\frac{161}{240}+\frac{129}{272}+\frac{95}{306}\)

=\(\frac{191}{14.15}+\frac{161}{15.16}+\frac{129}{16.17}+\frac{95}{17.18}\)

=\(\frac{191}{14}-\frac{191}{15}+\frac{161}{15}-\frac{161}{16}+\frac{129}{16}-\frac{129}{17}+\frac{95}{17}-\frac{95}{18}\)

 tự làm tiếp

1/210+1/240+1/272+1/306

=1/112+1/272+1/306

=3/238+1/306

=1/63

\(\frac{49}{5360}\)+\(\frac{1}{272}\)+\(\frac{1}{306}\)=\(\frac{73}{5695}\)+\(\frac{1}{306}\)=\(\frac{97}{6030}\)

Phân số 3/0 ko tồn tại, đề sai 

KQ:\(\frac{1}{63}\)
 

149/63

bằng    149/63

\(\frac{191}{210}+\frac{161}{240}+\frac{129}{272}+\frac{96}{306}=\frac{1691}{714}\)

1691/714

Đáp án : 149/63