Tính B = \(\frac{1010+1007+\frac{2017}{113}+\frac{2017}{117}-\frac{1010}{119}-\frac{1007}{119}}{1010+1008+\frac{2018}{113}+\frac{2018}{117}-\frac{1010}{119}-\frac{1008}{119}}\)
Những câu hỏi liên quan
1) Cho n thuộc N; Chứng tỏ: A= \(\frac{14n+3}{21n+5}\) là phân số tối giản
2) Tính : B = \(\frac{1010+1007+\frac{2017}{113}+\frac{2017}{117}-\frac{1010}{119}-\frac{1007}{119}}{1010+1008+\frac{2018}{113}+\frac{2018}{117}-\frac{1010}{119}-\frac{1008}{110}}\)
A=\(\frac{1003+1007+\frac{2010}{113}+\frac{2010}{117}-\frac{1003}{119}-\frac{1007}{119}}{1003+1008+\frac{2011}{113}+\frac{2011}{117}-\frac{1003}{119}-\frac{1008}{119}}\)
30 tháng 4 2019 lúc 8:13
Tính biểu thức :
\(A=\frac{1003+1007+\frac{2010}{113}+\frac{2010}{117}-\frac{100}{119}-\frac{1007}{119}}{1003+1008+\frac{2011}{113}+\frac{2011}{117}-\frac{1003}{119}-\frac{1008}{119}}\)
Giúp nha!!!
Đề ???
\(A=\frac{1003+1007+\frac{2010}{113}+\frac{2010}{117}-\frac{1003}{119}-\frac{1007}{119}}{1003+1008+\frac{2011}{113}+\frac{2011}{117}-\frac{1003}{119}-\frac{1008}{119}}\)
\(=\frac{2010+\frac{2010}{113}+\frac{2010}{117}-\frac{2010}{119}}{2011+\frac{2011}{113}+\frac{2011}{117}-\frac{2011}{119}}\)
\(=\frac{2010.\left(1+\frac{1}{113}+\frac{1}{117}-\frac{1}{119}\right)}{2011.\left(1+\frac{1}{113}+\frac{1}{117}-\frac{1}{119}\right)}\)
\(=\frac{2010}{2011}\)
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\(A=\frac{1003+1007+\frac{2010}{113}+\frac{2010}{117}-\frac{100}{119}-\frac{1007}{119}}{1003+1008+\frac{2011}{113}+\frac{2011}{117}-\frac{1003}{119}-\frac{1008}{119}}\)
\(A=\frac{1003+1008+\frac{2011}{113}+\frac{2011}{117}-\frac{1003}{119}-\frac{1008}{119}}{1003+1008+\frac{2011}{113}+\frac{2011}{117}-\frac{1003}{119}-\frac{1008}{119}}\)+ \(\frac{1+\frac{1}{113}+\frac{1}{117}-\frac{903}{119}-\frac{1}{119}}{1003+1008+\frac{2011}{113}+\frac{2011}{117}-\frac{1003}{119}-\frac{1008}{119}}\)
\(A=1+\frac{1+\frac{1}{113}+\frac{1}{117}-\frac{904}{119}}{2011+\frac{2011}{113}+\frac{2011}{117}-\frac{2011}{119}}\)
\(A=\frac{1+\frac{1}{113}+\frac{1}{117}-\frac{1}{119}-\frac{90.}{119}}{2011+2011.\left(\frac{1}{113}+\frac{1}{117}-\frac{1}{119}\right)}\)
\(A=\frac{\frac{90}{119}}{2010+2011}\)
\(A=\frac{\frac{90}{119}}{4021}\)
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cho mình hỏi làm thế nào để k cho người khác vậy?????
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\(A=1003+1007+\frac{2010}{113}+\frac{2010}{117}-\frac{1003}{119}-\frac{1007}{119}\)
_________________________________________________________________
\(1003+1008+\frac{2011}{113}+\frac{2011}{117}-\frac{1003}{119}-\frac{1008}{119}\)
Tính:Bài 1) A frac{5}{12.17}+ frac{35}{17.18}+ frac{39}{18.21}+ frac{30}{21.72}Bài 2) frac{1003+1007+frac{2010}{113}+frac{2010}{117}-frac{1003}{119}-frac{1007}{119}}{1003+1008+frac{2011}{113}+frac{2011}{117}-frac{1003}{119}-frac{1008}{119}} Bài 3) M frac{20}{112}+ frac{20}{280}+ frac{20}{520}+ frac{20}{832}Bài 4) A frac{frac{15}{6.16}+frac{15}{16.26}+frac{15}{26.36}}{frac{33}{6.16}-frac{33}{16.26}+frac{33}{26.36}}Ai nhanh nhất, được nhiều tick đúng nhất và xong tr...
Đọc tiếp
Tính:
Bài 1) A = \(\frac{5}{12.17}\)+ \(\frac{35}{17.18}\)+ \(\frac{39}{18.21}\)+ \(\frac{30}{21.72}\)
Bài 2) \(\frac{1003+1007+\frac{2010}{113}+\frac{2010}{117}-\frac{1003}{119}-\frac{1007}{119}}{1003+1008+\frac{2011}{113}+\frac{2011}{117}-\frac{1003}{119}-\frac{1008}{119}}\)
Bài 3) M = \(\frac{20}{112}\)+ \(\frac{20}{280}\)+ \(\frac{20}{520}\)+ \(\frac{20}{832}\)
Bài 4) A = \(\frac{\frac{15}{6.16}+\frac{15}{16.26}+\frac{15}{26.36}}{\frac{33}{6.16}-\frac{33}{16.26}+\frac{33}{26.36}}\)
Ai nhanh nhất, được nhiều tick đúng nhất và xong trước ngày 2 tháng 5 thì mk sẽ chọn câu trả lời đó!
A=1003+1007+2010/113+2010/117-1003/119-1007/119
1003+1008+2011/113+2011/117-1003/119-1008/119
A=
1003+1007+2010/113+2010/117-1003/119-1007/119
1003+1008+2011/113+2011/117-1003/119-1008/119
Tính A =(1003+1007+2010/113+2010/117-1003/119-1007/119)/(1003+1008+2011/113+2011/117+1003/119+1008/119)
Tính hộ mình với, nhanh lên nhé
ai nhanh nhất mình sẽ tick
Tính
\(A=\dfrac{1003+1007+\dfrac{2010}{113}+\dfrac{2010}{117}-\dfrac{1003}{119}-\dfrac{1007}{119}}{1003+1008+\dfrac{2011}{113}+\dfrac{2011}{117}-\dfrac{1003}{119}-\dfrac{1008}{119}}\)
\(tuA=1003+1007+\dfrac{2010}{113}+\dfrac{2010}{117}-\dfrac{2010}{119}=2010\left(1+\dfrac{1}{113}+\dfrac{1}{117}-\dfrac{1}{119}\right)\)\(mauA=1003+1008+\dfrac{2011}{113}+\dfrac{2011}{117}-\dfrac{2011}{119}=2011\left(1+\dfrac{1}{113}+\dfrac{1}{117}-\dfrac{1}{119}\right)\)có \(\left(1+\dfrac{1}{113}+\dfrac{1}{117}-\dfrac{1}{119}\right)\ne0=>A=\dfrac{2010}{2011}\)
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